Hello,
Thanks to all for your answers.
The solution given by R. Michael was perfect ! Thank you very much, that
helped a lot !
Thomas
On Tue, Feb 28, 2012 at 11:50 AM, Alemtsehai Abate abatea...@gmail.comwrote:
Perhaps, the following does it as well.
(d - data.frame(x1=letters[2*1:4 - 1],
Perhaps, the following does it as well.
(d - data.frame(x1=letters[2*1:4 - 1], x2=letters[2*1:4]))
c(t(d))
Alemtsehai
Hello,
I am looking for a way to transform an array into a list (or a string).
My array has two columns 1 and 2, and I would like to create a list of
the
values.
Hello,
I am looking for a way to transform an array into a list (or a string).
My array has two columns 1 and 2, and I would like to create a list of the
values.
Let's say I have :
x1 x2
1 a b
2 c d
3 e f
4 g h
What I would
Hello,
Try
(d - data.frame(x1=letters[2*1:4 - 1], x2=letters[2*1:4]))
c(apply(d, 1, identity))
Note that you'll need the concatenation 'c()'.
Hope this helps,
Rui Barradas
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Perhaps the following?
d - structure(list(x1 = structure(1:4, .Label = c(a, c, e,
g), class = factor), x2 = structure(1:4, .Label = c(b,
d, f, h), class = factor)), .Names = c(x1, x2), class =
data.frame, row.names = c(1,
2, 3, 4))
with(d, c(as.character(x1), as.character(x2)))
# [1] a c e g b
Your question is not well formed: do you want a list or a string
(totally different things)? Or even more likely, a character vector?
What do you have now: is it really an array (=matrix) or is it the
data.frame it looks like?
If it's a matrix:
x - matrix(letters[1:8], ncol = 2)
x - as.vector(x)
My apologies: I missed the order of the desired output: the easiest
thing to do is likely to use the same techniques given below (and by
others in this thread) with a transpose t() before.
Michael
On Sat, Feb 25, 2012 at 2:05 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
Your
My apologies. The last line should have been
with(d, sort(c(as.character(x1), as.character(x2
Regards,
Jorge.-
On Sat, Feb 25, 2012 at 2:03 AM, Jorge I Velez wrote:
Perhaps the following?
d - structure(list(x1 = structure(1:4, .Label = c(a, c, e,
g), class = factor), x2 =
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