Is this what you want:
my.df - data.frame(a = c(1:5, 1:10, 1:20), b = runif(35))
split(my.df, c(0, cumsum(diff(my.df$a) 0)))
$`0`
a b
1 1 0.2655087
2 2 0.3721239
3 3 0.5728534
4 4 0.9082078
5 5 0.2016819
$`1`
a b
6 1 0.89838968
7 2 0.94467527
8 3 0.66079779
9 4 0.62911404
10 5 0.06178627
11 6 0.20597457
12 7 0.17655675
13 8 0.68702285
14 9 0.38410372
15 10 0.76984142
$`2`
a b
16 1 0.49769924
17 2 0.71761851
18 3 0.99190609
19 4 0.38003518
20 5 0.77744522
21 6 0.93470523
22 7 0.21214252
23 8 0.65167377
24 9 0.1210
25 10 0.26722067
26 11 0.38611409
27 12 0.01339033
28 13 0.38238796
29 14 0.86969085
30 15 0.34034900
31 16 0.48208012
32 17 0.59956583
33 18 0.49354131
34 19 0.18621760
35 20 0.82737332
On Tue, Sep 9, 2008 at 5:38 AM, David Carslaw
[EMAIL PROTECTED] wrote:
Hi all,
Given a data frame:
my.df - data.frame(a = c(1:5, 1:10, 1:20), b = runif(35))
I want to split it by a such that I end up with a list containing 3
components i.e. the first containing a = 1 to 5, the second a = 1 to 10 etc.
In other words, sets of sequences of a.
I can't seem to find the right form using the split function - can you help?
Much appreciated.
David
-
Institute for Transport Studies
University of Leeds
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