what do you mean by 'send the figure to pdf'?
My guess is that this is a Mac-specific question (e.g. you are using the
R.app GUI), so please consider if this is the appropriate list.
On Fri, 16 Mar 2007, Kubovy Michael wrote:
Dear r-helpers,
When I do an xYplot and display the result in a
I'm having a problem with the mfg option of par. Am I making an error in my
usage? Here is a simple example that I thought would plot to the 4 corners
of a 2x2 plot but doesn't plot to the lower right and plots twice on the
upper left.
par(mfrow = c(2, 2))
pos - as.matrix(expand.grid(1:2,
On Friday 16 March 2007 09:36, Delphine Fontaine wrote:
Thanks for your answer which was very helpfull. I have another question:
I have read in this document
(http://cran.r-project.org/doc/manuals/R-intro.pdf) that most of the
programs written in R are ephemeral and that new releases are not
Hi, just to clarify Hadley's points, GGobi is the new XGobi, but GGobi does
NOT require an X server on Windows.
On 3/17/07, hadley wickham [EMAIL PROTECTED] wrote:
I should mention that it's very easy to install rggobi and ggobi on
windows these days. GGobi has a nice installer,
The problem here is that setting par(mfg =) does an implicit par(new=TRUE)
on the next plot (as otherwise it would advance to the next position).
That is going to be confusing if there has been no plot, and that is what
you are seeing: the first plot is done at c(1,1), overriding the setting
Hi,
I am trying to make a legend with four symbols as follows
1.white box
2.black box
3.clear box (same as background)
4.clear box with shading lines
but the shading lines arent showing...
here is my code.
par(bg=lightyellow)
barplot(c(seq(1,6,1)))
legend(8.5,0.3, bty=o,
Hello, does anyone know of an existing toolbox to estimate Markov
Decision Processes in R?
example in MATLAB: http://www.cs.ubc.ca/~murphyk/Software/MDP/mdp.html
-zubin
__
R-help@stat.math.ethz.ch mailing list
On 2007-03-16, [EMAIL PROTECTED] [EMAIL PROTECTED] wrote:
for example:
I have got these data, organized in a dataframe.
sample1 sample2 sample3 sample4 group
replicate11.000.020.350.50A
replicate21.000.021.541.11A
replicate31.00
Hi all,
I've been using the arrows() function in plots a lot, but I'm not
happy with the appearance of the arrow heads. I understand that arrows
() doesn't offer more sophisticated arrowhead shapes like e.g. a
filled triangle, possibly with choice of angle at the point. Does
anyone know an
Peter McMahan [EMAIL PROTECTED] writes:
That's a good point.
What's a good point? [this is why top-posting isn't so helpful].
What's the overhead on digests like that?
Depends on the digest algorithm, the implementation, etc. To some
extent, you can just try it and see. Or you can
One way would be to use the grid function arrow(). Paul Murrell's document on
Integrating Grid Graphics Output
with Base Graphics Output has an example of integrating grid graphics arrows
in base graphics.
There's also an Arrows() function in the package IDPMisc.
Mikkel
Hi all,
I've been
Hello,
I am interested in estimating this type of random effects panel:
y_it = x'_it * beta + u_it + e_it
u_it = rho * u_it-1 + d_itrho belongs to (-1, 1)
where:
u and e are independently normally zero-mean distributed.
d is also independently normally zero-mean distributed.
So, I
Hi Simon,
Try
fill=c(white,dark grey,black,black), density=c(NA,NA,25,75),
etc
Cheers
Andrew
On Sat, Mar 17, 2007 at 12:36:19PM +, Simon Pickett wrote:
Hi,
I am trying to make a legend with four symbols as follows
1.white box
2.black box
3.clear box (same as background)
On Sat, Mar 17, 2007 at 08:12:35PM +0100, Guillermo Villa wrote:
Hello,
I am interested in estimating this type of random effects panel:
y_it = x'_it * beta + u_it + e_it
u_it = rho * u_it-1 + d_itrho belongs to (-1, 1)
where:
u and e are independently normally zero-mean
Mikkel Grum:
I've been using the arrows() function in plots a lot, but I'm not
happy with the appearance of the arrow heads. I understand that
arrows
() doesn't offer more sophisticated arrowhead shapes like e.g. a
filled triangle, possibly with choice of angle at the point. Does
anyone
Dear Hendrik,
Arrows() is the first entry turned up by RSiteSearch(arrows,
restrict=functions), so its effort to hide isn't very successful.
Regards,
John
John Fox
Department of Sociology
McMaster University
Hamilton, Ontario
Canada L8S 4M4
905-525-9140x23604
I'm not sure I'm barking up the right tree here, but would I need to make
use of groups to plot two separate datasets within ONE panel in xyplot? The
desired end result is a single xy plot of two separate (but similar in
values and ranges).
Full code follows, xyplot code at bottom
I have 1 bivarate samples (x1, x2), and I want to estimate the marginal
density of x2. I searched the R manual but couldn't find a function that can do
this job. It seems density only works for single-variate samples. Can anybody
help me with it? Thanks a lot!
Best,
J. Deng
On 17-Mar-07 22:14:54, junjun deng wrote:
I have 1 bivarate samples (x1, x2), and I want to estimate the
marginal density of x2. I searched the R manual but couldn't find a
function that can do this job. It seems density only works for
single-variate samples. Can anybody help me with it?
