Hi:
Summary:
I am trying to determine the 90th percentile of ambulance response times for
groups of data.
Background:
A fire chief would like to look at emergency response times at the 90th
percentile for 1 kilometer grids in Cape Coral, Florida. I have mapped out
ambulance response times on
1) tapply will work for quantile, but the syntax was a little off: try this
tapply(Cape $ ResponseTime, Cape $ Grid_ID, quantile, c(0.05, 0.95))
The fourth argument is additional parameters passed to the function
FUN which here is quantile. You could also do this
tapply(Cape $ ResponseTime, Cape
There's a slight variant that might be even more helpful if you need
to line the data up with how you started: ave(). I'll let you work out
the details, but the key difference is that it returns a vector that
has the 90th percentile for each group, each time that group appears,
instead of the
David:
You need to re-read ?tapply _carefully_. Note that:
FUN the function to be applied, or NULL. In the case of functions
like +, %*%, etc., the function name must be backquoted or quoted.
Now note that in tapply(whatever, byfactor, mean), mean _is_ a function.
However in tapply
Hi:
If you have R 2.11.x or later, one can use the formula version of aggregate():
aggregate(Correct ~ Subject + Group, data = ALLDATA, FUN = function(x)
sum(x == 'C'))
A variety of contributed packages (plyr, data.table, doBy, sqldf and
remix, among others) have similar capabilities.
If you
This is a nice demonstration of the formula interface to aggregate. A
less elegant alternative is to pass lists as arguments.
with(dd,
aggregate(Correct,
by = list(Subject = Subject,
Group = Group),
FUN = function(x) sum(x == 'C')))
HI All,
I have a long data file generated from a minimal pair test that I gave to
learners of Arabic before and after a phonetic training regime. For each of
thirty some subjects there are 800 rows of data, from each of 400 items at
pre and posttest. For each item the subject got correct, there
Since you did provide a description of your data (e.g., at least
'str(ALLDATA)') so that we know its structure, I will take a guess:
tapply(ALLDATA$Correct, list(ALLDATA$Subject, ALLDATA$Time),
function(x)sum(x==C))
On Sat, Apr 30, 2011 at 3:28 PM, Kevin Burnham kburn...@gmail.com wrote:
HI
On 05/01/2011 05:28 AM, Kevin Burnham wrote:
HI All,
I have a long data file generated from a minimal pair test that I gave to
learners of Arabic before and after a phonetic training regime. For each of
thirty some subjects there are 800 rows of data, from each of 400 items at
pre and
Dear R helpers,
I am trying to calculate the Annualized Percent Rate using following R - Code.
#
## R Code
library(animation)
# INPUT
C = 25 # Loan Amount
E = 2500 # Other Cost
R = 6 # Interest rate
r =
Hi:
I'm pretty sure that newton.method in the animation package is meant to
illustrate the technique rather than to be used as an optimizer in practice.
Look at ?optim; it that doesn't meet your needs, consult the Optimization
Task View at CRAN, where you will find several packages, in addition
.
Thanks in advance Sir.
Regards
Amy
--- On Mon, 10/25/10, Dennis Murphy djmu...@gmail.com wrote:
From: Dennis Murphy djmu...@gmail.com
Subject: Re: [R] Using tapply?
To: Amy Milano milano_...@yahoo.com
Cc: r-help@r-project.org
Date: Monday, October 25, 2010, 10:47 AM
Hi:
I'm pretty sure
Hi Amy,
I guess U can just use the apply() function for the purpose U described.
Alex
--
View this message in context:
http://r.789695.n4.nabble.com/Using-tapply-tp3009834p3012694.html
Sent from the R help mailing list archive at Nabble.com.
__
Hello,
I'm trying to use tapply to find group means in a function. It works
outside of a function, but I get the error message from the following code:
Error in tapply(index, cluster, mean) : arguments must have same length.
Any suggestions? Thanks.
eric
d - data.frame(cbind(cluster=1:2,
eric lee wrote:
Hello,
I'm trying to use tapply to find group means in a function. It works
outside of a function, but I get the error message from the following code:
Error in tapply(index, cluster, mean) : arguments must have same length.
Any suggestions? Thanks.
This is neither caused
eric lee ericlee100 at gmail.com writes:
Hello,
I'm trying to use tapply to find group means in a function. It works
outside of a function, but I get the error message from the following code:
Error in tapply(index, cluster, mean) : arguments must have same length.
Any suggestions?
On 5/15/2008 5:05 AM, Patrick Hausmann wrote:
Dear list,
I have a dataframe like this:
w - c(1.2, 1.34, 2.34, 3.12, 2.43, 1.99, 2.01, 2.23, 1.45, 1.59)
g - rep(c(a, b), each=5)
df - data.frame(g, w)
df
df
gw
1 a 1.20
2 a 1.34
3 a 2.34
4 a 3.12
5 a 2.43
6 b 1.99
7 b 2.01
8 b
Dear list,
I have a dataframe like this:
w - c(1.2, 1.34, 2.34, 3.12, 2.43, 1.99, 2.01, 2.23, 1.45, 1.59)
g - rep(c(a, b), each=5)
df - data.frame(g, w)
df
df
gw
1 a 1.20
2 a 1.34
3 a 2.34
4 a 3.12
5 a 2.43
6 b 1.99
7 b 2.01
8 b 2.23
9 b 1.45
10 b 1.59
Using tapply to get
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