Benilton Carvalho schrieb:
Well, AFAIK, the definition of a p-value is the probability of
observing something at least as extreme as the observed data.
If you observed z, and Z follows a std-normal
p-value = P( Z -abs(z) ) + P( Z abs(z) )
= 2*P ( Z abs(z) )
= 2*pnorm(z,
I got an answer for the other question (thank you)
But there is another question (I am afraid this is a basic question ...)
In this tread there is a hint hwo to calculate the p-vlue of an GEE:
_http://finzi.psych.upenn.edu/R/Rhelp02a/archive/74150.html_
Then, get the P values using a normal
Benilton Carvalho schrieb:
the recommendation was to use lower.tail=FALSE.
b
O
but then the results are significant and this does not match the
observation.
The results are matching the observations if the formula is
Hi to all,
maybe the last question was not clear enough.
I did not found any hints how to decide whether it should use lower.tail
or not.
As it is an extra R-feature ( written in
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/66250.html )
I do not find anything about it in any statistical books
I did just the download of the pls package, but the NIR dataset is not
available
require(pls)
[1] TRUE
data(NIR)
Warning message:
data set 'NIR' not found in: data(NIR)
is there another package with the dataset for the examples?
With regards Carmen
Prof Brian Ripley schrieb:
On Sat, 16 Dec 2006, R. Villegas wrote:
2006/12/15, Carmen Meier [EMAIL PROTECTED]:
Hello r-group
I have a question to the ks.test.
I would expect different values for less and greater between data1 and
data2.
Does anybody could explain my point
R. Villegas schrieb:
2
data1-c(8,12,43,70)
data2- c(70,43,12,8)
is the same for ks.test, isn't it?
Yes, it's the same. Wich version of R have you?.
2.4.0
Carmen
__
R-help@stat.math.ethz.ch mailing list
Hello r-group
I have a question to the ks.test.
I would expect different values for less and greater between data1 and
data2.
Does anybody could explain my point of misunderstanding the function?
data1-c(8,12,43,70)
data2- c(70,43,12,8)
ks.test(data1,pnorm)
ks.test(data1,pnorm,alternative
Hi to all,
I would like to bind data1 and data2 (both are coming from an Excel
sheet) but only the data rows
using rbind will cause double names and value.
but I need only add the data.rows and the rest of the names and values
should be NA
value.1=c(a,b,c,d,5:54) # building similar
Hi To all,
I found in the tread
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/46740.html
the reply for
/ y - 3 /
/ f - function(x) y /
/ environment(f) - NULL /
/ f(1)
/but this example (R 2.4.0) will cause an error:
The use of the NULL environment is not longer possible (translated)
The
Thanks, a lot
I was not able to find it the hole day ...
Carmen
Phil Spector schrieb:
Carmen -
You certainly can write functions that use ..., but you need
to extract the arguments that the dots represent with list().
Here's a modified version of your function that may help explain
how
Hi to all
I did not found the right hints for functions with the dot-dot-dot argument.
Is it possible to write own functions with the tree dots and if yes
what's wrong with the following example?
test - function(x, ...)
{
print (x)
if (exists(y))print(y)
if (exists(z))print(z)
}
test(4,y=2)
Hi to all
I would to determinate whether bits is a binary code and I would to find
out the which bit is set to 1
bits -00110110
I found to detect whether there are only numbers
all.digits(bits)
but is there any function to detect whether there are only 0 and 1 in
the string
And how could I get
fernando espindola schrieb:
Hi R-user,
I have a problem when try to run the next code:
plot(prueba$IC, type=l)
but plot with type=p, there not problem, I don't know what is the
problem?? Anybody can help me
normally there is no problem with type=l maybe you should send a
Carmen,
Gabor has already given you the detail you ask for, but might try the
following plot to see what is going wrong:
plot(times(tt), x, type='l')
This does not give you the EXACT control of the axis you asked for,
but this simple plot command gives you a fairly nice result. It
Hi to all ... the same code, but another question.
I changed only the type='n' to type='l' and debugged the function xy.coords.
with type = 'l' :
there are the correct values of x and y inside the function xy.coords
but the y value is filled with NA seems that the length is matching now
because
Hi to all,
I have some problems to get the times-scale to the x-axis the times are
coming from an excel sheet f. e
[1] 0:01:00 0:02:00 0:03:00 0:04:00 0:05:00 0:06:00 0:07:00
[8] 0:08:00 0:09:00 0:10:00 0:11:00 0:12:00 0:13:00 0:14:00
[15] 0:15:00 0:16:00 0:17:00 0:18:00 0:19:00 0:20:00 0:21:00
Thank you for your reply Gabor,
sure, the manually written axis works fine in any configuration.
but I would prefer an automatic input.
That means that I would like to use the datafield[1] for the minimum
time and the datafield[max] (means the last one) for the maximum time.
divided into x
Gabor Grothendieck schrieb:
Is the problem how to produce an axis with a given minimum tick,
maximum tick and given number of ticks? In that case try this
yes but ... ;-)
I started with an plain R gui
library(zoo)
library(chron)
# input data
# z is from original example
mn - times(23:00:00)
mx
Gabor Grothendieck schrieb:
My understanding is that the main point of your post was how to get times
on the X axis. hopefully at this point its clear how to do that and
you can
come up with some algorithm to put whatever points you want on.
That´s right thank you
Here is a slight
Yes this one works, but (sorry) in the OP there was a plot without data
to define the range
So I tried to use your working suggestion in that manner:
library(zoo)
library(chron)
time -
c(2:25:00,2:26:00,2:27:00,2:28:00,2:29:00,2:30:00,2:31:00,
Gabor Grothendieck schrieb:
Your code plots x which has nothing to do with xt.
The same result if you change xt to x: 02:25 at the origin nothing else
- I do not know why
#-- your suggestion
mn - times(min_time)
mx - times(max_time)
n - 12
t - times(seq(mn, mx, length =
Gabor Grothendieck schrieb:
Please provide a complete self contained example. I can't follow the
partial code below; however, its likely you are plotting one thing
and creating axes using another so there is no reason it should
come out right.
You are right .. seems to be that it was too
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