You can keep it a dataframe as follows:
> set.seed(123)
> x <- data.frame(a = 1:10, b = 2:11, c = 3:12, other = rnorm(10))
> x
a b c other
1 1 2 3 -0.56047565
2 2 3 4 -0.23017749
3 3 4 5 1.55870831
4 4 5 6 0.07050839
5 5 6 7 0.12928774
6 6 7 8 1.71506499
7
I think I got it:
set.seed(123)
x <- data.frame(a = 1:10, b = 2:11, c = 3:12, other = rnorm(10))
x
temp <- as.matrix(x[1:3])
temp[temp %in% 7] <- 4
temp[temp > 7] <- temp[temp > 7]-1
x[1:3] <- temp
x
It works only with matrices, right? Can't do x[x>7] when x is a data frame?
Thanks!
On Fri, Jan
Hello!
# I have a data frame x:
x <- data.frame(a = 1:10, b = 2:11, c = 3:12, other = rnorm(10))
# First, I need to change every value 7 in columns a:c to 4
# Then, I need to decrease by 1 all values in columns a:c that are >7
What would be the fastest way of doing it?
Thank you!
--
Dimitri
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