[R] Convert components of a list to separate columns in a data frame or matrix XXXX

Hello everyone, What is the most efficient simpliest way to convert all components of a list to separate columns in a matrix? Is there an easy way to programmatically pad the length of the resulting shorter character vectors so that they can be easily combined into a data frame? I have the

Re: [R] Convert components of a list to separate columns in a data frame or matrix XXXX

Is this what you are after: more-c('R is a free software environment for statistical computing', + 'It compiles and runs on a wide variety of UNIX platforms') result-strsplit(more,' ') result [[1]] [1] R is a freesoftware environment for [8]

Re: [R] Convert components of a list to separate columns in a data frame or matrix XXXX

On Jan 8, 2012, at 2:28 PM, jim holtman wrote: Is this what you are after: The code below is essentially what I would have imagined to be a method of programming cbind.data.frame.fill. It's worth noting that either reshape2 or plyr (I don't remember which) offer an rbind version:

Re: [R] Convert components of a list to separate columns in a data frame or matrix XXXX

Hello, I believe this solves your problem fun - function(x){ f - function(x, n){ if(length(x) n) x - c(x, rep(NA, n-length(x))) return(x) } lapply(x, f, max(unlist(lapply(x, length } fun(result) # the 'result' list above