A quick question for the gurus...
Given:
a=c(58,73,100,40,70)
b=c(40,70,73,100,58,70,70,58)
How can I replace the elements of b with the corresponding index
numbers from a that start at 1? All values in a are unique. So, I
end up with:
b=c(4,5,2,3,1,5,5,1)
I believe I need to use one of the
How about a trick?
b - as.numeric(factor(b, levels=a))
b
[1] 4 5 2 3 1 5 5 1
On Wed, Oct 19, 2011 at 5:38 PM, David Epstein david...@umich.edu wrote:
A quick question for the gurus...
Given:
a=c(58,73,100,40,70)
b=c(40,70,73,100,58,70,70,58)
How can I replace the elements of b with
Subject: [R] replacing values in one vector with corresponding index from
another vector
A quick question for the gurus...
Given:
a=c(58,73,100,40,70)
b=c(40,70,73,100,58,70,70,58)
How can I replace the elements of b with the corresponding index
numbers from a that start at 1? All values
thank you! that is straight forward.
On Wed, 2011-10-19 at 22:37 +, William Dunlap wrote:
match(b, a)
[1] 4 5 2 3 1 5 5 1
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Of Karen Kotschy
Sent: Tuesday, August 17, 2010 4:37 PM
To: Dimitris Rizopoulos
Cc: r-help@r-project.org
Subject: Re: [R] replacing values in a vector
Thanks so much to all those who suggested solutions! You guys are
wonderful!
I went with Dimitris' suggestion in the end.
Regards
Karen
Dear helpRs
Does anyone have an elegant way of doing the following:
For a given numeric vector, e.g. vec - c(3,2,6,4,7)
Create a series of vectors where all but 1 of the values are replaced by
0's, e.g.
vec.a - c(3,0,0,0,0)
vec.b - c(0,2,0,0,0)
vec.c - c(0,0,6,0,0)
vec.d - c(0,0,0,4,0)
Hi Karen,
Try this:
vec - c(3,2,6,4,7)
res - diag(vec)
k - length(vect)
for(i in 1:k) assign(paste('vec', letters[i], sep = '.'), res[i,])
vec.a
# [1] 3 0 0 0 0
vec.b
# [1] 0 2 0 0 0
HTH,
Jorge
On Tue, Aug 17, 2010 at 6:57 AM, Karen Kotschy wrote:
Dear helpRs
Does anyone have an elegant
Try this:
mapply(function(x, y)assign(x, y, envir = globalenv()), sprintf('vec.%s',
letters[1:length(vec)]), split(diag(vec), 1:length(vec)))
On Tue, Aug 17, 2010 at 7:57 AM, Karen Kotschy ka...@sevenc.co.za wrote:
Dear helpRs
Does anyone have an elegant way of doing the following:
For a
] replacing values in a vector
Dear helpRs
Does anyone have an elegant way of doing the following:
For a given numeric vector, e.g. vec - c(3,2,6,4,7)
Create a series of vectors where all but 1 of the values are replaced by
0's, e.g.
vec.a - c(3,0,0,0,0)
vec.b - c(0,2,0,0,0)
vec.c - c(0,0,6,0,0
try this:
vec - c(3,2,6,4,7)
n - length(vec)
for(i in seq_along(vec)){
r - numeric(n)
r[i] - vec[i]
assign(paste(vec., letters[i], sep = ), r)
}
I hope it helps.
Best,
Dimitris
On 8/17/2010 12:57 PM, Karen Kotschy wrote:
Dear helpRs
Does anyone have an elegant way of doing
Thanks so much to all those who suggested solutions! You guys are
wonderful!
I went with Dimitris' suggestion in the end.
Regards
Karen
On Tue 17Aug10, Dimitris Rizopoulos wrote:
try this:
vec - c(3,2,6,4,7)
n - length(vec)
for(i in seq_along(vec)){
r - numeric(n)
r[i] -
Hello list.
I have a vector of values:
eg
head(diff_mirs_list)
[1] hsa-miR-26b hsa-miR-26b hsa-miR-23a hsa-miR-27b hsa-miR-29a
[6] hsa-miR-29b
and I would like to conditionally replace each value in this vector with a
number defined in a dataframe:
fc
Probe ave.fc
1
Boy are you confused. This has nothing at all to do with substitution.
Instead do
test - with(fc,ave.fc[match(diff_mirs_list,Probe)])
cheers,
Rolf Turner
On 7/11/2008, at 11:46 AM, Iain Gallagher wrote:
Hello list.
I have a vector of values:
eg
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