to begin with, which doesn't seem to be the case.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Szumiloski, John
Sent: Wednesday, February 09, 2011 11:30 AM
To: r-help@r-project.org
Cc: Rick DeShon
Subject: Re: [R
Thanks in advance,
Rick DeShon
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible
) # Sample the data
Thanks in advance,
Rick DeShon
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained
,
parameters=c(min,dplt,dif,p))
Thanks for your help!
Rick DeShon
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Hi All.
Imagine you have a large block diagonal matrix. I'd like to replace
the zeros in this matrix with small random (runif) numbers. Any ideas
for a simple and efficient way to do this?
Best regards,
Rick DeShon
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of iterations to convergence: 11
Any idea why having a zero for the first value of X causes this problem?
Thanks in advance,
Rick DeShon
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...
$ RT : int NA 1309 544 654 NA 441 882 1097 898 ...
$ block: int 1 1 1 1 1 1 1 1 1 1 ...
- attr(*, formula)=Class 'formula' length 3 RT ~ trial | id
.. ..- attr(*, .Environment)=R_GlobalEnv
- attr(*, FUN)=function (x)
- attr(*, order.groups)= logi TRUE
Thanks!
Rick DeShon
Hi All.
I would like to compute a separate covariance matrix for a set of variables
for each of the levels of a factor and then compute the average covariance
matrix over the factor levels. I can loop through this computation but I
need to perform the calculation for a large number of levels and
matrix over
the list members in lcov?
Thanks in advance,
Rick DeShon
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