Dear Jeff,
I believe this works:
data.frame - data.frame[order(data.frame$var.1, data.frame$var.2),]
HTH,
Adrian
Adrian Dusa
Romanian Social Data Archive
1, Schitu Magureanu Bd.
050025 Bucharest sector 5
Romania
Tel./Fax: +40 (21) 312.66.18\
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Chiara Seghieri wrote:
Dear All,
I'm trying to maximize a likelihood with respect one parameter using
optimize on simulated data (without error component).
I've iterated the maximization procedure 1000 times and I should always
obtain the same estimate of the parameter (equal to the simulated
If indeed your error space is pitted with local minima then I suggest you
might try a method called
bootstrap restarting to avoid these spurious local minimas.
The paper was authored by Simon Wood and can be found here
http://www.stats.gla.ac.uk/~simon/simon/papers/bsfit.pdf
-Original
**
June Elijah Simakani
Department of Statistics
University of Port Elizabeth, Vista Campus
P.O.Box 1600, Port Elizabeth 6000
South Africa
Tel.no: + 27(41) 408 3234(w)
+ 27(41) 582 1573(h)
Fax.no: + 27(41) 464 2859
Christoph, yes there IS a way, such as the horrible
eval(parse(text=paste(c(, my.group[1],
= , class.weight[2], ,, my.group[2], = , class.weight[1], ), sep=)))
BUT I would suggest you rethink whether there isn't a an altogether
more straightforward way to do what you want. For example,
tmp
Maybe you should show your colleague how to access help pages in R? Right
in ?knn, it says:
prob: If this is true, the proportion of the votes for the winning
class are returned as attribute 'prob'.
so 1.0 mean all three NNs are of the `winning'; i.e., predicted, class, and
Dear R users,
I have found a quite uncommon behaviour when compiling a library I want
to call from R (avce00, in package RArcInfo).
I define CPL_LSB (-DCPL_LSB is passed to the compiler in the command
line) but it's useless, since #ifdef CPL_LSB ... #endif clauses doesn't
notice that CPL_LSB is
Hi,
-Original Message-
From: Liaw, Andy [mailto:[EMAIL PROTECTED]
Maybe you should show your colleague how to access help pages
in R? Right
in ?knn, it says:
prob: If this is true, the proportion of the votes for the
winning
class are returned as attribute 'prob'.
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hello,
for my present project i need to use the data stored in a ca. 100mb
stata dataset.
when i import the data in R using:
library(foreign)
x-read.dta(mydata.dta)
i find that R needs a startling 665mb of memory!
(in stata i can simply allocate, say, 128mb of memory and go ahead)
is there
Hi,
problem solved passing to R 1.9.0 (in the Debian unstable branch).
Stefano
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Edwin Leuven [EMAIL PROTECTED] writes:
for my present project i need to use the data stored in a ca. 100mb
stata dataset.
when i import the data in R using:
library(foreign)
x-read.dta(mydata.dta)
i find that R needs a startling 665mb of memory!
(in stata i can simply allocate,
Dear Dr. Brainard,
In addition to what Roger has pointed out, I would like to point out one
fact that you seem not to be aware of. Open source software, by and large,
have licences, just as the proprietary ones. Openly asking others to send
you the code, IMHO, is plain disregard of the licence
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What does the 665 MB represent? Did you try doing a garbage
collection after you had done the import?
i didn't (sorry, R beginner)
i followed your example and things look much better now, and
object.size(x) returns:
219,167,604
which is about double the size of the same object in stata
Dear R people
I came across a strange thing:
sd(rep(0.01, 15)) #0
sd(rep(0.001, 15)) #4.489023e-19
sd(rep(0.1, 15)) #0
sd(rep(0.0001,15)) #1.712427e-24
sd(rep(0.01, 13)) #1.805557e-18
sd(rep(0.001, 13)) #4.513894e-19
sd(rep(0.1, 13)) #0
Hi,
I have a problem, can you help?
When i type:
library(RODBC)
a-odbcConnect(oracle)
sqlQuery(a,(select VALFACT500 from EPISGDHS) UNION (select
VALFACT1000 from EPISGDHS))
Comes the error:
[1] S1000 923 [unixODBC][Easysoft][Oracle]ORA-00923: FROM keyword not
found where expected at
Hello,
-Original Message-
From: Andreas Pauling [SMTP:[EMAIL PROTECTED]
Sent: Monday, March 29, 2004 4:02 PM
To: [EMAIL PROTECTED]
Subject: [R] strange thing with sd
Shouldn't it give always zero?
