Dear Everybody,
Enclosed are the tiny beginning of a program and its output.
As a pity, if I load the image load(kanal.RData) the elements of
de.dd are non numerical; de.dd[2]+de.dd[3] returns Fehler in
de.dd[2] + de.dd[3] : nicht-numerisches Argument für binären Operator.
How can I keep the
You program contains:
de.dd-c(Dresden,51,2,13,44)
and since you are mixing characters with numerics and putting them
into a single vector, the data is coerced to a common data type, which
in this case is numeric. What are you trying to do? Do you want to
use a list?
de.dd
[1] Dresden 51
Meant to say coerced to character.
See ?c
On Dec 9, 2007 6:14 AM, Mag. Ferri Leberl [EMAIL PROTECTED] wrote:
Dear Everybody,
Enclosed are the tiny beginning of a program and its output.
As a pity, if I load the image load(kanal.RData) the elements of
de.dd are non numerical;
Thank you, this seems promissing. How can I address then a certain
element e.g. to add the second and the third component?
Faithfully,
Mag. Ferri Leberl
Am Sonntag, den 09.12.2007, 07:11 -0800 schrieb jim holtman:
You program contains:
de.dd-c(Dresden,51,2,13,44)
and since you are mixing
Several different ways. You can look in the Intro to R to learn more:
my.list - list(a=matrix(1:9,3), b=1:4, c=this is a string, d=list(1,2,3))
my.list
$a
[,1] [,2] [,3]
[1,]147
[2,]258
[3,]369
$b
[1] 1 2 3 4
$c
[1] this is a string
$d
$d[[1]]
[1]
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