Hello,
I have a set of data that has a Date column looks like this:
12/9/2007
12/16/2007
1/1/2008
1/3/2008
1/12/2008
etc.
I'd like the date to look something like the follow (so that I could sort by
date easily).
20071209
20071216
20080101
20080103
20080112
How to do it? Thank you very much
warmstr...@research:~$ R
strptime(12/9/2007,%m/%d/%Y)
[1] 2007-12-09
format(strptime(12/9/2007,%m/%d/%Y),%Y%m%d)
[1] 20071209
On Tue, Jul 21, 2009 at 1:16 PM, liujbliujul...@yahoo.com wrote:
Hello,
I have a set of data that has a Date column looks like this:
12/9/2007
12/16/2007
On 7/21/2009 1:16 PM, liujb wrote:
Hello,
I have a set of data that has a Date column looks like this:
12/9/2007
12/16/2007
1/1/2008
1/3/2008
1/12/2008
etc.
I'd like the date to look something like the follow (so that I could sort by
date easily).
20071209
20071216
20080101
to transform m/d/ to mmdd?
To: r-help@r-project.org
Received: Tuesday, July 21, 2009, 1:16 PM
Hello,
I have a set of data that has a Date column looks like
this:
12/9/2007
12/16/2007
1/1/2008
1/3/2008
1/12/2008
etc.
I'd like the date to look something like the follow (so
that I
Assuming that there are no duplicate dates,
try this using zoo and chron:
Lines - 12/9/2007 0
+ 12/16/2007 1
+ 1/1/2008 2
+ 1/3/2008 3
+ 1/12/2008 4
library(zoo)
library(chron)
z - read.zoo(textConnection(Lines), FUN = chron)
z # is automatically sorted by times
12/09/07 12/16/07 01/01/08
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