I was running your example code, and I always had the result zero
I tried your sample code, and a few other variations, and got 0 for all
of them, running R 1.8.1 on a Windows machine
Peter
Peter L. Flom, PhD
Assistant Director, Statistics and Data Analysis Core
Center for Drug Use and HIV Research
National Development and Research Institutes
71 W. 23rd St
Peter Flom wrote:
I tried your sample code, and a few other variations, and got 0 for all
of them, running R 1.8.1 on a Windows machine
Not only do I get 0 on R 1.8.1 on Unix (linux, RH8), I get _exactly_
0. I thought this was going to be a simple arithmetic precision problem,
but this test
Zitat von Barry Rowlingson [EMAIL PROTECTED]:
Peter Flom wrote:
I tried your sample code, and a few other variations, and
got 0 for all
of them, running R 1.8.1 on a Windows machine
Not only do I get 0 on R 1.8.1 on Unix (linux, RH8), I get
_exactly_
0. I thought this was going to
Just so you don't feel that you are alone
I get the same response as you use R1.8.0 on an XP operating system.
Alex
-Original Message-
From: Andreas Pauling [mailto:[EMAIL PROTECTED]
Sent: March 29, 2004 10:02 AM
To: [EMAIL PROTECTED]
Subject: [R] strange thing with sd
Dear R
Hi,
I have another problem, can you help?
When i type:
library(RODBC)
a-odbcConnect(oracle)
sqlQuery(a,select DISTINCT(DOENT_ID) from EPISGDHS where (VALFACT
BETWEEN 100 AND 50))
Comes the error:
[1] S1000 904 [unixODBC][Easysoft][Oracle]ORA-00904: \DOENT_ID\: invalid
identifier at
Is the ca. 100MB the size of the .dta file, or the size of the data when
loaded into Stata? Or is there not a difference? Have you checked the size
of the .rda file created as Doug had suggested? I'd be curious to see what
that is...
Andy
From: Edwin Leuven
What does the 665 MB
Hi,
I'm trying to get confidence intervals to slopes from a linear model
and I can't figure out how to get at them. As a cut 'n' paste example:
#
# dummy dataset - regression data for 3 treatments, each treatment with
different (normal) variance
x - rep(1:10, length=30)
y - 10
Andreas Pauling wrote:
Dear R people
I came across a strange thing:
sd(rep(0.01, 15)) #0
sd(rep(0.001, 15)) #4.489023e-19
sd(rep(0.1, 15)) #0
sd(rep(0.0001,15)) #1.712427e-24
sd(rep(0.01, 13)) #1.805557e-18
sd(rep(0.001, 13)) #4.513894e-19
sd(rep(0.1,
On Mon, 29 Mar 2004, Liaw, Andy wrote:
Is the ca. 100MB the size of the .dta file, or the size of the data
when loaded into Stata? Or is there not a difference?
i think it is about the same.
info on the processes using top to get an idea of memory use of R vs
Stata using the same data:
Stata tends to store data as float, integer, or even byte where
appropriate for the precision. This is one source of space saving. A
factor of 2 is not atypical.
i was suspecting something like this.
what does R do? default to double always (or something like this)?
is this a deliberate
David,
try the estimable() function in the gregmisc package.
Andrew
On Monday 29 March 2004 06:44, David Orme wrote:
Hi,
I'm trying to get confidence intervals to slopes from a linear model
and I can't figure out how to get at them. As a cut 'n' paste example:
#
# dummy
Dear Cecilia,
while Saghir and Kjetil may have a point, guidances are no laws. After all,
it's your presentation and only you can decide what suits the specific
purpose best.
An R logo can be found on http://www.r-project.org/foundation/.
Knut
At 09:17 2004-03-29 +0200, Bashir Saghir (Aztek
Dear list,
here is an example of stepAIC that I do not understand.
The data is n=42, Lage is the only factor and there are four other
variables treated as continuous.
First you see the stepAIC-forward solution (fs7). The strange thing here
is that apparently not all interactions are tried for
On 29 Mar 2004, at 16:54, Andreas Plank wrote:on=2.63
my question is about ordination technics:
To decide using a linear model response or a unimodal model response,
in Canoco (software for ordination technics)
you can calculate a so-called length of gradient.
