, to create a line chart, with the years (Y10_11, etc.) in
the X-axis and the Categorie in the Y-axis. The lines should be created with
the numbers for each categorie. So in each plot there should be 6 lines in
dependence of the value for each year.
Thank you.
Best regards.
Mat
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3 4700
4 3500
5 3800
Thanks.
Best regards. Mat
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hello togehter,
i have a little problem, i have frames like this two:
Cat Hours
A101 15
B103 10
Cat Hours
A103 16
B106 11
I need to convert this 2 data.frames into the following equal structure:
Cat Hours
A101
B
this?
The solution look like this one:
1
A Marius Muller -
B Rockwood
C Microlog Services
D Firefox Services
Thank you.
Best regards. Mat.
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works perfect, thank you :-)
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Hello togehter,
i have a litte problem. I have an output data.frame which look like this
one:
ID
1 10
2 11
3 12
Now I have another data.frame with more than one line for each ID:
IDGroupValue
1 10110
2 10220
3 103
this one, that i can convert into a data.frame
ID 1 2 3 4 5
110 10 20 30 40 50
211 0 0 60 70 0
312 0 0 0 80 0
Thank you
Mat
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thanks for the help up to here.
A little problem remains.
I have different ABNR, if i try it with another ABNR, the Column extend
for each ABNR, it should start with FIRST again.
dat1 - read.table(text=FS_ID ABNR
932733688812
11391 33688812
11392 33688812
11388 33688812
11390 33688812
THREEMAX
1 2 57 7
2 6 NA NA 6
3 5 7NA 7
4 1 NA NA 1
how can i do this?
thank you. Mat
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date value should stand under FIRST, the newer date under
SECOND.
Maybe anyone can help me, how i can do this.
Best regards. Mat
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Hello together,
i have a little problem, to create a new column, in a data.frame.
I know i can calculate one column with as a example 2 like this:
ORDER$WEIGHT - ORDER$VALUE * 2
But how can i create the ORDER$WEIGHT with different numbers, like this one.
I have a data.frame like this one:
thanks a lot, works perfectly
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ee
i tried it like this one:
out1-out[(out$No==no.ind),]
in no.ind i have the 2 numbers: c(2,3)
but this doesn't work.
Maybe anyone can help me.
Thank you.
Mat
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thanks together,
out1 - out[(out$No %in% no.ind),]
works perfectly :-)
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-10-0415
32013-10-0110
the result should be this one:
IDName First SecondThird
1 Andy10 15
2 John 7 10 15
3 Amy 10
maybe you can help me, to do this?
Thank you.
Mat
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with plotbase-t(plotbase).
Maybe you can help me.
Thanks Mat
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regards. Mat
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Thanks first.
that doesn't look bad. But if have a equal ID in dat2, the days are no
longer correct.
the correct data.frame has to look like this one:
ID Name Management Training
1 1 Jack 13
2 2 John 10
3 3 Jill 04
not this one:
ID
thanks. Works perfectly
you made my day :-)
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. So the value of one column
has to have a own color in dependence of the Cat.
Perhabs anyone have an idea?
Thanks.
Mat
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if i can sort my list as follows, i can create the bar chart.
But how can i sort my list from:
[,1] [,2] [,3]
[,4]
abnr2 11425 11425 11555 11888
TIME 21 1
49396 1140
B49396 15013
perhabs anyone can help me.
Thank you
Mat
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Value
A 33 Evo
B 1 Mer 80
C 1 Pold
thanks.
Mat
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thank you, this code works:
library(plyr)
join(dat1,dat2,by=c(cu.nr.,name),type=right)
but my dat2 frame has a lot of columns, which i don't want to match.
How can i say, that only the column value should be match to dat1 ?
Thank you.
Mat
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i found a way :-)
data-merge(data,project,by.x=PJ_ID,by.y=PROJ_ID,all.x=TRUE)
perhaps this can help someone
Mat
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productive
Thanks.
Mat
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=.)
write.xls( Orders,pfad,colNames = TRUE,sheet = 1,from = 1,rowNames = FALSE )
if(dim(CO.PHB)[1]0){
write.table( CO.PHB,pfad,row.names=FALSE,sep= | )
}}
how should my code look like, if i want only an Export, when there is data
in the data.frame?
Thanks Mat
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can i do this.
Thanks.
Mat
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111 final2013-01-12
is there any way to filter my data.frame to the latest data, perhabs max?
Thanks.
Mat
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: Mercedes_02352
Audi_03555
and now i want to filter this data.frame to
235
355
can you help me?
Thanks.
Mat
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thx, that worked perfekt, but is there any way to convert my Number 1 row
# 123
up as column description?
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.
1 2 3
1st round 1:22:30:0
2nd round 2:2 1:01:1
can you help me?
Thanks.
Mat
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2
A Albert1800
B Jack2000
C Mike 2200
How can i eliminate this double entries?
Thanks.
Mat?
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thx, works perfectly :-)
Mat
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want a new data.frame, who show me only the newest entries according
to the No.
The solution look like this one:
No. Datelast change
1 1 2012-11-05 final
2 2 2013-01-17 final
can anyone help me?
thanks.
Mat
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Hello together,
i want to round some numbers in my data.frame.
How can i round a number to values like 0.5; 1.0; 1.5; 2.0; etc.
It should look like this one
before
2.2 ; 2.3; 2.26; 1.11
after
2.0; 2.5; 2.5; 1.0
thanks.
Mat
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thx, works perfektly :-)
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Hallo together,
i have a data.frame like this one.
A
13
2-2
31
and now i want to convert the negative number to 0.
A
13
20
31
How can i do this?
