Hi Christian
I did not see any response to your question yet, and my will not be
very helpful. The error message comes from axis building, plot
itself seems to be OK. If you choose slightly bigger value for ylim
it will go through without any complain.
plot(x,y, log = y, ylim = c(30,1.2))
Dear John,
I have not expected to cause that many traffic and largish discussion.
What I tried to point out is that:
- a programmer should know that one has to use TRUE / FALSE in code in
order to make it work generaly which is also checked by R CMD check.
- a user simply typing some lines in
Hi!
How to compute probabilities of survival from rpart object?
Consider the following example:
library(rpart)
survtree - rpart(Surv(time,status)~., data=aml)
This code will produce the following survival tree:
1) root 23 26.44184 1.000
2) x=Maintained 11 12.61182 0.6848303 *
3)
Bruce Foster [EMAIL PROTECTED] writes:
...
The machines are AMD Athlon MP 2400+ with 2 GB RAM, dual CPUs, and
lots of free disk space.
Any per-user/per-process limits? Resource usage look suspiciously
close to 256M. If your install is allowing overcommitment of memory,
the OS can kill
Thank you. I somehow missed your answer and find it only after I
went through archives. I had to have partial blindfoldness when
searching in your book and in documentation for the answer.
Best regards
Petr Pikal
On 10 May 2005 at 13:24, r-help@stat.math.ethz.ch wrote:
Dear all
Please
I would like to donc an AFC (factoriel correspondance analysis) and I know that
on Splus, the function to do that is afc(data). But on R??? is it acm?
That a lot!
Sabine
-
ils, photos et vidéos !
[[alternative HTML version deleted]]
http://snipurl.com/f0xh
(leads you to packages 'ade4' and 'MASS')
-s.
Navarre Sabine wrote:
I would like to donc an AFC (factoriel correspondance analysis) and I know that
on Splus, the function to do that is afc(data). But on R??? is it acm?
That a lot!
Sabine
my help.search didn't give me any result :(
the one you suggest should be right what I need
thank you,
simone
Il giorno 20/mag/05, alle 00:33, Chuck Cleland ha scritto:
help.search(latent class) shows lca() in the e1071 package.
simone gabbriellini wrote:
Dear List,
just a little question,
I am
Hi
I'm generating the following in a file and getting a syntax error:
bryansAtHeaderLevel -
oops, I forgot to attach the example txt file with the syntax error, so I will
do it here, can anyone see what the error is with bryansAtLineLevel?
bryansAtHeaderLevel -
It is my experience that location parameters are not very affected
by the garch parameters. So doing a naive estimate of location,
followed by the garch estimate, followed by an estimate of location
accounting for heteroskedasticity is likely to be indistinguishable
from the estimates from the
TL == Thomas Lumley [EMAIL PROTECTED]
on Thu, 19 May 2005 09:39:13 -0700 (PDT) writes:
TL On Thu, 19 May 2005, Rod Montgomery wrote:
Thomas Lumley wrote:
This one is actually a FAQ, mtx[,1,drop=FALSE]
-thomas
I wonder whether there is, or should be, a way
On May 20, 2005, at 11:00 am, Jan T. Kim wrote:
On Thu, May 19, 2005 at 03:10:53PM -0400, John Fox wrote:
Since you can use variables named c, q, or t in any event, I don't
see why
the existence of functions with these names is much of an impediment.
True, particularly since I'm not too likely to
You have to have the package installed for help.search() to find things in
it. You could try
RSiteSearch(latent class, restrict=function)
Andy
From: Simone gabbriellini
my help.search didn't give me any result :(
the one you suggest should be right what I need
thank you,
simone
Well...
You just can't end vector declaration with a comma...
x - c(0,1,)
Error: syntax error
x - c(0,1)
Eric
Eric Lecoutre
UCL / Institut de Statistique
Voie du Roman Pays, 20
1348 Louvain-la-Neuve
Belgium
tel: (+32)(0)10473050
[EMAIL PROTECTED]
Why do you expect FF to specify a Fortran compiler when F77 works on the
command line?
I would expect F77 to work.
On Thu, 19 May 2005, Joel Bremson wrote:
Hi all,
Thanks to all who offered advice on using F95 in R.
