Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst -
list(rep(list(1:3),3), rep(list(4:6),3)) lst[[1]][[1]][[1]][1] 1 2
3[[1]][[2]][1] 1 2 3[[1]][[3]][1] 1 2 3[[2]][[2]][[1]][1] 4 5 6[[2]][[2]][1]
4 5 6[[2]][[3]][1] 4
lapply(lst, function(x) return(x[[2]]))
On Fri, Jan 11, 2013 at 6:40 AM, Bjoern Helm bjoern.h...@tu-dresden.de wrote:
Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst -
list(rep(list(1:3),3), rep(list(4:6),3))
On 01/12/2013 12:40 AM, Bjoern Helm wrote:
Dear R users,I have a list of equally structured lists, how can I access e.g.
all 2nd compontents in those sub-lists?An example:lst -
list(rep(list(1:3),3), rep(list(4:6),3)) lst[[1]][[1]][[1]][1] 1 2
3[[1]][[2]][1] 1 2 3[[1]][[3]][1] 1 2
Hi,
thank you. I just came up with
lapply(c(1:length(lst)), function(x) return(lst[[x]][[2]]))
but your solution is much more elegant. Although I don't completely understand:
if lst is the argument of function x[[2]] this should be iterpreted as
lst[[2]]. Where am I wrong?
Björn
Am
On Jan 11, 2013, at 3:26 PM, Bjoern Helm wrote:
Hi,
thank you. I just came up with
lapply(c(1:length(lst)), function(x) return(lst[[x]][[2]]))
but your solution is much more elegant. Although I don't completely
understand: if lst is the argument of function x[[2]] this should be
5 matches
Mail list logo