Dear Bert
Thank you for your suggestion. I have tried it but it did not work.
For record, I am reposting the post with the plain text.
library(tidyverse)
library(plyr)
library(survey)
dat <- structure(list(
r3a_1 = structure(c(3L, 2L, 3L, 3L, 3L, 3L, 3L,3L, 3L, 3L, 3L, 2L,
2L, 3L, 3L, 3L,
1. This is a plain text list. Set your email to post in plain text, not
html, which often gets mangled (see below).
2. I did not run your example, but try:
my_funca(mk =names(dat)[1:9], y = dat$seg_2)
## seg_2 is a component of dat and is not in the environment of the call. I
did not see any
Dear R-Help
I am working with complex survey data using the survey package.
I would like to create a function for the generate multi crosstable. The
problem is that I am getting error with the following message:
"Error in eval(predvars, data, env) : object 'y' not found"
Here is the example:
Hello everyone,
Does anybody know whether it's possible to calculate extract major axis
regression residuals on the results of a major axis Model II regression done by
lmodel2?
Many thanks,
Orca
Example :
> data1 data1
SSTo SSTp
1 17.21 20.36
2 19.61 20.19
3 18.60
...
and here is a maybe slightly neater approach using ?mapply (again with
the method column changed to character():
f <- function(meth,i,fr) do.call(meth,list((fr[i,])))
mapply(FUN=f,meth=input.df[,4],seq_len(nrow(input.df)),
MoreArgs = list(fr = input.df[,1:3]) )
Cheers,
Bert
Bert
OOPS! I forgot to tell you that I first changed the "method" column,
which is a factor, to character, with
input.df$method <- as.character(input.df$method)
Then things will work properly.
-- Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking
1. return() is not needed in R functions (it's harmless, however). You
might wish to go through an R function tutorial (many good ones are on
the web) to learn about what slick things you can do with functions in
R.
2. The following is just a brute force loop, so more elegant
approaches are
Hi all,
the function jtest allows to compare two non-nested models. The comparison
is made such that the fitted values of one model are included in the
regressor matrix of the other model. It then looks whether there is any
predictive power of these fitted values.
Unfortunately, the input has to
Hi,
I am writing regarding to my problem about using plot function. I am using R
x64 3.1.1 (installed on Windows 7 SP1 (laptop Sony VGN-SR) ), and when I use
type this code:
x - c(-30,30)
y - c(-5,5)
plot.window(x , y)
or any other form of plot function, it doesn't show anything. I used
Hi,
I am writing regarding to my problem about using plot function. I am
using R x64 3.1.1 (installed on Windows 7 SP1 (laptop Sony VGN-SR) ), and
when I use type this code:
x - c(-30,30)
y - c(-5,5)
plot.window(x , y)
or any other form of plot function, it doesn't show anything. I used
plot.window() is an internal support function, not a user function.
use
plot()
x - c(-30,30)
y - c(-5,5)
plot(x , y)
On Fri, Jan 16, 2015 at 4:18 PM, Nafise Mehdipour
nfs.mehdip...@gmail.com wrote:
Hi,
I am writing regarding to my problem about using plot function. I am
using R x64 3.1.1
On 16/01/2015 1:18 PM, Nafiseh Mehdipour wrote:
Hi,
I am writing regarding to my problem about using plot function. I am using
R x64 3.1.1 (installed on Windows 7 SP1 (laptop Sony VGN-SR) ), and when I
use type this code:
x - c(-30,30)
y - c(-5,5)
plot.window(x , y)
or any other
annie Zhang annie.zhang2...@gmail.com writes:
## the predicted scores from the model
(pred - predict(data.cpls,n.comp=1:2,newdata=x.new,type=score))
## the predicted scores using x%*%projection
cbind(x.new.centered%*%data.cpls$projection[,1],x.new.centered%*%data.cpls$projection[,2])
Can
Ok, yes, I can match them now. Thank you very much!
On Tue, Jun 24, 2014 at 3:58 AM, Bjørn-Helge Mevik b.h.me...@usit.uio.no
wrote:
annie Zhang annie.zhang2...@gmail.com writes:
## the predicted scores from the model
(pred - predict(data.cpls,n.comp=1:2,newdata=x.new,type=score))
##
Hi All,
I want to produce scores from X using $projection. When I predict, I cannot
match the predicted scores and scores using x%*%projection.
Below is a very simple example,
set.seed(seed=1)
y - c(1, 1, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 1, 1, 0, 1, 1, 0, 0, 0)
x - matrix(runif(200),nrow=20)
data
Andras,
What do you want your code to do? Give us a little explanation with your
code.