Now I'm trying to compile a test package using gfortran, Linux 2.4.21 and
R
Very little space is available in one of my plots for the legend. I would
like to lift it out of the main plot area and present it in the subtitle
area. Would appreciate any help that I can get.
Ravi Vishnu
This message is meant for the addressee only and may contain
confidential and
Dear list,
I have a degradation model:
dX/dt = * I(X2)*( k1*X(t) )/( X(t)+k2 )
where X(t) is concentration at time t, and k1 and k2 are parameters
that I want to estimate. I(X) is a known inhibitor function.
My questions is whether this is implemented or easily computed in any
R package. I
Hi folks,
I try to plot a variable which contains string-variables. it works, but the
problem is that there are a lot of values at the x axis (up to 24)
SO i have to scale or rotate the label at the x axis.
I tried this with the text() function. It doesn't work correctly.
Is there a simple way
Dear r-help,
Now I am drawing graphs with xyplot function.
In order to place a legend under the plots I use the key argument in
the xyplot function.
One of the 'key' components is 'divide', which defines a number of
points on the each line of the legend. The default is 3 points.
I
Eric Lecoutre wrote:
Well...
You just can't end vector declaration with a comma...
x - c(0,1,)
Error: syntax error
x - c(0,1)
You may not be able to, but I can!
x=c(0,1,)
x
[1] 0 1
( R 2.0.1 and R 1.8.1 )
I suspect the error is more to do with the length of the line
overflowing a buffer, so
Sebastian Schoenherr wrote:
Hi folks,
I try to plot a variable which contains string-variables. it works, but the
problem is that there are a lot of values at the x axis (up to 24)
SO i have to scale or rotate the label at the x axis.
I tried this with the text() function. It doesn't work
[EMAIL PROTECTED] wrote:
Very little space is available in one of my plots for the legend. I would
like to lift it out of the main plot area and present it in the subtitle
area. Would appreciate any help that I can get.
Look at the following code and read the corresponding help pages:
On 5/20/05, Robin Hankin [EMAIL PROTECTED] wrote:
On May 20, 2005, at 11:00 am, Jan T. Kim wrote:
On Thu, May 19, 2005 at 03:10:53PM -0400, John Fox wrote:
Since you can use variables named c, q, or t in any event, I don't
see why
the existence of functions with these names is much
Le 20.05.2005 13:20, Sebastian Schoenherr a écrit :
Hi folks,
I try to plot a variable which contains string-variables. it works, but the
problem is that there are a lot of values at the x axis (up to 24)
SO i have to scale or rotate the label at the x axis.
I tried this with the text() function.
From: Robin Hankin
On May 20, 2005, at 11:00 am, Jan T. Kim wrote:
On Thu, May 19, 2005 at 03:10:53PM -0400, John Fox wrote:
Since you can use variables named c, q, or t in any event, I don't
see why
the existence of functions with these names is much of an
impediment.
True,
You can in R-2.1.0 Patched:
c(1,)
[1] 1
--sundar
Eric Lecoutre wrote:
Well...
You just can't end vector declaration with a comma...
x - c(0,1,)
Error: syntax error
x - c(0,1)
Eric
Eric Lecoutre
UCL / Institut de Statistique
Voie du Roman Pays, 20
1348 Louvain-la-Neuve
Belgium
tel:
On 20-May-05 Eric Lecoutre wrote:
Well...
You just can't end vector declaration with a comma...
x - c(0,1,)
Error: syntax error
x - c(0,1)
Eric
Well, maybe some people can't achieve that, but I can:
x-c(1,2,3,)
x
[1] 1 2 3
(on both R-1.8.0 and R-2.1.0beta)
Best wishes to all,
Hello,
Regarding use of parenthesis, it is true that R is much better with
f(10) != f[10] != f[[10]], where Matlab is a little confusing. Also, in
Matlab, you can use some functions without (), further adding to the
confusion (the only example that comes to my mind in R is the use of '?'
as
It seems although your are trying to do a retrospective power calculation -
not something to be encouraged.
I don't think that power.t.test was designed to work on observed data in the
way you seem to want to use it. You could use power.t.test to do a
prospective calculation where you know the
On Fri, 20 May 2005, bogdan romocea wrote:
On 20-May-05 Uwe Ligges wrote:
All possible changes to T/F (both removing the meaning of
TRUE/FALSE in a clean session and making them reserved words)
would break code of lots of users.