(from Canoco Help file:)
The length
I have numeric vector z and I want to factorize it using z$breaks
which I got from histograms breaks. Is there an elegant way to do this ?
I, probably, could write a loop and check if z hits into some interval
and replace z with value of z$mids, but I suspect there is more
R-ish way.
My organization has a policy against installing software downloaded from
the Internet. There is a waiver procedure, but it is difficult and
lengthy. It is much easier to get approval to purchase software, even if
it is a CD copy of open-source.
However, a search on r-project.org didn't seem
Oleg Bartunov oleg at sai.msu.su writes:
I have numeric vector z and I want to factorize it using z$breaks
Have a look
at:
?cut
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If you can use Linux, you can buy a Quantian CD from cheapbyte.com for
$4.99, I believe. Quantian is a `live' CD: You pop it in the CD drive,
boot up the computer, and voila, it runs Debian Linux right off the CD,
without touch the hard drive. Quantian has R and a whole suite of other
[EMAIL PROTECTED] wrote:
My organization has a policy against installing software downloaded from
the Internet. There is a waiver procedure, but it is difficult and
lengthy. It is much easier to get approval to purchase software, even if
it is a CD copy of open-source.
However, a search on
George_Heine at blm.gov writes:
My organization has a policy against installing software downloaded from
the Internet.
Check out:
http://dirk.eddelbuettel.com/quantian.html
__
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[EMAIL PROTECTED] wrote:
My organization has a policy against installing software downloaded from
the Internet. There is a waiver procedure, but it is difficult and
lengthy. It is much easier to get approval to purchase software, even if
it is a CD copy of open-source.
However, a search on
sd(rep(0.01, 15)) #0
sd(rep(0.001, 15)) #4.489023e-19
sd(rep(0.1, 15)) #0
sd(rep(0.0001,15)) #1.712427e-24
sd(rep(0.01, 13)) #1.805557e-18
sd(rep(0.001, 13)) #4.513894e-19
sd(rep(0.1, 13)) #0
sd(rep(0.0001,13)) #0
sd(rep(5.01,15)) #0
Why Dont U Download and Burn into a CD at your Home?
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Barry Rowlingson
Sent: Monday, March 29, 2004 3:08 PM
To: [EMAIL PROTECTED]
Cc: [EMAIL PROTECTED]
Subject: Re: [R] How to purchase R on CD
[EMAIL
Thnak you all,
I was running R-base-care 1.5.01 (the debian site default). I
replaced this (at Uwe's suggestion) with 1.8.1 from the CRAN site and
gregmisc installs and runs cleanly.
Thanks again,
Christian
On Mon, 29 Mar 2004, Warnes, Gregory R wrote:
Date: Mon, 29 Mar 2004 08:59:51
I have run several glm models and would like to obtain the
adjusted R squared for the model. What is the appropriate command for
obtaining an adjusted R squared?
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Thanks to Marc Schwartz and Jim Lemon for their solutions, and
the very useful document by JL.
This is a summary in case it is useful to others.
My problem was to provide, for the same data series, two
different X ordinates ('axes' was probably a misnomer here).
In this case, both ordinates
You may want:
lm( y ~ x:z )
This is the same model you fitted, but prametrized differently.
But please check that what you REALLY want is not
lm( y ~ z + x:z )
This is the model with different intercepts as well.
Bendix Carstensen
--
Bendix Carstensen
Senior Statistician
Thanks for the explanation. I actually had read the help page for
dev.print after finding this statement in the Defunct help page (while
searching for savePlot):
The new function `dev.print()' should now be used for saving plots
to a file or printing them.
Personally I didn't find the
On Mon, 29 Mar 2004, Gabor Grothendieck wrote:
Oleg Bartunov oleg at sai.msu.su writes:
I have numeric vector z and I want to factorize it using z$breaks
Have a look
at:
?cut
Thanks for pointers, this is what I needed.
__
[EMAIL PROTECTED]
Eric,
thanks for quick reply. at first look I thought it is what I need,
but, unfortunately, it doesn't applied to original data - it
creates new data with loosing original indexes ! I want to keep indexes
of original data, but replace original data with $mids of corresponding
$breaks.
So, if I
Oleg Bartunov oleg at sai.msu.su writes:
I want to keep indexes
of original data, but replace original data with $mids of corresponding
$breaks.
