Dear R-Users,
The following question is more of general nature than a merely technical
one. Nevertheless I hope someone get me some answers.
I have been using the mice package to perform the multiple imputations. So
far, everything works fine with the standard regressions analysis.
Dear R-Users,
For example i have a data matrix with five samples and three variables.
DATA - matrix(c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5),nrow=5,ncol=3,byrow=TRUE)
colnames (DATA) - c(V1,V2,V3)
rownames (DATA) - c(S1,S2,S3,S4,S5)
I want to normalize all samples to same sum of variables:
NormFun -
in this case you may use something like the following:
DATA - matrix(1:5, 5, 3)
dimnames(DATA) - list(c(S1,S2,S3,S4,S5), c(V1,V2,V3))
#
DATA / rowSums(DATA)
DATA / rep(colSums(DATA), each = nrow(DATA))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
On 11/29/06, antonio rodriguez [EMAIL PROTECTED] wrote:
Hi,
I'm trying to do a filled.contour plot where some points are labelled as
NA. How do I could plot this kind of graphics, so NA points are coloured
black, keeping the levels of remaining points. NA's values represent
land points
x.fun - function( formula, data ) dotplot( formula, data )
x.grp - function( formula, groups, data ) dotplot( formula, groups, data )
data( barley )
x.fun( variety ~ yield | site, data=barley )
# no problem
dotplot( variety ~ yield | site, groups=year, data=barley )
# no problem
x.grp(
Hi All,
I think i'm failing to undersatnd how aggregate() is supposed to work.
example:
test1-sample(c(0,1),100,replace=T)
test2-sample(letters,100,replace=T)
aggregate(test1,list(test2),sum)
Error in data.frame(w, lapply(y, unlist, use.names = FALSE)) :
arguments imply differing
see nlm or optim
Justin BEM
Elève Ingénieur Statisticien Economiste
BP 294 Yaoundé.
Tél (00237)9597295.
- Message d'origine
De : Wayne Delport [EMAIL PROTECTED]
À : r-help@stat.math.ethz.ch
Envoyé le : Vendredi, 8 Décembre 2006, 8h27mn 44s
Objet : [R] formula format for parameter
Dear all,
I have two variables called c2 and c3 and want to plot these variables in the
same qqnorm-plot with two different symbols or colors to distinguish them so I
can easily compare the variables aginst each other. How can I do in R? I only
manage to do two separated qqnorn-plots.
It does that for me without errors ...
(R 2.3.1 on Mac OSX 10.4.8)
Best, Ingmar
From: Gustaf Rydevik [EMAIL PROTECTED]
Date: Fri, 8 Dec 2006 12:58:01 +0300
To: r-help@stat.math.ethz.ch
Subject: [R] Aggregate?
Hi All,
I think i'm failing to undersatnd how aggregate() is supposed to
try this:
z1 - rnorm(100)
z2 - rt(100, 3)
##
q1 - qqnorm(z1, plot.it = FALSE)
q2 - qqnorm(z2, plot.it = FALSE)
plot(range(q1$x, q2$x), range(q1$y, q2$y), type = n)
points(q1)
points(q2, col = red, pch = 3)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Dear R users,
I’m a graduate students and in my master thesis I must
obtain the values of the parameters x_i which maximize this
Multinomial log–likelihood function
log(n!)-sum_{i=1]^4 log(n_i!)+sum_
{i=1}^4 n_i log(x_i)
under the following constraints:
a) sum_i x_i=1,
x_i=0,
b)
Don't know of a more straight forward way but this works. It constructs
a new call to bwplot from the one to x.grp2 and evaluates it in the
parent environment:
library(lattice)
x.grp2 - function(x, groups, data) {
cl - match.call()
cl[[1]] - as.name(bwplot)
eval.parent(cl)
}
x.grp2(
Dear all R users,
I am wondering if there are any function for Constraint optimization in R.
Especially i am looking for a R - equivalent of fmincon function in
MATLAB.
Thanks and regards,
Arun
[[alternative HTML version deleted]]
__
Dear R-helpers,
I'm for sure not familiar with R, but it seem like a nice sofware tool,
so I've decided to try using it.
Here is my problem I just can't figure out:
I'd like to do least square fit of a straight horizontal (a = 0) line y
= ax + b through some data points
x = (3,4,5,6,7,8)
y =
Hi
look to your workspace by ls(). I bet there is some mismatch in
variables as your example works for me without any error. You
probably redefined sum function.
test1-sample(c(0,1),100,replace=T)
test2-sample(letters,100,replace=T)
aggregate(test1,list(test2),sum)
Group.1 x
1b
Hi all - I'm trying to generate lattice barchart graphs with missing
values, and came across the following:
This does not run. I would expect it to:
library(lattice)
D = data.frame(X=1, Y=factor(letters[2], letters[1:2]))
barchart(~ X, D, groups=Y)
Error in grid.Call.graphics(L_rect, x$x,
Aimin:
1) Please do not spam the r-help list---one request per issue (and two
private mails to the code author) really suffice. Not all contributors
to the R-project are on-line 24/24, and have time to provide immediate
answers.
