Hlp
Given this data
x - c(1,5,100,300,250,200,550,900,1000)
quantile(x)
0% 25% 50% 75% 100%
1 100 250 550 1000
When I run the quantile, I can only know the value of the nth
percentile
I want to know what's the percentile position of each items in the
list
Sample
1 = 100% on the
Hi,
I think you want ecdf(), but read the help page because it works a
little different than you might expect.
ecdf.x - ecdf(x)
ecdf.x(x)
Best,
Ista
On Tue, Sep 7, 2010 at 8:37 AM, mic mikezia...@gmail.com wrote:
Hlp
Given this data
x - c(1,5,100,300,250,200,550,900,1000)
quantile(x)
Is this what you want to have:
x - c(1,5,100,300,250,200,550,900,1000)
# assume you want the position of 25th percentile
which(x==quantile(x,0.25))
[1] 3
Note that position is meaningful only when the percentile is one of the
observed data values. If you want to know the position of 70th
Otherwise you can try following:
x - c(1,5,100,300,250,200,550,900,1000)
which(x==quantile(x,0.25,type=3))
This will always return number within your vector. See further information
with ?'quantile'
Thanks and regards,
--
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It seems to produce some strange values:
xx=1:10
which(xx==quantile(x,0.2,type=3))
[1] 5
which(xx==quantile(x,0.5,type=3))
integer(0)
--
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http://r.789695.n4.nabble.com/Percentile-rank-for-each-element-in-list-tp2529523p2530060.html
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