When I try to run your code, I get
Error: could not find function genoud.
Either supply the code for the functions included in your code, or tell us
what packages we need to run it.
Jean
Andras
Dear All,
I could use a bit of help here, this function is hard to figure out (for me at
least) I have the following so far:
PKindex-data.frame(Subject=c(1),time=c(1,2,3,4,6,10,12),conc=c(32,28,25,22,18,14,11))
Dose-200
Tinf -0.5
defun- function(time, y, parms) {
dCpdt - -parms[kel] *
, but I have not been able to
find a solution.
Thank you, D
--
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Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
help would be greatly appreciated. I have very little experience in
r,
so I apologize if this is a trivial question, but I have not been able
to
find a solution.
Thank you, D
--
View this message in context:
http://r.789695.n4.nabble.com/Help-writing-function-in-R-tp4629824.html
Sent from the R help
Hello everybody,
I noticed a performance problem when using the source-function in R.
When I try to source an r script that is located in the same directory
as the script I execute via command line ('R -f file.r' contents
'source(someOtherScript.r)') it's very fast. But if I put
On 19.01.2012 14:25, Jos van Nijnatten wrote:
Hello everybody,
I noticed a performance problem when using the source-function in R.
When I try to source an r script that is located in the same directory
as the script I execute via command line ('R -f file.r' contents
On 12-01-19 8:25 AM, Jos van Nijnatten wrote:
Hello everybody,
I noticed a performance problem when using the source-function in R.
When I try to source an r script that is located in the same directory
as the script I execute via command line ('R -f file.r' contents
'source(someOtherScript.r)')
Hello Uwe, Duncan and the rest of the community,
It indeed seemed to be a file system problem and I'm lucky to figure
that out before it crashed. New computer's great and everything is
working fine again.
Sorry for wasting your time ;-)
On Thursday, January 19, 2012 15:16, Duncan Murdoch
Hello again.
Following a great idea from Jim and Dennis, I began to use the function
ave() in my big data.
I proved to use this command in my data with FUN=max(x,na.rm=T), and I
received a Warning that translated looks like
Warning in max (x, na.rm = T):
no arguments to max; returning -Inf
Is
On Apr 28, 2011, at 12:30 PM, петрович wrote:
Hello again.
Following a great idea from Jim and Dennis, I began to use the
function
ave() in my big data.
I proved to use this command in my data with FUN=max(x,na.rm=T),
Try instead:
look at the 3rd example of help(ave)
and I
received
: Re: [R] help with function
To: Iain Gallagher iaingallag...@btopenworld.com
Cc: r-help@r-project.org
Date: Saturday, 18 December, 2010, 0:13
On Fri, 17 Dec 2010, Iain Gallagher
wrote:
Hello List
I'm moving this over from the bioC list as, although
the problem I'm working
Hello List
I'm moving this over from the bioC list as, although the problem I'm working on
is biological, the current bottle neck is my poor understanding of R.
I wonder if someone would help me with the following function.
cumulMetric - function(deMirPresGenes, deMirs){
#need to match
On Fri, 17 Dec 2010, Iain Gallagher wrote:
Hello List
I'm moving this over from the bioC list as, although the problem I'm working on
is biological, the current bottle neck is my poor understanding of R.
I wonder if someone would help me with the following function.
Here is how I'd take
Hi,
I want to merge 4 data frames with one column in common but I am
getting error message while using this function. Can any one help me out.
merge_all(Br,Ki,Lu,Pr,by=Genes)
Error: could not find function merge_all
I have installed the package: reshape but I still get this error
--
Hi,
Did you also load the package (you'll need to load it every session
you want to use it)?
## load reshape package
library(reshape)
## now try
merge_all(Br, Ki, Lu, Pr, by=Genes)
If this does not resolve your problem, please run: sessionInfo()
at your console and report the output (it will
Hi Josh,
Thanks for your reply.
While I am loading the package, it says package plyr is
required and I tried to install plyr package but I am unable to do so
because it is giving an error message as shown below.
Please help me.
library(reshape)
Loading required
Hi Josh,
I thought of giving up and started writing code in excel using
VBA but then I saw ur message and gave a try in R. I got it, the location
from which I am calling the package plyr is not working out so called from
different CRANmirror location and then I was able load the
Hello all
I have what seems like a simple question but have not been able to find an
answer on the forum. I'm trying to define a function which involves
regression models and a large number of covariates.