2) The error occurs because plot.svm() currently does not set valid
If you really want to fit a horizontal line then the best estimate
(meaning least squares) for b is mean(y), regardless of the actual x
values, which becomes clear if you look at your design matrix /
regressor matrix .
In general least squares regression could be done with lsfit(). In your
Try
debug(e1071:::plot.svm)
and then re-run your plot command, stepping through one line at a time
and see where it fails.
Andy
From: Aimin Yan
where is plot.svm method?
I just find plot(svm, data, formula) method
Aimin
__
b = mean(y)
On 08/12/06, Kåre Edvardsen [EMAIL PROTECTED] wrote:
Dear R-helpers,
I'm for sure not familiar with R, but it seem like a nice sofware tool,
so I've decided to try using it.
Here is my problem I just can't figure out:
I'd like to do least square fit of a straight horizontal (a
Hi
from write.csv help page:
x the object to be written, preferably a matrix or data frame. If
not, it is attempted to coerce x to a data frame.
So array is not a kind of object which can be saved as you want
without some complication. Basically it is a plain vector with dim
attributes and
Arun Kumar Saha arun.kumar.saha at gmail.com writes:
Dear all R users,
I am wondering if there are any function for Constraint optimization in R.
Especially i am looking for a R - equivalent of fmincon function in
MATLAB.
Thanks and regards,
Arun
Unfortunately, the built-in
Hi all!
I have lots of functions called in the following pattern
'NameOfFunctionNumber' where the name always stays the same and the number
varies from 1 to 98.
Another function which I run in advance returns the number of the function
which has to be called next.
Now I want to combine
Try using 'get' to return the object specified as a character string:
f1-function()1
f2 - function()2
z - 'f2'
z
[1] f2
get(z)()
[1] 2
On 12/8/06, Katharina Vedovelli [EMAIL PROTECTED] wrote:
Hi all!
I have lots of functions called in the following pattern
'NameOfFunctionNumber'
I'm writing a package that interfaces to the FAME database, via a
library of compiled C routines accessible through a Linux .so file. My
.onLoad() function loads the .so like this:
dyn.load(/opt/fame/timeiq/lib/linux_x86/libjchli.so, local = F)
and after that I also load my own fame.so via
If I understand what you need,
Number=2
x - paste(NameOfFunction,as.character(Number),sep=)
x
[1] NameOfFunction2
And you can use do.call(x, ...) to get your function.
Hope it helps,
Scionforbai
__
R-help@stat.math.ethz.ch mailing list
May be you are also not familiar with statistic. the solution of
min \sum_{i=1}^{n} (y_{i}-b)^{2} is the mean. So the solution is
b-mean(y)
Justin BEM
Elève Ingénieur Statisticien Economiste
BP 294 Yaoundé.
Tél (00237)9597295.
- Message d'origine
De : Kåre Edvardsen [EMAIL
try this:
f1 - function(x) x + 1
f2 - function(x) x + 2
f3 - function(x) x + 3
###
FunNam - f1
eval(call(FunNam, x = 1:5))
FunNam - f2
eval(call(FunNam, x = 1:5))
FunNam - f3
eval(call(FunNam, x = 1:5))
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
On Fri, 2006-12-08 at 14:57 +0100, Katharina Vedovelli wrote:
Hi all!
I have lots of functions called in the following pattern
'NameOfFunctionNumber' where the name always stays the same and the number
varies from 1 to 98.
Another function which I run in advance returns the number of the
Hello,
Due to the continued growth of Mango Solutions, we are now inviting
applications for the following positions:
* Senior R/S Programmer:
http://www.mango-solutions.com/company/jobuk13.html
* R/S Programmer:
http://www.mango-solutions.com/company/jobuk14.html
To view all available
On Dec 8, 2006, at 7:42 AM, David Barron wrote:
b = mean(y)
On 08/12/06, Kåre Edvardsen [EMAIL PROTECTED] wrote:
Dear R-helpers,
I'm for sure not familiar with R, but it seem like a nice sofware
tool,
so I've decided to try using it.
Here is my problem I just can't figure out:
I'd
How does one tell Sweave() to include analysis warning messages in
the verbatim output?
_
Professor Michael Kubovy
University of Virginia
Department of Psychology
USPS: P.O.Box 400400Charlottesville, VA 22904-4400
Parcels:Room 102Gilmer Hall
Dr. PETER MALUBA/CHRIS NISSEN ASSOCIATES
SOLICITORS ADVOCATES
GABORONE.
BOTSWANA.