Just wanted to point out that there's another (darker) side to this:
From: Philippe Grosjean
Hello,
Regarding use of parenthesis, it is true that R is much better with
f(10) != f[10] != f[[10]], where Matlab is a little
confusing. Also, in
Matlab, you can use some functions without (), further adding to the
confusion (the only example that comes to my
Sundar Dorai-Raj [EMAIL PROTECTED] writes:
You can in R-2.1.0 Patched:
c(1,)
[1] 1
--sundar
Eric Lecoutre wrote:
Well...
You just can't end vector declaration with a comma...
x - c(0,1,)
Error: syntax error
x - c(0,1)
I can in versions going back to 1.8.0 (did Eric
hi all
i have a simple question. code is displayed below.
how can i use a vectorised command in order to do this (ie replace the
loop)? (ie apply, lapply, sweep, etc)
z-matrix(c(1:9),3,3)
top-c(1.5,5.5,9)
for (i in 1:3) z[z[,i]top[i]]-top[i]__
Liaw, Andy wrote:
Don't give up to easily: If _ can be done away as assignment operator,
I'd guess anything is fair game...
Even my great dream that R and Python eventually merge into the same
language? R gets Python's syntax and Object-oriented functions and
Python gets access to all R's
On May 20, 2005, at 01:14 pm, Liaw, Andy wrote:
[snip]
R uses round brackets in two unrelated ways:
4*(1+2) --- using ( and ) to signify grouping
f(8) function f() evaluated at 8.
where there is no reason to use the same parenthesis symbol for both
tasks.
The same is done in
It might be worth pointing out that R is supposed to have a 1024 byte (not
character) input buffer, and I did fix a few things related to that when
internationalizing the parser (and also some about multi-byte pushbacks
which I suspect is the issue here).
It is still good practice to keep
On Friday 20 May 2005 07:05 am, Wladimir Eremeev wrote:
Dear r-help,
Now I am drawing graphs with xyplot function.
In order to place a legend under the plots I use the key argument in
the xyplot function.
One of the 'key' components is 'divide', which defines a number of
points on
Might it want bryansAtHeaderLevel - to be syntactically complete?
Have you tried wrapping the entire sequence between { and }?
hope this helps.
[EMAIL PROTECTED] wrote:
Hi
I'm generating the following in a file and getting a syntax error:
bryansAtHeaderLevel -
[snip snip snip snip]
How about strict option that could be set to
disallow use of T/F variables?
I had a student run into trouble fairly recently (although can't
at the moment provide a reproducible example using T as a
variable in a formula that was passed to nls() ... I think there
On 5/20/05, Barry Rowlingson [EMAIL PROTECTED] wrote:
Liaw, Andy wrote:
Don't give up to easily: If _ can be done away as assignment operator,
I'd guess anything is fair game...
Even my great dream that R and Python eventually merge into the same
language? R gets Python's syntax and
The statemets ends with '0,)', maybe this is the reason...
BTW, all statements end with the similar symbols.
I have found, that R some times complain on this and sometimes not,
but did not search the reasons.
My R 2.1.0 on win2000 doesn't complain on the statement
bryansAtLineLevel-c(
Hi all,
From a vector, I want to get the unique values and the counts of these
unique values in the vector. For example,
x-c(2 ,1 ,2, 1, 4 ,2 ,1, 4 ,1 ,1)
xu-unique(x)
xn-numeric(length(xu))
for (i in 1:length(xu)) {xn[i]-length(which(x==xu[i]))}
There must be a very much simpler method of doing
Ben Bolker wrote:
[snip snip snip snip]
How about strict option that could be set to
disallow use of T/F variables?
I had a student run into trouble fairly recently (although can't
at the moment provide a reproducible example using T as a
variable in a formula that was passed to nls() ... I
Dear Deepayan,
I suggest something like
pointsGrob(
x=if(key$divide1){(1:key$divide-1)/(key$divide-1)} else 0.5,
[blah-blah-blah]
)
This looks like your 3rd variant.
However, I haven't try very hard to verify my solution.
