It is really the same thing. One of many possibilities:
theFrame - data.frame(theValues=runif(150,-10,10))
exact - diag(15)[1+ (rank(theFrame$theValues)-1)%/%10,]
not.so.exact - diag(15)[1+
(rank(theFrame$theValues+runif(150,0,3))-1)%/%10,]
If what you actually wanted was one factor with
On Sun, 28 Mar 2010, Economics Guy wrote:
It is really the same thing. One of many possibilities:
theFrame - data.frame(theValues=runif(150,-10,10))
exact - diag(15)[1+ (rank(theFrame$theValues)-1)%/%10,]
not.so.exact - diag(15)[1+
(rank(theFrame$theValues+runif(150,0,3))-1)%/%10,]
If what
I am revising a program that I wrote when I was very new at R
(2007ish), and while I have been able to write very nice and fast code
for almost all of it, there is one issue that I cannot seem to do it
in less than 40 ugly and computationally expensive lines.
I have a data frame that contains one
On Sat, 27 Mar 2010, Economics Guy wrote:
I am revising a program that I wrote when I was very new at R
(2007ish), and while I have been able to write very nice and fast code
for almost all of it, there is one issue that I cannot seem to do it
in less than 40 ugly and computationally expensive
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