Hello Luca.
Dr. Ottorino-Luca Pantani wrote:
...
c(1803.02, 193.51, 3.47)
Each solution is to be taken with 3 different pipettes (5000, 250 and 10
µL Volume max) and each of those delivers volumes in steps of 50 µL, 5
µL or 1µL, respectively
Since the above values would
Dear R-users,
I have the following problem
In a lab experiment I have to mix three solutions to get different
concentrations of various molecules in a cuvette
I've used R to calculate the necessary µliters for each of the level of
the experiment and I must confess that it is more useful and
Dr. Ottorino-Luca Pantani ottorino-luca.pantani at unifi.it writes:
In a lab experiment I have to mix three solutions to get different
concentrations of various molecules in a cuvette
I've used R to calculate the necessary µliters for each of the level of
the experiment and I must
On May 9, 2008, at 5:39 AM, Dieter Menne wrote:
Dr. Ottorino-Luca Pantani ottorino-luca.pantani at unifi.it
writes:
Imagine that for a particular cuvette (I have 112 different
cuvettes !!)
you have to mix the following volumes of solution A, B, and C
respectively.
c(1803.02, 193.51,
Charilaos Skiadas ha scritto:
On May 9, 2008, at 5:39 AM, Dieter Menne wrote:
If I understand the OP's question properly, the first value is to be a
multiple of 50, the second a multiple of 5, and the third a multiple
of 1. This can be done with this slight variation on the above theme:
a -
Dear R-users,
I have the following problem
In a lab experiment I have to mix three solutions to get different
concentrations of various molecules in a cuvette
I've used R to calculate the necessary µliters for each of the level of
the experiment and I must confess that it is more useful and
On 5/6/2008 12:07 PM, Dr. Ottorino-Luca Pantani wrote:
Dear R-users,
I have the following problem
In a lab experiment I have to mix three solutions to get different
concentrations of various molecules in a cuvette
I've used R to calculate the necessary µliters for each of the level of
the
Hi Ottorino,
You could just use the modulus operator %% as follows:
x-c(1803.02, 193.51, 3.47);
x-x%%c(50,5,1) #just using the modulus operator
[1] 1800 1903
thanks
Dr. Ottorino-Luca Pantani wrote:
Dear R-users,
I have the following problem
In a lab experiment I have to mix three
I believe this function matches the description in OOO:
mround - function(number, multiple) multiple * round(number/multiple)
I've implemented a slightly more general form in the reshape package:
round_any - function (x, accuracy, f = round) {
f(x/accuracy) * accuracy
}
Hadley
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