Note the label= arg on cut:
cut(z,t$breaks,lab=t$mids)
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On Tue, 30 Mar 2004 00:06:39 +0400 (MSD) Oleg Bartunov wrote:
Eric,
thanks for quick reply. at first look I thought it is what I need,
but, unfortunately, it doesn't applied to original data - it
creates new data with loosing original indexes ! I want to keep
indexes of original data, but
Hello, it want to know if there is a library that transform a file in
excell (*. xls) to text file(*.txt, *,prn, *.csv). Thanks
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On Mon, 29 Mar 2004, Achim Zeileis wrote:
On Tue, 30 Mar 2004 00:06:39 +0400 (MSD) Oleg Bartunov wrote:
Eric,
thanks for quick reply. at first look I thought it is what I need,
but, unfortunately, it doesn't applied to original data - it
creates new data with loosing original indexes
Maybe but,
From excel
save as
then set type to one that you want.
Perl has some tools for this, and various Windows scripting languages can do
this.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Sent: Monday, March 29, 2004 3:22 PM
To: [EMAIL PROTECTED]
Subject:
I have a 2 by 226200 table, conveniently read in by read.table(), which
exhibits some strange behavior when plotted by plot(V1,V2). The general
pattern for the range of windspeeds, [0V150] is as expected -- the wind
gust falls in the interval [V1V265] except for certain values of V2.
For V2 ==
On Mon, 29 Mar 2004 14:06:36 -0800 (PST), Clint Bowman
[EMAIL PROTECTED] wrote :
I have a 2 by 226200 table, conveniently read in by read.table(), which
exhibits some strange behavior when plotted by plot(V1,V2). The general
pattern for the range of windspeeds, [0V150] is as expected -- the wind
Hello,
My data is discrete, taking values between around -5 and +5.
I cannot give bounds for the values. So I consider it as
numerical data and not categorical data.
The histogram has a 'normal' shape, so
I test for normality via a chisquare statistic (by calculating the expected
values by
Right on. The convenience of slurping up data with read.table() and the
nearly expected plot caused me to overlook that V2 was read in as a
factor. I also had quite a few NAs which may have contributed to the
problem.
Thanks
On Mon, 29 Mar 2004, Duncan Murdoch wrote:
On Mon, 29 Mar 2004
On Mon, 29 Mar 2004, Edwin Leuven wrote:
Stata tends to store data as float, integer, or even byte where
appropriate for the precision. This is one source of space saving. A
factor of 2 is not atypical.
i was suspecting something like this.
what does R do? default to double always (or
On 29-Mar-04 [EMAIL PROTECTED] wrote:
Hello,
My data is discrete, taking values between around -5 and +5.
I cannot give bounds for the values. So I consider it as
numerical data and not categorical data.
The histogram has a 'normal' shape, so I test for normality
via a chisquare
On 29 Mar 2004, at 19:07, Christian Hennig wrote:
Dear list,
First you see the stepAIC-forward solution (fs7). The strange thing here
is that apparently not all interactions are tried for inclusion, but
only
WQ:Lage. In particular, I think that WFL:Lage should be tried
in the last two steps,
G'day Stefano,
SC == Stefano Calza [EMAIL PROTECTED] writes:
SC Hi. I'm experiencing a problem with updating packages on R
SC 1.8.1 (2003-11-21) on Debian testing. I get the following
SC message when updating for example Design:
SC ... ... /usr/bin/ld: cannot find -lg2c-pic
Hi,
I've recently purchased PowerBookG4 (panther) and installed RAqua 1.8.1.
I also installed gcc version 3.3 through Xcode tools. But, for some
reason, I'm having a hard time getting gcc work with R. For example, I get
the following error while installing Hmisc package. I would appreciate any
Kosuke,
I tried to reproduce your error, running OS X 10.3.3, R 1.8.1. and gcc 3.3
20030304. Hmisc installed without any problem.
Sorry that I couldn't help more.
Andrew
On Monday 29 March 2004 20:21, Kosuke Imai wrote:
Hi,
I've recently purchased PowerBookG4 (panther) and installed
We are pleased to announce that the development of the
notorious Method for Object Recognition of Obscure Nature
(or Moron, for short) has been switched to the R language.
Given a directory of images (i.e. jpegs), Moron attempts
to predict a category distribution for the content of each
image.
Hello !
I need help ! I would like to make a recursive regression on a logistic model (or
linear model) to test the the stability of my data.
Is anybody know if R has a special command or not ?
Thanks for your help.
Best regards,
**
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