On Thu, 22 Jan 2004, Yun-Fang Juan wrote:
After fitting with lm, I want to get the 95 % confidence intervals of the
expected predicted value.
Of the predicted expected value, I assume?
I know in S-plus I can use pointwise() to get the confidence intervals .
But in R, I couldn't find such a
On Fri, 23 Jan 2004, Briggs, Meredith M wrote:
Is there an R package that solves linear least squares with upper and
lower bounds on the variables. Something like the Parker and Stark
algorithm written in Fortran.
Probably not, but this is an easy application of optim(method=L-BFGS)
or of
Hi,
I am the new maintainer of the R syntax highlighting plugin for kate. (The
initial author, Egon, stopped maintaining it, because he does not use kate
anymore.)
@ Andy: Thanks for providing the link to this file. (I was very busy this week
and did not look at the R mailing list until
On Fri, 2004-01-23 at 01:33, Denise wrote:
Hi everyone,
I've been looking for a function that calculates the Turnbull estimate
for left, right and interval censored data. None of the data that I am
using has exact failure times. The only function I seem to find can handle
data that has no
Now, I am including Richar Upton's 2 cm model implementation and
Christoffer Tornoe's nls solution (I recommend Christoffer's
nlmeODE package for these problems also if multi-response data is
available) The code follows:
Multi-response data?, Is there a way of dealing with those
Hello
I' d like to implement a space-time model as it is formulated
Technometrics vol 22 1980
A three stage iterative procedure for space-time modelling
P,E Pfeiffer, and S.J Deutsch
For model identification the sample space-time autocorrelation and partial
autocorrelation function are
I downloaded R onto my computer using Windows XP
The program itself works fine, but my problem occurs when I type
help.start() and enter the search engine. Whenever I type anything
into
it, nothing happens. I've tried reinstalling it a few times, but the
same
thing keeps
With predict.lda the posterior probabilities only relate to the existing
Class definitions. This is fine for Class definitions like gender but it is
a problem when new data does not necessarily belong to an existing Class.
Is there a classification method that gives posterior probabilities for
At 04:23 AM 1/23/2004, Mike White wrote:
With predict.lda the posterior probabilities only relate to the existing
Class definitions. This is fine for Class definitions like gender but it is
a problem when new data does not necessarily belong to an existing Class.
Is there a classification method
Hi all!
How to retrieve the levels number of a factor object?
See this code:
groups-gl(4,10)
I want to retrieve the number of levels (4) of my object groups
I tried groups.levels but this don't work
Thanks
Laurent Houdusse
Analyste Programmeur
Hello
I was looking for the source code for the new arima procedure the STARMA model
(Space-Time ARMA)
If somebody have the source code of this model please send me them
I'm student and in my research for my master I'm appling the STARMA model for
modelling the pollutant particules.
It's
Thanks. Here is some more info that may help:
I am estimating a transformation model H(Y)=Xb+e and have obtained (up
to a location parameter) an estimated of H(T), call it H_est(T). (Its a
new estimator I am trying out that works with unspecified functional
forms etc). Now if the model is a
On Fri, 2004-01-23 at 08:24, Laurent Houdusse wrote:
Hi all!
How to retrieve the levels number of a factor object?
See this code:
groups-gl(4,10)
I want to retrieve the number of levels (4) of my object groups
I tried groups.levels but this don't work
Thanks
Laurent Houdusse schrieb:
Hi all!
How to retrieve the levels number of a factor object?
See this code:
groups-gl(4,10)
I want to retrieve the number of levels (4) of my object groups
I tried groups.levels but this don't work
Simply try:
length(levels(groups))
Thomas P.
Hi,
Is there any existing way in R of doing response surface analyses and
plotting the response surface, like what minitab can do?
Thanks
Xiaolei
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Wassim Kamoum [EMAIL PROTECTED] writes:
Hello
I was looking for the source code for the new arima procedure the STARMA model
(Space-Time ARMA)
If somebody have the source code of this model please send me them
I'm student and in my research for my master I'm appling the STARMA
Hello
I was looking for the source code for the new arima procedure the STARMA model
(Space-Time ARMA)
If somebody have the source code of this model please send me them
I'm student and in my research for my master I'm appling the STARMA model for
modelling the pollutant particules.