Thanks.
Mat
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works perfectly. Thank you :-)
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1
How can i do this?
Thank you.
Mat
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Thank you all, a few ideas worked perfectly for me.
I take with(dat1,aggregate(B,by=list(A=A),length)) for my task.
Have a nice day.
Mat
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is generated from the data above and is ok.
The Excel sheet was generated every day. And the numbers can change from day
to day.
I know how to color the whole row, but i don't know how to color the number
Difference -- 1,15 according to her value, like: if1,2 - RED, if 1,2
- GREEN
Thanks.
Mat
i tried it this way. With this Code the Row Difference gets complete green.
But i want the color change to red according to a different value.
highlight_other-out.ex1[(out.ex1$AUFTR_NAME==Difference),]$LFD2
zellen_other-paste(paste(A,highlight_other,sep=),paste(S,highlight_other,sep=),sep=:)
#
how to colour a complete row, like this task:
U3R - sh$Range(zellen_blue)
U3RF - U3R$Font()
U3RF[[Bold]] - TRUE
U3RF[[Size]] - 10
U3RF[[Color]] --10526881
but how can i color numbers accordung to her value?
Thanks.
Mat
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i tried it this way, but this won't help.
O3R - sh$PT_IST(zellen_other)
O3RF - O3R$Font()
O3RF[[Bold]] - TRUE
O3RF[[Size]] - 10
O3RF[[Color]] -5287936
perhabs you can help me, how i can differenz between the values of more and
less than 1,25?
Thanks.
Mat
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help.
Mat
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, with the Numbers in my vector.
this one doens't work:
data_export_final-data_export[(data_export$KD_NR==Top10),]
Thank you.
Mat
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gsub() works perfectly, thank you very much.
Mat
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get this result under my column for the Excel Export?
Now my Excel Export looks like this one.
PT_PROG
23
100
7
and now i want under this digets the sum of this column (130)?
Thanks for your help.
Mat
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Ok, I can replicate your problem, with following code:
dat - 1:10
barplot(dat, beside=TRUE,ylim=c(0,100));
par()$usr;
par(new=T);
plot(dat, ylim=c(0,100), type=l);
par()$usr;
So it looks like even if you specify yourself ylim, the resulting
effective ylim (usr[3:4] ) will be
Barry, thanks a lot for checking for this!! Find below answers.
Le 13. 04. 11 18:26, Barry Rowlingson a écrit :
2011/4/13 Matthieu Stiglermatthieu.stig...@gmail.com:
Jim
Thanks for your feedback! The problem is that the people those responsible
for layout are us... We are doing the book in
Hi
Well this is the output of str(dep) on a small example:
str(dep)
chr [1:8] ### ...
Browse[1] dep
[1] ###
[2] ### chunk number 1:
[3] ###
[4] #line
indeed this makes the trick! quite strange... is this a known bug/issue?
thanks!
Matthieu
Le 24. 01. 11 19:48, William Dunlap a écrit :
Put a space after the # in the line
#line 516
to avoid the problem. A similar problem also
appears in parse().
parse(text=#line 102\nlog(pi)\n)
Le 24. 01. 11 20:43, Duncan Murdoch a écrit :
On 11-01-24 12:07 PM, Matthieu Stigler wrote:
hi
I am seeing a strange behavior I can't understand... doing:
source(/tmp/RFile.r,echo=TRUE)
Error in rep.int(c(prompt.echo, continue.echo), c(leading,
length(dep) - :
invalid 'times' value
Ajay
Please avoid cross-posting on two lists. Continue this thread only on
thes-ig-debian list.
You can't update packages from within R? Did you try to start R with
sudo permissions?:
sudo R
Hope this helps
Mat
Le 22. 01. 11 07:50, Ajay Ohri a écrit :
Dear List
I use synaptic
a écrit :
Hi Mat,
You might be able to use the matrix method to get what you want.
head.matrix(EuStockMarkets)
-Ista
On Sat, Sep 4, 2010 at 1:15 PM, matmatthieu.stig...@gmail.com wrote:
Hi
I have a few problems with tail/head when applied to multiple time series.
I'm not sure as whether I
Hi
I have a few problems with tail/head when applied to multiple time
series. I'm not sure as whether I did not understand the function or
whether it correspond to an unexpected behavior.
When head(a,n) is applied on data.frame or matrix, it returns a
data-frame or matrix with first n obs
array or vector by himself, then the r tools use
the array or vector to calculate? I am very looking forward to your reply
thanks very much
sincerely
mat chueng
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https
Raghu
Those packages are still not on CRAN. You can download the current
version from R-forge:
*|install.packages(blotter, repos=http://R-Forge.R-project.org;)
Mat
|*
Le 10. 07. 10 12:00, r-help-requ...@r-project.org a écrit :
Message: 137
Date: Sat, 10 Jul 2010 08:32:38 +0100
From
) which looked quite well.
At least this seemed to work out all right on my Windows XP PC.
Hope this helps,
-Mat
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
On Behalf Of Mike Prager
Sent: Thursday, June 05, 2008 9:38 AM
To: [EMAIL PROTECTED]
Subject: Re: [R] Lattice
is the best way to determine the two best teams to play
for the championship - a far from perfect scenario. Yet another debate
of the use of Super Crunching if I may borrow from Ian Ayres. Open to
any ideas/opinions.
Cheers,
-Mat
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL
.
The formal job announcement is available at www.usajobs.gov - enter
FDA-09-07-109 in the search box. This announcement contains details
about the position, qualifications, and information about applying. If
you have any other questions, I would be happy to assist in anyway.
Thanks,
-Mat
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