I would like the function to accept any number of covariates and, ideally, I
would like to
Hello Tim,
This function will do it where the covariates are provided as separate
arguments. It would be easy to modify this to handle a list too.
function(outcome, ...) {
arg.names - as.character(match.call())[-1]
nargs - length(arg.names)
f - as.formula(paste(arg.names[1], ~,
Dear Whom it may concern,
I need help to figure the macro function in R: I need to plot the
different data sets by a plotxyf function, I want the title to be different
for different data set.
# get the data set
final.xyf- xyf(data=as.matrix(my.final),
Y=classvec2classmat(final$outcome),
On Tue, 2010-04-06 at 09:33 -0700, Changbin Du wrote:
#plot function
plotxyf-function (data) {
plot(data, type=mapping, labels=final$target, col=final$outcome+1,,
main=Supervised: Mapping plot for data)
Change this to: main=paste(Supervised: Mapping plot for, data)
A small correction.
On Tue, Apr 6, 2010 at 9:43 AM, Stuart Luppescu s...@ccsr.uchicago.eduwrote:
On Tue, 2010-04-06 at 09:33 -0700, Changbin Du wrote:
#plot function
plotxyf-function (data) {
plot(data, type=mapping, labels=final$target, col=final$outcome+1,,
main=Supervised: Mapping
On Tue, 6 Apr 2010, Stuart Luppescu wrote:
On Tue, 2010-04-06 at 09:33 -0700, Changbin Du wrote:
#plot function
plotxyf-function (data) {
plot(data, type=mapping, labels=final$target, col=final$outcome+1,,
main=Supervised: Mapping plot for data)
Change this to: main=paste(Supervised:
Thank you,man. the problem solved.
Plus. when I got the parameters of the data.
And I used the truehist(mydata) to get a histogram of the data,
How can I draw a line of the distribution of the estimated parameters in the
histogram plot?
for example:
fitdistr(na.exclude(mydata),normal)
mean
Saji Ren wrote:
Thank you,man. the problem solved.
Plus. when I got the parameters of the data.
And I used the truehist(mydata) to get a histogram of the data,
How can I draw a line of the distribution of the estimated parameters in the
histogram plot?
for example:
Please read the footer of this message. ?fitdistr says
x: A numeric vector.
and setting the class does not make it a numeric vector (it is just a
label). And fitdistr early on does
if (missing(x) || length(x) == 0L || mode(x) != numeric)
stop('x' must be a non-empty
On Sat, 2010-01-02 at 23:20 -0800, Saji Ren wrote:
Hi, R users:
I want to fit my data into a normal distribution by using the command
fitdistr in MASS.
I changed my data class from ts to numeric by
class(mydata)=numeric
but after using fitdistr, I got the result below
Hi, R users:
I want to fit my data into a normal distribution by using the command
fitdistr in MASS.
I changed my data class from ts to numeric by
class(mydata)=numeric
but after using fitdistr, I got the result below
fitdistr(mydata,normal)
meansd
NA NA
(NA) (NA)
the help
I check my data again, and find that:
1. when the class of mydata is ts, I can't compute the sd of it. R returns
'NA'.
2. when I change the class from ts into numeric, R still can't compute the
sd of the data.
Any suggestion?
--
View this message in context:
And when I used the command below:
fitdistr(mydata, normal, na.rm=TRUE)
the result is still the same.
--
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Dear All,
I need to write 'n' functions on 'm' variables. The functions should be
constructed according to the values of an (nxm) matrix of '1/0' values as
follows. For example,
if row1 is equal to ,say [1 0 ...0 0] then f1 - (1+x1)
if row 2 is equal to, say [1 1 1 0...0 1] then f2
On Fri, Mar 13, 2009 at 6:28 PM, Lars Bishop lars...@gmail.com wrote:
Dear All,
I need to write 'n' functions on 'm' variables. The functions should be
constructed according to the values of an (nxm) matrix of '1/0' values as
follows. For example,
if row1 is equal to ,say [1 0 ...0 0]
Hi everybody
I need to create a program using the function filter with this vector.
MATDINAMIC$VELOCIDADFIN[1:1000]
That´s why I want to identify when use the mean and the median because I
have problems.
I want to know if I am using correct this:
I think you can get the median with:
filter(MATDINAMIC$VELOCIDADFIN[1:1000],c(0, 1, 0))
On Mon, Jun 9, 2008 at 5:08 PM, wilquin Minaya [EMAIL PROTECTED]
wrote:
Hi everybody
I need to create a program using the function filter with this vector.
MATDINAMIC$VELOCIDADFIN[1:1000]
That´s
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