1. Statistically, you probably don't want to do this at all (but
that's another story).
2. Programatically, you probably want to use one of several packages
that do it already rather than trying to reinvent the wheel. A quick
search on rseek.org for "all subsets regression" brought up this:
It's hard to imagine a situation where this makes sense, but of course
you can do it if you want. Perhaps
rhs <- unlist(sapply(1:(ncol(df)-1), function(x)
apply(combn(names(df)[-1], x), 2, paste, collapse = " + ")))
lapply(rhs, function(x) lm(as.formula(paste("y ~", x)), data = df))
--Ista
On
Suppose I have the following data:
y<-rnorm(10)
age<-rnorm(10)
sex<-rbinom(10,1, 0.5)
edu<-round(runif(10, 1, 20))
edu2<-edu^2
df<-data.frame(y,age,sex,edu,edu2)
I want to run a large number of models, for example:
lm(y~age)
lm(y~age+sex)
lm(y~age+sex+edu)
lm(y~age+sex+edu+edu2)
Date: Wed, 9 Feb 2011 20:15:23 +0100
From: e.vettora...@uke.uni-hamburg.de
To: ritacarre...@hotmail.com
CC: r-help@r-project.org
Subject: Re: [R] Loop in variable names
Hi Stella,
in your coding 'cut' is a string, not a data object.
something like
cut - paste(P,i, sep=)
table
Hello!
I would like to do some tables for several variables and I would like to write
a loop that does the table for each variable. I should also point out that my
data set has several missing observations and sometimes the observations that
are missing are not the same for all my variables.
Hi Stella,
in your coding 'cut' is a string, not a data object.
something like
cut - paste(P,i, sep=)
table(StoreData$CompanyID, !is.na(StoreData[,cut]))
should work.
hth.
Am 09.02.2011 19:02, schrieb Rita Carreira:
Hello!
I would like to do some tables for several variables and I
Try:
for(i in angus) {
cut - StoreData[[paste(P, i)]]
table(StoreData$CompanyID, !is.na(cut))
}
On Wed, Feb 9, 2011 at 1:02 PM, Rita Carreira ritacarre...@hotmail.com wrote:
Hello!
I would like to do some tables for several variables and I would like to
write a loop that does the table
Often I perform the same task on a series of variables in a dataframe, by
looping through a character vector that holds the names and using paste(),
eval(), and parse() inside the loop.
For instance:
thesevars-names(environmental)
environmental$ToyOutcome-rnorm(nrow(environmental))
Try this:
lm(environmental[c(ToyOutcome, thisvar)])
or
lm(ToyOutcome ~., environmental[c(ToyOutcome, thisvar)])
On Wed, Nov 11, 2009 at 6:49 PM, Jacob Wegelin jacobwege...@fastmail.fm wrote:
Often I perform the same task on a series of variables in a dataframe, by
looping through a
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