Hallo,
Mein Name ist Dr. Peter Maluba, bin ein 50 jähriger
Anwalt aus Gaborone, Botswana.
Einer meiner 15 Jährigen Klienten ,ein Deutscher Namens Gunter Haymann,
welcher über 18 Jahre für eine Diamanten
The best approach is probably to load all of your functions into a list:
myfunctions - list()
myfunctions[[1]] - NameOfFunction1
myfunctions[[2]] - NameOfFunction2
...
Or
myfunctions - list()
for (i in 1:98){
+ myfunctions[[i]] - get( paste('NameOfFunction',i,sep='') )
+ }
Then you can
Hello R-Group
I found how to fill the data.frame -
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/70843.html
N1 - rnorm(4)
N2 - rnorm(4)
N3 - rnorm(4)
N4 - rnorm(4)
X1 - LETTERS[1:4]
###
nams - c(paste(N, 1:4, sep = ), X1)
dat - data.frame(lapply(nams, get))
names(dat) - nams
I second Marc's comments below, but for amusement, another alternative to
the (undesirable) eval(call()) construction is:
foo-function(x)x^2
get(foo)(1:5)
[1] 1 4 9 16 25
I believe this is equally undesirable, however, and as Marc said, making
your function a function of two arguments or
Hello every one,
is there an R package that can handle dynamic panel data model aviablable ?
thank you for help
chen
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On Fri, 8 Dec 2006, [EMAIL PROTECTED] wrote:
Dear R users, I??m a graduate students and in my master thesis I must
obtain the values of the parameters x_i which maximize this Multinomial
log??likelihood function log(n!)-sum_{i=1]^4 log(n_i!)+sum_ {i=1}^4 n_i
log(x_i)
under the following
Hello, how do Ito solve a non linear system of equations
in R?
--
Este mensaje ha sido analizado por MailScanner
en busca de virus y otros contenidos peligrosos,
y se considera que está limpio.
__
R-help@stat.math.ethz.ch mailing list
Dear all R users,
I have a optimization problem like this:
f(x,y) is a function with two variables, x, and y. Variable x is unbounded
but y lies between [-10, 10]. I want to minimize f(x,y) subject to a
constraint x + y 5. Can anyone tell me which R function should I use. I
already gone
Hi Gustaf
I'm having the same issue myself. What I've ended up doing is
replacing NA's with a big negative value, define levels as one color
for negative values, and a regular scale above.
How to define 'levels' as one color for negative values and a regular
scale above? I don't know how
I don't understand what you're asking for.
But if your goal is to create N1 through N15 in order to use them to
fill a data frame, then it can be much simpler:
items - 15
VarSize - 10
tmp - matrix(0,nrow=VarSize,ncol=items)
tmp - data.frame(tmp)
names(tmp) - paste('N',seq(items),sep='')
## of
Dear useRs,
calls and results below:
paste(\ \n)
[1] \n
*but*
paste(\ \N)
[1] N
Question: Is that by design? If so, how can I obtain simple LaTeX-type:
[1] \N
version
platform i386-pc-linux-gnu
arch i386
os linux-gnu
system i386, linux-gnu
status
major
thanks, I did get this plot.
Before I have this problem, I did get a plot by my code.
However after I change a little my code. it doesn't work.
It is pity not saving my original code.
Now the question is the plot I get using your code is different from
what I got before.
Moreover I did remember I
On Fri, 8 Dec 2006, Szymon Wlazlowski wrote:
Dear useRs,
calls and results below:
paste(\ \n)
[1] \n
*but*
paste(\ \N)
[1] N
Question: Is that by design? If so, how can I obtain simple LaTeX-type:
[1] \N
FAQ 7.37:
Hello R-Group
I found how to fill the data.frame -
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/70843.html
N1 - rnorm(4)
N2 - rnorm(4)
N3 - rnorm(4)
N4 - rnorm(4)
X1 - LETTERS[1:4]
###
nams - c(paste(N, 1:4, sep = ), X1)
dat - data.frame(lapply(nams, get))
names(dat) - nams
The code bekow works so this is why I didn't include the data to
reproduce it. The loops about 500
times and each time, a zoo object with 1400 rows and 4 columns gets
created. ( the rows represent minutes so each file is one day
worth of data). Inside the loop, I keep rbinding the newly created
I have a data set like this
I want to assign outward to Y if sc 90 and assign inward to Y if sc=90.
then cbind(p1982,Y) to get like these
p aa as ms cur sc Y
1 154l_aa ARG 152.04 108.83 -0.1020140 92.10410 inward
2 154l_aa THR 15.86 28.32 0.2563560 103.67100inward
3 154l_aa ASP 65.13
Using rbind almost always slows things down significantly. You should
define the objects aggfxdata and fullaggfxdata before the loop and then
assign appropriate values to the corresponding rows and/or columns.
