Hi,
If x is a data frame, then x$getmean will try to get the vector named
getmean in x. You put () after x$getmean. I think r is confused about
it. It appears that you want to call a function named getmean().
--
View this message in context:
On 14.09.2012 22:16, Steve Lianoglou wrote:
Hi,
On Fri, Sep 14, 2012 at 2:33 PM, agrins agri...@d.umn.edu wrote:
HI all-
I have used this .fun in S+ without a problem however, in R when I run this
code to generate multiple graphs:
trendplot-function(datafr,dataf2, abbrev=, titlestr=,
2) Make the vector a list. I don't know if there are side-Effects to
this, but perhaps it's just the anxiety of a Java-Programmer who isn't
used to the somewhat easy-going way R deals with classes:
class(dataf2) - list
Indeed, there are _many_ side effects to this and you really should
HI all-
I have used this .fun in S+ without a problem however, in R when I run this
code to generate multiple graphs:
trendplot-function(datafr,dataf2, abbrev=, titlestr=,
devname=s,filen=,styr=1990,endyr=2012) {
if (!is.null(dev.list())) {dev.off()}
dataf-datafr[datafr$abbrev==abbrev,]
Hi,
On Fri, Sep 14, 2012 at 2:33 PM, agrins agri...@d.umn.edu wrote:
HI all-
I have used this .fun in S+ without a problem however, in R when I run this
code to generate multiple graphs:
trendplot-function(datafr,dataf2, abbrev=, titlestr=,
devname=s,filen=,styr=1990,endyr=2012) {
if
I have got the following statement:
* overview.domains$sample.var - aggregate(migr$amigo.migr,
by=list(siruta=amigo$siruta), var)[,-1]/overview.domains$n.i.*
*Error in migr$amigo.migr : $ operator is invalid for atomic vectors*
What should i do to solve this error?
Thank you.
Kind regards,
Le jeudi 19 avril 2012 à 09:34 +0300, Ana-Maria Dobre a écrit :
I have got the following statement:
* overview.domains$sample.var - aggregate(migr$amigo.migr,
by=list(siruta=amigo$siruta), var)[,-1]/overview.domains$n.i.*
*Error in migr$amigo.migr : $ operator is invalid for atomic vectors*
Amy
It would have been helpful if you had sent your R code of how you
constructed the sab object.
If you have a data.frame, the subset command you are having trouble with
should work fine. See below.
# Working Example
sab = data.frame(group=c('Group A', 'Group A', 'Group C', 'Group B', 'Group
Dear all,
Starting from a recent version of R, the $ became unusable on atomic vectors,
e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course do
x['a']
- but that requires more typing (5 characters rather than 2).
On Thu, 6 Dec 2007, Søren Højsgaard wrote:
Dear all,
Starting from a recent version of R,
From R 2.5.0, not so recent.
the $ became unusable on atomic vectors, e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course
On 06-Dec-07 12:04:56, Søren Højsgaard wrote:
Dear all,
Starting from a recent version of R, the $ became unusable
on atomic vectors, e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course do
x['a']
- but that
On 12/6/2007 7:04 AM, Søren Højsgaard wrote:
Dear all,
Starting from a recent version of R, the $ became unusable on atomic
vectors, e.g.
x - c(a=1,b=2)
x$a
NULL
Warning message:
In x$a : $ operator is invalid for atomic vectors, returning NULL
I can of course do
x['a']
- but that
12 matches
Mail list logo