I tried to redefine the entire function
On Friday 20 May 2005 10:05 am, Wladimir Eremeev wrote:
Dear Deepayan,
I suggest something like
pointsGrob(
x=if(key$divide1){(1:key$divide-1)/(key$divide-1)} else 0.5,
[blah-blah-blah]
)
This looks like your 3rd variant.
However, I haven't try very hard
Anyone know where I can reach the author of the compareGrowthCurves function?
I'm having trouble with it.
Thanks,
Suzie
__
Switch to Netscape Internet Service.
New! Netscape Toolbar for Internet Explorer
Search from anywhere on
Hi,
table should do it.
x-c(2 ,1 ,2, 1, 4 ,2 ,1, 4 ,1 ,1)
table(x)
x
1 2 4
5 3 2
--
Ravi Varadhan, Ph.D.
Assistant Professor, The Center on Aging and Health
Division of Geriatric Medicine and Gerontology
Johns Hopkins
you could use table(), i.e.,
x - c(2, 1, 2, 1, 4, 2, 1, 4, 1, 1)
###
tab - table(x)
xu - as.numeric(names(tab))
xn - as.vector(tab)
xu; xn
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address:
[Barry Rowlingson]
Even my great dream that R and Python eventually merge into the same
language? R gets Python's syntax and Object-oriented functions and
Python gets access to all R's statistical functions?
R is more than a statistical library. I'm coming to R with a strong
Python
DS Yes. It has to do with namespaces. Try ?assignInNamespace
Thank you.
It works.
I have got the desired output (---o---).
--
Best regards
Wladimir Eremeev mailto:[EMAIL PROTECTED]
__
R-help@stat.math.ethz.ch
Hello,
I've got to compute a minimization equation under an equality constraint
(Min g(x1,x2,x3) with x1+x2=const). The Constroptim function does not
authorize an equality condition but only inequality conditions. Which
function can I use instead?
Thank you very much for your help.
Gael Robert -
[EMAIL PROTECTED] wrote:
Anyone know where I can reach the author of the compareGrowthCurves function?
Which package are we talking about? I guess statmod, but please
indicate this!
For sure you have tried the address (in CC) you can find in
library(help=statmod)
Uwe Ligges
I'm having
Dear Ravi,
From a vector, I want to get the unique values and the counts of these
unique values in the vector. For example, x-c(2,1,2,1,4,2,1,4,1,1)
try
hist(x,plot=FALSE,breask=unique(x))$counts
[1] 5 3 0 0 0 2
--
Best regards
Wladimir Eremeev mailto:[EMAIL
Another reason could be, a too long line.
--
Best regards
Wladimir Eremeev mailto:[EMAIL PROTECTED]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
[EMAIL PROTECTED] writes:
Anyone know where I can reach the author of the compareGrowthCurves function?
I'm having trouble with it.
Anything wrong with [EMAIL PROTECTED] (1st hit on Google)?
--
O__ Peter Dalgaard Blegdamsvej 3
c/ /'_ --- Dept. of Biostatistics
On Friday 20 May 2005 17:32, [EMAIL PROTECTED] wrote:
Hello,
I've got to compute a minimization equation under an equality constraint
(Min g(x1,x2,x3) with x1+x2=const). The Constroptim function does not
authorize an equality condition but only inequality conditions. Which
function can I use
Prof Ripley,
I'm aware of R CMD check, but who uses it? Not many regular users, I
presume. As long as T/F are allowed to stand for TRUE/FALSE without
being reserved words, there will be users who will fall in the trap.
As your example shows, some code would have to be manually converted.
Hi all, hope you having a nice day,
I ahve this weird results with identical (probably I am not understanding
correctly what it does ...)
I have these two data frames and I issue :
identical(temp, temp1)
[1] FALSE
However, these data frames are Nx2 and when I issue:
identical(temp[,2],
Why can't you just solve x1 in terms of x2 and plug it in..
ie. min g(const-x2, x2, x3)
Jean
On Fri, 20 May 2005 [EMAIL PROTECTED] wrote:
Hello,
I've got to compute a minimization equation under an equality constraint
(Min g(x1,x2,x3) with x1+x2=const). The Constroptim function does not
?table
On Fri, 20 May 2005, Wladimir Eremeev wrote:
Dear Ravi,
From a vector, I want to get the unique values and the counts of these
unique values in the vector. For example, x-c(2,1,2,1,4,2,1,4,1,1)
try
hist(x,plot=FALSE,breask=unique(x))$counts
[1] 5 3 0 0 0 2
--
Best regards
Are you sure that's what you want to do? The subscript is a logical vector
of length 3, subscripting a 3 x 3 matrix, so you're treating the matrix as a
vector (stacked columns) and recycling the indices. The first iteration
modifies 6 entries of the matrix.
