Hi all,
I would like create a new column in a data.frame (a1) to store 0, 1 data
converted from a factor as below.
a1$h2-NULL
for (i in 1:dim(a1)[1]) {
if (a1$h1[i]==H) a1$h2[i]-1 else a1$h2[i]-0
}
My question: is it possible to remove the loop from above code to achieve the
Hello,
Try:
a1$h2 - 0
a1$h2[a1$h1==H] - 1
Regards
Le 12/07/03 16:18, jin...@ga.gov.au a écrit :
Hi all,
I would like create a new column in a data.frame (a1) to store 0, 1 data
converted from a factor as below.
a1$h2-NULL
for (i in 1:dim(a1)[1]) {
if (a1$h1[i]==H) a1$h2[i]-1 else
Hi
Hi all,
I would like create a new column in a data.frame (a1) to store 0, 1 data
converted from a factor as below.
a1$h2-NULL
for (i in 1:dim(a1)[1]) {
if (a1$h1[i]==H) a1$h2[i]-1 else a1$h2[i]-0
}
My question: is it possible to remove the loop from above code to
On 07/03/2012 05:18 PM, jin...@ga.gov.au wrote:
Hi all,
I would like create a new column in a data.frame (a1) to store 0, 1 data
converted from a factor as below.
a1$h2-NULL
for (i in 1:dim(a1)[1]) {
if (a1$h1[i]==H) a1$h2[i]-1 else a1$h2[i]-0
}
My question: is it possible to
On Jul 3, 2012, at 5:08 AM, Jim Lemon wrote:
On 07/03/2012 05:18 PM, jin...@ga.gov.au wrote:
Hi all,
I would like create a new column in a data.frame (a1) to store 0, 1
data converted from a factor as below.
a1$h2-NULL
for (i in 1:dim(a1)[1]) {
if (a1$h1[i]==H) a1$h2[i]-1 else
And one more alternative:
a1$h2 - apply(a1,1, function(x) if (x[h1]==H) 1 else 0 )
--
View this message in context:
http://r.789695.n4.nabble.com/Is-it-possible-to-remove-this-loop-SEC-UNCLASSIFIED-tp4635250p4635271.html
Sent from the R help mailing list archive at Nabble.com.
Thank you all for providing various alternatives. They are all pretty fast.
Great help! Based on a test of a dataset with 800,000 rows, the time used
varies from 0.04 to 11.56 s. The champion is:
a1$h2 - 0
a1$h2[a1$h1==H] - 1
Regards,
Jin
Geoscience Australia Disclaimer: This e-mail (and
On 2012-07-03 17:23, jin...@ga.gov.au wrote:
Thank you all for providing various alternatives. They are all pretty fast.
Great help! Based on a test of a dataset with 800,000 rows, the time used
varies from 0.04 to 11.56 s. The champion is:
a1$h2 - 0
a1$h2[a1$h1==H] - 1
Interesting. My
Le 04/07/2012 12:43, Peter Ehlers a écrit :
On 2012-07-03 17:23, jin...@ga.gov.au wrote:
Thank you all for providing various alternatives. They are all pretty
fast. Great help! Based on a test of a dataset with 800,000 rows, the
time used varies from 0.04 to 11.56 s. The champion is:
a1$h2 -
Thanks for your validation. Yes Peter's solution is the fastest, faster than
the previous one by saving 25% time. It was missed out in my previous testing.
Jin
-Original Message-
From: Pascal Oettli [mailto:kri...@ymail.com]
Sent: Wednesday, 4 July 2012 2:07 PM
To: Li Jin
Cc:
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