It's
Eugene Salinas (R) [EMAIL PROTECTED] writes:
Thanks. Here is some more info that may help:
I am estimating a transformation model H(Y)=Xb+e and have obtained (up
to a location parameter) an estimated of H(T), call it H_est(T). (Its
a new estimator I am trying out that works with unspecified
thanks to everyone for their help. easy now. best regards, /iaw
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PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
On 23 Jan 2004, Peter Dalgaard wrote:
Wassim Kamoum [EMAIL PROTECTED] writes:
Hello
I was looking for the source code for the new arima procedure the STARMA model
(Space-Time ARMA)
If somebody have the source code of this model please send me them
I'm student and in my
Dear R-helpers,
I got the following problem with the function hasArg()
I would like to use the function to check whether the argument crit is
present as an argument of the function (here is the simplified version of
the function):
SDT.Optim - function(crit = NULL, Hess = F)
{
[EMAIL PROTECTED] wrote on 23/01/2004 15:24:21:
Hi all!
How to retrieve the levels number of a factor object?
See this code:
groups-gl(4,10)
I want to retrieve the number of levels (4) of my object groups
I tried groups.levels but this don't work
Is
Please do give reproducible example. The code you gave, which you claimed
`works correctly' doesn't:
SDT.Optim - function(crit = NULL, Hess = F)
+ {
+ q - length(par); x - data
+ if(hasArg(crit))
+ cat(\n Crit
groups-gl(4,10)
levels(groups)
[1] 1 2 3 4
length(levels(groups))
[1] 4
Is this what you want?
spencer graves
Laurent Houdusse wrote:
Hi all!
How to retrieve the levels number of a factor object?
See this code:
groups-gl(4,10)
I want to retrieve the number of levels
as I am playing around with parameters to graphics, it seems to me that
there would be a market for a book written that is the equivalent of the
perl cookbook, but for graphics creation in R/S. just demonstrating how
each parameter works, how one can make complex graphics, some graphics
Laurent Houdusse [EMAIL PROTECTED] writes:
Hi all!
How to retrieve the levels number of a factor object?
See this code:
groups-gl(4,10)
I want to retrieve the number of levels (4) of my object groups
I tried groups.levels but this don't work
Thanks
Do you mean
See the rw-FAQ, which explains this (as you have already been told
privately).
The problem is in your browser configuration, not in R. You need Java and
Javascript installed and enabled.
On Fri, 23 Jan 2004, Tamara Porter wrote:
I downloaded R onto my computer using Windows XP
The
Hi, there,
I'd like to get a statistics to reflect the correlation of two time
serials observations. for example, one time serials over time 1 to 20, and
another one from same time points from 1 to 20. I need one scalar satistics
as a correlation of these two observations.
Thank you and have a
Greetings R-friends,
I'm looking for some code to fit an ARMA, up to (3,3), preferably with ML.
I'm doing a simulation experiment, so I need to fit it to the order of
millions of times. I'm using Professor Ripley's arima() command right now,
but I hope to find soemthing faster in c. Does anyone
Hi!
I am trying to get R to run regressions for me of a variable on lagged
differences of itself.
Specifically:
x-x(-1) = a + b1(x(-1)-rx(-2))+b2(x(-4)-rx(-5))+e
I need to do this a lot of times, altering the value of r.
What I've been trying to do was to use the lag() command to create
You need to do tsunion (or something like it) on the time series. lm()
does not know about time series and you are merely supplying vectors as
far as it is concerned.
On Fri, 23 Jan 2004, Tobias Mühlhofer wrote:
Hi!
I am trying to get R to run regressions for me of a variable on lagged
Sorry I didn't answer before.
Martin, thanks very much for your notes and for tidying the function
up!= ! I've learnt a lot with you.
About matPower, I didn't realise that where it says pot - pot %*% p ot,
consumption of memory was higer than it was on the original
algorithm,=
Hi all,
Here is a summary of substantive replies to my posts (on both s-news and
r-help) regarding use of Excel's Solver for a nonlinear regression problem.
A number of people replied that Solver performs well as an optimizer
based on experience, particularly if given reasonable starting
Dear Jesus,
Yes there is a way and it is via Christoffer Torn\{o}e's package nlmeODE. I checked
Chapter 4 of Bates and Watts. As usual, a little work involved, but doable and quite
powerful.
Thanks,
olinares
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Dear R Users,
Does anyone know how to specify Y-label in plot.stepfun()? I do:
library(stepfun)
x = ecdf(rnorm(30))
plot(x, ylab='CDF')
and I get:
Error in plot.stepfun(ylab = Fn(x), ..., verticals = verticals) :
formal argument ylab matched by multiple actual arguments
Thanks,
Aleksey
Hi,
I am working on a model sort of like a credit assignment problem.
The goal is to get non-negative weights for each input variable and
discount the predictors (down to 0) that lead to no credits.
I am trying out the lm fitting and find out they give a lot of negative weights.
I am totally
On Fri, 23 Jan 2004 12:08:31 +, you wrote:
I downloaded R onto my computer using Windows XP
The program itself works fine, but my problem occurs when I type
help.start() and enter the search engine. Whenever I type anything
into
it, nothing happens. I've tried reinstalling
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