Hi,
this should be an easy one, but I can't figure it out.
I have a vector of tests, with their units between brackets (if they have
units).
eg tests - c(pH, Assay (%), Impurity A(%), content (mg/ml))
Now I would like to hava a function where I use a test as input, and which
returns the units
Try this:
replace(gsub(.*\\((.*)\\)$, \\1, tests), !grepl(\\(.*\\), tests), )
On Wed, Oct 13, 2010 at 3:16 PM, Bart Joosen bartjoo...@hotmail.com wrote:
Hi,
this should be an easy one, but I can't figure it out.
I have a vector of tests, with their units between brackets (if they have
Bart,
I'm hardly one of the lists regex gurus: but this can
get you started...
tests - c(pH, Assay (%), Impurity A(%), content (mg/ml))
x - regexpr(\\((.*)\\), tests)
substr(tests, x + 1, x + attr(x, match.length) - 2)
Bart Joosen wrote:
Hi,
this should be an easy one, but I can't figure
One way:
gsub(.*\\(([^()]*)\\).*, \\1,tests)
Idea: Pick out the units designation between the () and replace the
whole expression with it. The \\1 refers to the [^()]*
parenthesized expression in the middle that picks out the units.
Cheers,
Bert
On Wed, Oct 13, 2010 at 11:16 AM, Bart Joosen
Note:
My original proposal, not quite right, can be made quite right via:
gsub(.*\\((.*)\\).*||[^()]+, \\1,tests)
The || or clause at the end handles the case where there are no
parentheses in the string.
-- Bert
On Wed, Oct 13, 2010 at 11:16 AM, Bart Joosen bartjoo...@hotmail.com wrote:
Here's a shorter (but more cryptic) one:
gsub(^([^\\(]+)(\\((.+)\\))?, \\2, tests)
[1] (%) (%) (mg/ml)
gsub(^([^\\(]+)(\\((.+)\\))?, \\3, tests)
[1] % % mg/ml
-Matt
On Wed, 2010-10-13 at 14:34 -0400, Henrique Dallazuanna wrote:
Try this:
On Wed, Oct 13, 2010 at 2:16 PM, Bart Joosen bartjoo...@hotmail.com wrote:
Hi,
this should be an easy one, but I can't figure it out.
I have a vector of tests, with their units between brackets (if they have
units).
eg tests - c(pH, Assay (%), Impurity A(%), content (mg/ml))
strapply in
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