Hi,
As part of the legend to a plot, I need to have the n in italics
because it is a requirement of the journal I aim to publish in:
This study, n = 3293
Presently I have:
legend(20, 105, This study, n = 3293, pch=1, col=rgb(0,0,0,0.5),
pt.cex=0.3, cex=0.8, bty=n)
I suppose
Hi all - A stupid question here, my apology. I would like to know how can I
flip a vector in R? For example, I have a vector:
a = c(1,2,3)
I would like my vector b to have the following value
b = c(1,2,3)
But what operator I need to put to my original vector 'a' to obtain 'b'? Please
let me
Hi - I'm quite wondering what makes the lag operator does not work for my time
series. I have a time series of length about 20 elements. I would like to
have a lag 1 of this time series. I did the following:
logprice = log(price, base=exp(1))
# this is my log price which is a vector of
On Sat, 2007-03-17 at 22:01 -0400, Chabot Denis wrote:
Hi,
As part of the legend to a plot, I need to have the n in italics
because it is a requirement of the journal I aim to publish in:
This study, n = 3293
Presently I have:
legend(20, 105, This study, n = 3293, pch=1,
On Sun, 2007-03-18 at 02:52 +, [EMAIL PROTECTED] wrote:
Hi all - A stupid question here, my apology. I would like to know how can I
flip a vector in R? For example, I have a vector:
a = c(1,2,3)
I would like my vector b to have the following value
b = c(1,2,3)
I presume you meant:
On Mar 17, 2007, at 10:52 PM, [EMAIL PROTECTED] wrote:
Hi all - A stupid question here, my apology. I would like to know
how can I flip a vector in R? For example, I have a vector:
a = c(1,2,3)
I would like my vector b to have the following value
b = c(1,2,3)
But what operator I need
Hi Thomas,
sadly, the full code is not much help to us in the absence of the
data. Can I suggest that you construct a reproducible worked example
to help explain your question? For what it's worth I suspect that the
answer is that you need to join these datasets into one and theneitehr
use the
It is easier with:
legend('topleft', expression(paste(This study, , italic(n) == 3295)))
On 3/17/07, Marc Schwartz [EMAIL PROTECTED] wrote:
On Sat, 2007-03-17 at 22:01 -0400, Chabot Denis wrote:
Hi,
As part of the legend to a plot, I need to have the n in italics
because it is a
On Sat, 2007-03-17 at 21:56 -0500, Marc Schwartz wrote:
On Sat, 2007-03-17 at 22:01 -0400, Chabot Denis wrote:
Hi,
As part of the legend to a plot, I need to have the n in italics
because it is a requirement of the journal I aim to publish in:
This study, n = 3293
Presently I
What is happening is that by indexing the time series, you are losing the
time series attributes. Here is a quick test that I ran.
x
Time Series:
Start = 1
End = 20
Frequency = 1
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20
y - lag(x,1)
y
Time Series:
Start = 0
End = 19
Thanks for the warning:
Here is the link to the datasets, rather large at 2 and 5 mb. Another note
is that one set has more datapoints than the other, don't know if this can
be done with xyplot.
http://www4.ncsu.edu/~tpcolson/coastcurvfreqs.txt
http://www4.ncsu.edu/~tpcolson/coastslopefreqs.txt
None of Andy's comments) are inconsistent with the point that
rlm() and lqs(), if they disagree with lm(), likely offer better
places to start than does lm(), in identifying points that should
be examined as in some sense outliers. All such methods are
to be used, not as crutches, but as sources
Hi again Thomas,
ah, sorry, I should be more precise. Please construct a reproducible
worked example that does not require us to download 7 Mb of data. You
might also try the suggestions that I made and let us know if they
worked for you.
Cheers
Andrew
On Sat, Mar 17, 2007 at 10:37:46PM
On 3/17/07, Thomas Colson [EMAIL PROTECTED] wrote:
Thanks for the warning:
Here is the link to the datasets, rather large at 2 and 5 mb. Another note
is that one set has more datapoints than the other, don't know if this can
be done with xyplot.
As long as the two datasets have the same
Sorry 'bout that.
Here's about as simple as I can get it:
#First dataset
N - 25
x - round(rnorm(N),2)
y - round(rnorm(N),2)
df - data.frame(x = x, y = y)
#Plot it
xyplot(df$x~df$y,xlab=Test 1 Data,ylab=P(AA*))
#Second Dataset
N - 20
x - round(rnorm(N),2)
y - round(rnorm(N),2)
df - data.frame(x
The make.groups function did the trick. Thank you so much for the seemingly
obvious solution!
piedfac - read.table(C:/R_PLots/piedmontfacfreqs.txt, header=TRUE,
sep=,, na.strings=NA, dec=., strip.white=TRUE)
coastfac - read.table(C:/R_PLots/coastalfacfreqs.txt, header=TRUE,
sep=,,
Try this:
plot(1:10)
legend(topleft, This ~ study ~ italic(n) == 3293)
On 3/17/07, Chabot Denis [EMAIL PROTECTED] wrote:
Hi,
As part of the legend to a plot, I need to have the n in italics
because it is a requirement of the journal I aim to publish in:
This study, n = 3293
Presently I
Much nicer, thanks, Thomas. I've made a small change to make the
differences more obvious for this example.
#First dataset
N - 25
x - round(rnorm(N),2)
y - round(rnorm(N),2)
df.1 - data.frame(x = x, y = y)
#Plot it
xyplot(x~y,xlab=Test 1 Data,ylab=P(AA*), data=df.1)
#Second Dataset
N - 20
x -
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