It looks like you want to replace the
[EMAIL PROTECTED] wrote:
Hello,
I've got to compute a minimization equation under an equality constraint
(Min g(x1,x2,x3) with x1+x2=const). The Constroptim function does not
authorize an equality condition but only inequality conditions. Which
function can I use instead?
Hi,
What about trying
sorry everyone
the previous code seems to have been wrong. this is the corrected code
ie the last line
z-matrix(c(1:9),3,3)
top-c(1.5,5.5,9)
for (i in 1:3) z[,i][z[,i]top[i]]-top[i]
/
allan
Huntsinger, Reid wrote:
Are you sure that's what you want to do? The subscript is a logical
d1 - data.frame(x=1:3, y=4:6)
d2 - data.frame(x=1:3, z=4:6)
d3 - data.frame(x=1:3, y=4:6)
identical(d1, d2)
[1] FALSE
identical(d1, d3)
[1] TRUE
Andy
From: Jean Eid
Hi all, hope you having a nice day,
I ahve this weird results with identical (probably I am not
understanding
Jean Eid wrote:
Hi all, hope you having a nice day,
I ahve this weird results with identical (probably I am not understanding
correctly what it does ...)
I have these two data frames and I issue :
identical(temp, temp1)
[1] FALSE
However, these data frames are Nx2 and when I issue:
Jean Eid [EMAIL PROTECTED] writes:
str(temp)
`data.frame': 7072 obs. of 2 variables:
$ pub_id : int 1 1000 10001 10002 10003 10004 10005 10006 10007
$ faminc90: int -2 5998 19900 43000 35000 4 56538 61000 36000 39105
str(temp1)
`data.frame': 7072 obs. of 2 variables:
$
On Fri, 20 May 2005, Jean Eid wrote:
Hi all, hope you having a nice day,
I ahve this weird results with identical (probably I am not understanding
correctly what it does ...)
Why should
a data frame with colunns pub_id faminc90
a data frame with colunns pub_id faminc
be considered
Amir,
Dear All ,
1- I'm trying to access the values of fitted(model) after model-
tune.svm( ) but seemingly it is not poosible. How can I access to
values of fitted ? However ,it is possible only after model- svm( )
tune.svm() is a wrapper to tune() and as such returns a tune-object.
That
You may fit the model using lm() directly - R will set up a coding for
qualitative predictor automatically (taking experiments as qualitative
predictor).
HTH
Wuming
On 5/18/05, [EMAIL PROTECTED] wrote:
Hello sir:
Here's a question on covariance analysis which needs your help.
There're 3
Hi,
my vector V- c(1,0.5,0.06,0.056,0.01,0.04,0.4,0.9,0.82,0.1)
if( V 0.5) { V - 1 - V }
I get a warning saying only the first element will be used in comparing (if V
0.5).
However, my results tell me vis-versa ,it actually compares every element of
the vector V with 0.5 and that is
Try
V - ifelse(V 0.5, 1-V, V)
or
V - pmin(V, 1-V)
On 5/20/05, Jagarlamudi, Choudary [EMAIL PROTECTED] wrote:
Hi,
my vector V- c(1,0.5,0.06,0.056,0.01,0.04,0.4,0.9,0.82,0.1)
if( V 0.5) { V - 1 - V }
I get a warning saying only the first element will be used in comparing (if
Both
V[V 0.5] - 1 - V[V 0.5]
and
ifelse(V0.5, 1-V,V)
should do it.
Ravi.
--
Ravi Varadhan, Ph.D.
