Re: [R] multiple logical comparisons

2010-03-22 Thread baptiste auguie
try this one,

`%ni%` - Negate(`%in%`)

Best,

baptiste

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[R] multiple logical comparisons

2010-03-21 Thread Martin Batholdy
Hi,

I would like to compare a column of data with a vector.

I have this data.frame for example;

x - data.frame(A = c(1:5), B = c(1,1,2,2,2))

Now I have a search vector:

search - c(1,3,5)


when I now try to get all the data-rows which have a 1, a 3, or a 5 in column A 
and a 2 in column B, 
I tried this:

x[x$B == 2  x$A == search,]


I hoped to get 
3 2
5 2
as output.


But I get an empty set.


Can someone help me on that?


_

search - c(1,3,5)
x - data.frame(A = c(1:5), B = c(1,1,2,2,2))

x[x$B == 2  x$A == search,]

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Re: [R] multiple logical comparisons

2010-03-21 Thread Erik Iverson

Martin Batholdy wrote:

Hi,

I would like to compare a column of data with a vector.

I have this data.frame for example;

x - data.frame(A = c(1:5), B = c(1,1,2,2,2))

Now I have a search vector:

search - c(1,3,5)


when I now try to get all the data-rows which have a 1, a 3, or a 5 in column A and a 2 in column B, 
I tried this:


x[x$B == 2  x$A == search,]


I hoped to get 
3 2

5 2
as output.


See ?%in%

x[x$B == 2  x$A %in% search, ]

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Re: [R] multiple logical comparisons

2010-03-21 Thread Martin Batholdy
thanks!



Now I have one more question;

How can I do the reverse?
when %in% is == (for two vectors of different lengths); what is the equivalent 
to !=  ?



On 21.03.2010, at 22:33, Erik Iverson wrote:

 Martin Batholdy wrote:
 Hi,
 I would like to compare a column of data with a vector.
 I have this data.frame for example;
 x - data.frame(A = c(1:5), B = c(1,1,2,2,2))
 Now I have a search vector:
 search - c(1,3,5)
 when I now try to get all the data-rows which have a 1, a 3, or a 5 in 
 column A and a 2 in column B, I tried this:
 x[x$B == 2  x$A == search,]
 I hoped to get 3 2
 5 2
 as output.
 
 See ?%in%
 
 x[x$B == 2  x$A %in% search, ]
 
 

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Re: [R] multiple logical comparisons

2010-03-21 Thread Erik Iverson

Martin Batholdy wrote:

thanks!



Now I have one more question;

How can I do the reverse?
when %in% is == (for two vectors of different lengths); what is the equivalent 
to !=  ?



a %in% b returns a logical vector, so

!a %in% b

returns its negation.  See order of precedence in ?Syntax.

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Re: [R] multiple logical comparisons

2010-03-21 Thread David Winsemius

Just read the help page:

?%in%

%w/o% - function(x,y) x[!x %in% y] #-- x without y
(1:10) %w/o% c(3,7,12)
--  
David.

On Mar 21, 2010, at 5:57 PM, Martin Batholdy wrote:


thanks!



Now I have one more question;

How can I do the reverse?
when %in% is == (for two vectors of different lengths); what is the  
equivalent to !=  ?




On 21.03.2010, at 22:33, Erik Iverson wrote:


Martin Batholdy wrote:

Hi,
I would like to compare a column of data with a vector.
I have this data.frame for example;
x - data.frame(A = c(1:5), B = c(1,1,2,2,2))
Now I have a search vector:
search - c(1,3,5)
when I now try to get all the data-rows which have a 1, a 3, or a  
5 in column A and a 2 in column B, I tried this:

x[x$B == 2  x$A == search,]
I hoped to get 3 2
5 2
as output.


See ?%in%

x[x$B == 2  x$A %in% search, ]




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and provide commented, minimal, self-contained, reproducible code.


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