Ravi.
ravi : I appreciate your help but could you be a little more specific
about what you mean ? I can just stack
aggfxdata below the current full one ( the rbind works out the ordrering
by date because it's a zoo object )
so it's not a question of where to put the new one. It's a question of
how to
I have a data set like this:
if I want to less than 20 obs from this data set.
How can I do these?
str(p1982)
'data.frame': 465979 obs. of 6 variables:
$ p : Factor w/ 1982 levels 154l_aa,1A0P_aa,..: 1 1 1 1 1 1 1 1 1 1 ...
$ aa : Factor w/ 19 levels ALA,ARG,ASN,..: 2 16 4 5 18 3 19
p1982[sample(nrow(p1982),20),]
On 12/8/06, Aimin Yan [EMAIL PROTECTED] wrote:
I have a data set like this:
if I want to less than 20 obs from this data set.
How can I do these?
str(p1982)
'data.frame': 465979 obs. of 6 variables:
$ p : Factor w/ 1982 levels
Save your intermediate results as a list of matrices.
Then rbind them all at once using do.call.
It looks like this will save 23 seconds (see below), if you are running on
a PC like mine (AMD 2GHz, WinXP ).
But I wonder, if 23 a mere seconds is all you save is this really worth
worrying
I don't know about efficiency, but at least for readability, you may
want to do the following:
1. Indent your code.
2. Create a list of appropriate length, and populate the list with
objects you're creating in the loop.
3. After the loop, use do.call(rbind, list).
HTH,
Andy
From: Leeds, Mark
If p1982 is a data.frame:
p1982$Y - ifelse(p1982$sc90, 'inward', 'outward')
If it is a matrix
p1982 - cbind(p1982, Y=ifelse(p1982[,'sc']90, 'inward', 'outward'))
On 12/8/06, Aimin Yan [EMAIL PROTECTED] wrote:
I have a data set like this
I want to assign outward to Y if sc 90 and assign
Hopefully it is a dataframe or else you matrix will be converted to
character; forgot that when I sent it.
On 12/8/06, jim holtman [EMAIL PROTECTED] wrote:
If p1982 is a data.frame:
p1982$Y - ifelse(p1982$sc90, 'inward', 'outward')
If it is a matrix
p1982 - cbind(p1982,
Consider using a list:
N - list()
for (i in 1:15) N[[paste(N, i, sep='')]] - numeric(10)
N
$N1
[1] 0 0 0 0 0 0 0 0 0 0
$N2
[1] 0 0 0 0 0 0 0 0 0 0
$N3
[1] 0 0 0 0 0 0 0 0 0 0
$N4
[1] 0 0 0 0 0 0 0 0 0 0
$N5
[1] 0 0 0 0 0 0 0 0 0 0
$N6
[1] 0 0 0 0 0 0 0 0 0 0
$N7
[1] 0 0 0 0 0 0 0
I have some data that I need to view in various 3-D clouds. To better see
the cloud structure on a 2-D screen I would like to output a bunch of bmp
files with clouds at slightly different angles, then run them through an
external program to animate them. But I'm having trouble getting cloud()
This is FAQ Q7.22
On Fri, 8 Dec 2006, Eric Peterson wrote:
I have some data that I need to view in various 3-D clouds. To better see
the cloud structure on a 2-D screen I would like to output a bunch of bmp
files with clouds at slightly different angles, then run them through an
external
Something like this may be reasonably efficient. I create a length-500
list of 1400*4 matrices of uniform random numbers.
Farrar
numArrays - 500 # number of arrays
arrDim1 - 1400 # array num. rows
arrDim2 - 4 # array num. cols
arrList - list(numArrays,
Hi, all
How do I run sample R (Linux). I open R, find a prompt an now what?
Thanks
Nuno Vale
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
On 12/8/06, Eric Peterson [EMAIL PROTECTED] wrote:
I have some data that I need to view in various 3-D clouds. To better see
the cloud structure on a 2-D screen I would like to output a bunch of bmp
files with clouds at slightly different angles, then run them through an
external program to
Hello,
When I used spseg function in the spatialkernel package to run Monte
Carlo spatial segregation test, R would not let me run more than 50
simulations. That is, I tried to run the following code,
sp - spseg(pts, bin, hcv, opt=3, ntest=1000, poly=polyb)
where pts was a 116*2 matrix
hi all, I am trying to find some break points in GARCH
model. Is there any function for it? any suggestion is
appreciated!
Thanks
Rick
Cheap talk?
__
An apparatus exists whereby a collection of balls is displaced to the
top of a stack by suction. A top level (Level 1) each ball is shifted
1 unit to the left or 1 unit to the right at random with equal
probability. The ball then drops down to level 2. At Level 2, each
ball is again shifted 1 unit
65 matches
Mail list logo
