Just for the record, following Bill Dunlap's advice, I think this is
the best answer to the question as originally posed is.
myfun - function(vec, i=stop('i' must be supplied)){
vec[i]
}
myfun(1:40,10)
[1] 10
myfun(1:10)
Error in myfun(1:10) : 'i' must be supplied
--
Paul E. Johnson
On Mon, Sep 26, 2011 at 2:39 PM, Gene Leynes gley...@gmail.com wrote:
I don't understand how this function can subset by i when i is missing
## My function:
myfun = function(vec, i){
ret = vec[i]
ret
}
## My data:
i = 10
vec = 1:100
## Expected input and behavior:
I don't understand how this function can subset by i when i is missing
## My function:
myfun = function(vec, i){
ret = vec[i]
ret
}
## My data:
i = 10
vec = 1:100
## Expected input and behavior:
myfun(vec, i)
## Missing an argument, but error is not caught!
## How is subsetting
On 26/09/2011 3:39 PM, Gene Leynes wrote:
I don't understand how this function can subset by i when i is missing
## My function:
myfun = function(vec, i){
ret = vec[i]
ret
}
## My data:
i = 10
vec = 1:100
## Expected input and behavior:
myfun(vec, i)
## Missing an argument, but
On Sep 26, 2011, at 4:56 PM, Duncan Murdoch wrote:
On 26/09/2011 3:39 PM, Gene Leynes wrote:
I don't understand how this function can subset by i when i is
missing
## My function:
myfun = function(vec, i){
ret = vec[i]
ret
}
## My data:
i = 10
vec = 1:100
## Expected input
On Mon, Sep 26, 2011 at 3:39 PM, Gene Leynes gley...@gmail.com wrote:
I don't understand how this function can subset by i when i is missing
## My function:
myfun = function(vec, i){
ret = vec[i]
ret
}
## My data:
i = 10
vec = 1:100
## Expected input and behavior:
On 11-09-26 5:15 PM, David Winsemius wrote:
On Sep 26, 2011, at 4:56 PM, Duncan Murdoch wrote:
On 26/09/2011 3:39 PM, Gene Leynes wrote:
I don't understand how this function can subset by i when i is
missing
## My function:
myfun = function(vec, i){
ret = vec[i]
ret
}
## My
Alan and Duncan,
or test them explicitly with missing(). If you want to do this
automatically, then you shouldn't be using substrings and deparse, you
should work at the language level. But I don't see the reason you want to
do this...
Absolutely. That wasn't the way I wanted to do it,
Actually, this version is more general, doesn't need to know the name of the
function:
f = function(x,y){
curfun = deparse(match.call()[1])
curfun = substr(curfun,1,nchar(curfun)-2)
if(length(formals(curfun))!=nargs())
stop('Something is missing...')
}
f()
Putting this code
On Sep 26, 2011, at 8:04 PM, Duncan Murdoch wrote:
On 11-09-26 5:15 PM, David Winsemius wrote:
On Sep 26, 2011, at 4:56 PM, Duncan Murdoch wrote:
On 26/09/2011 3:39 PM, Gene Leynes wrote:
I don't understand how this function can subset by i when i is
missing
## My function:
myfun =
On 11-09-26 8:49 PM, David Winsemius wrote:
On Sep 26, 2011, at 8:04 PM, Duncan Murdoch wrote:
On 11-09-26 5:15 PM, David Winsemius wrote:
On Sep 26, 2011, at 4:56 PM, Duncan Murdoch wrote:
On 26/09/2011 3:39 PM, Gene Leynes wrote:
I don't understand how this function can subset by i
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