Assistant Professor, The Center on Aging and Health
Division of Geriatric Medicine and Gerontology
Johns Hopkins
On 20 May 2005, at 16:37, Philippe Grosjean wrote:
The only aspect I don't like is a too loosely use of the dot in
functions: both in functions names, in object classes and in generic
functions / methods. Hence, we have for instance: 'data.frame',
'help.search' and 'summary.matrix'... just
Hi, do you have any luck in fitting the regression? If so can you share with
me? I appreciate your help.
Kyong
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
Hello,
I am very new to R, and this is certainly and uber-newby question:
I am trying to read a vector of numeric data that contains the log
of daily DJI returns and simply plot a histogram of it.
The data I have is in a text file format, on each line a number
represents the log of the
Dear R Help List,
I have a vector of n and a vector of n-1 and I want to use boot() to
bootstrap the ratio of their respective medians. I want to eventually
use boot.ci() to generate confidence intervals. Because the vectors
are not equal in length, I tried a few things, but have yet to be
Version 1.0-1 of bayesm is now available on CRAN.
This is our first production version which include s much improved
documentation as well as five data sets used in our book, Bayesian Statistics
and Marketing.
peter r
Peter E. Rossi
Joseph T. and Bernice
Alex K wrote:
Hello,
I am very new to R, and this is certainly and uber-newby question:
I am trying to read a vector of numeric data that contains the log
of daily DJI returns and simply plot a histogram of it.
The data I have is in a text file format, on each line a number
represents the
On 5/20/05, Uwe Ligges [EMAIL PROTECTED] wrote:
Alex K wrote:
Hello,
I am very new to R, and this is certainly and uber-newby question:
I am trying to read a vector of numeric data that contains the log
of daily DJI returns and simply plot a histogram of it.
The data I
Matt Oliver wrote:
Dear R Help List,
I have a vector of n and a vector of n-1 and I want to use boot() to
bootstrap the ratio of their respective medians. I want to eventually
use boot.ci() to generate confidence intervals. Because the vectors
are not equal in length, I tried a few things, but
Hi Patrick, thank you for your reply,
On 5/20/05, Patrick Burns [EMAIL PROTECTED] wrote:
Two minor points:
1) You surely have logarithmic returns rather than the log of (some
type of) returns.
Yes, obviously, my mistake.
2) Once you get data suitable for a histogram, do:
You (and the mailing list) would defintely benefit from cliking on:
Help - Manuals - An introduction to R
and spend a few hours in frot of R while reading that.
Bendix
--
Bendix Carstensen
Senior Statistician
Steno Diabetes Center
Niels Steensens Vej 2
DK-2820 Gentofte
Hi,
Is there a way to perform Big-endian / Little-endian byte swap in R?
An ugly way is by using readBin/writeBin:
ByteSwap = function(X, size)
{
writeBin(X, tmp.dat)
readBin(tmp.dat, typeof(X), n = length(x), size=size,
endian=swap)
}
x =
Alex K wrote:
On 5/20/05, Uwe Ligges [EMAIL PROTECTED] wrote:
Alex K wrote:
Hello,
I am very new to R, and this is certainly and uber-newby question:
I am trying to read a vector of numeric data that contains the log
of daily DJI returns and simply plot a histogram of it.
The data I have is
thank you Andy
Simone
Il giorno 20/mag/05, alle 12:37, Liaw, Andy ha scritto:
You have to have the package installed for help.search() to find
things in
it. You could try
RSiteSearch(latent class, restrict=function)
Andy
From: Simone gabbriellini
my help.search didn't give me any result :(
On Friday, May 20, 2005 11:29 AM, Jari Oksanen wrote:
The most beautiful thing in old R (I started with 0.63) was
that it was
in the elegant unix tradition: all lower case and point (full stop,
period, whatever) in places where you needed it. It is
unfortunate that
other languages are
Taylor, Z Todd wrote:
On Friday, May 20, 2005 11:29 AM, Jari Oksanen wrote:
The most beautiful thing in old R (I started with 0.63) was
that it was
in the elegant unix tradition: all lower case and point (full stop,
period, whatever) in places where you needed it. It is
unfortunate that
Has anyone written a function that will print a difftime in the form:
hh:mm:ss
or
yy-mm-dd hh:mm:ss
depending on the actual size.
(sloppy notation for months/minutes, but surely you get the point).
Bendix
--
Bendix Carstensen
Senior Statistician
Steno Diabetes Center
Niels
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