On Wed, 12-Aug-2009 at 09:06AM -0700, Jill Hollenbach wrote:
|
| Thanks so much everybody, this has been incredibly helpful--not only is my
| immediate issue solved but I've learned a lot in the process. The lapply
| solution is best for me, as I need flexibility to edit df's with varying
|
I'm also a newbie, but I've been getting loads of utility out of the grep
function and it's cousin gsub.
Using asterisks are tricky because * often means anything of any length in
a search pattern (e.g. delete *.* means delete all your files!). To find
the literal * using grep you would need to
Hi Jill,
Completely not elegant, but may be usefull.
Of course other colleagues will solve this with 1 line command :-)
cheers
milton
df-read.table(stdin(), head=T, sep=,)
V1,V2,V3,V4
DPA1*,DPA1*,DPB1*,DPB1*
0103,0104,0401,0601
0103,0103,0301,0402
df.new-as.matrix(df)
for (i in 2:dim(df)[1])
On Tue, 11-Aug-2009 at 06:48PM -0700, Jill Hollenbach wrote:
|
| Hi,
| I am trying to edit a data frame such that the string in the first line is
| appended onto the beginning of each element in the subsequent rows. The data
| looks like this:
|
| df
| V1 V2 V3 V4
| 1 DPA1*
you could stick everything in a 1-liner, but that would make it less
readable:
myf - function(x){
tmp - as.character(x)
c(tmp[1], paste(tmp[1], tmp[-1], sep=))
}
df2 - as.data.frame(sapply(df, myf))
b
On Aug 12, 2009, at 3:39 AM, milton ruser wrote:
Hi Jill,
Completely not elegant,
Let's start with something simple and relatively easy to understand,
since you're new to this.
First, here's an example of the core of the idea:
paste('a',1:4)
[1] a 1 a 2 a 3 a 4
Make it a little closer to your situation:
paste('a*',1:4, sep='')
[1] a*1 a*2 a*3 a*4
Sometimes it helps
Thanks so much everybody, this has been incredibly helpful--not only is my
immediate issue solved but I've learned a lot in the process. The lapply
solution is best for me, as I need flexibility to edit df's with varying
numbers of columns.
Now, one more question: after appending the string
Hi,
I am trying to edit a data frame such that the string in the first line is
appended onto the beginning of each element in the subsequent rows. The data
looks like this:
df
V1 V2 V3 V4
1 DPA1* DPA1* DPB1* DPB1*
2 0103 0104 0401 0601
3 0103 0103 0301 0402
.
.
and what
8 matches
Mail list logo
