Took a bit of inspecting, looking at hidden functions, but this seems
to do it:
library(lattice)
a - c(1:10, 5:10)
b - cbind(c(0,2.5,4.5,6.5), c(5.5,7.5,9.5,11))
c - shingle(a, b)
summary(c, showValues=FALSE)
apply(as.matrix(levels(c)), 1, function(x) length(c[ c= x[[1]][1] c
=
On Fri, May 8, 2009 at 1:30 PM, David Winsemius dwinsem...@comcast.net wrote:
Took a bit of inspecting, looking at hidden functions, but this seems to do
it:
library(lattice)
a - c(1:10, 5:10)
b - cbind(c(0,2.5,4.5,6.5), c(5.5,7.5,9.5,11))
c - shingle(a, b)
summary(c,
On May 8, 2009, at 4:55 PM, Deepayan Sarkar wrote:
On Fri, May 8, 2009 at 1:30 PM, David Winsemius dwinsem...@comcast.net
wrote:
Took a bit of inspecting, looking at hidden functions, but this
seems to do
it:
library(lattice)
a - c(1:10, 5:10)
b - cbind(c(0,2.5,4.5,6.5),
Hello!
Suppose I have a set of values:
a - c(1:10, 5:10)
Suppose I also have a set of intervals:
b - cbind(c(0,2.5,4.5,6.5), c(5.5,7.5,9.5,11))
I can create a shingle that counts how many values are in each interval:
c - shingle(a, b)
I can display the shingle to see the counts:
summary(c,
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