Dear R helper,
does anyone have an idea on why R.2.4.0 draws the surface for the two
command lines below and the next time it renders the error message below
for exactly the same command lines:
norm.cop - normalCopula(0.5)
persp(norm.cop, dcopula)
Error in ceiling(length.out) : Non-numeric
Dear R-helpers,
is it some sort of R internal fault or am I doing something wrong when
typing the following two lines in R, I get the surface ploted and trying
it another time it gives the error message below:
Error in ceiling(length.out) : Non-numeric argument to mathematical function
Why is it
Dear R-helper,
Is there any thing that I am doing wrong in the following codes:
norm.cop - normalCopula(0.5)
persp(norm.cop, dcopula)
The last command produces what follows
Error in persp(x, y, z, xlim, ylim, zlim, theta, phi, r, d, scale,
expand, :
invalid 'x' argument
In addition:
Can someone help interprete the error message below? i was trying to
load the package copula from the R command prompt.
Error in loadNamespace(package, c(which.lib.loc, lib.loc), keep.source =
keep.source) :
in 'copula' methods specified for export, but none defined: show,
summary, persp,
Dear r-users,
how can I use the persp or a similar command in R to plot two surfaces
in the same set of axes?
many thanks,
Dominique
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Dear r-users,
Is there any command in R allowing to evaluate a double integral? for
instance let say I want to evaluate the following integral:
integrate[lo=(0,1),up=(2,3)] f(x,y)=x^2+y^2
where lo is the vector of lower bounds and up that of upper bounds.
I thaught the function adapt would work
Dear helpeRs,
I seem to be a little bit confused on the result I am getting from the
few codes below:
u=v=seq(0,1,length=30)
u
[1] 0. 0.03448276 0.06896552 0.10344828 0.13793103 0.17241379
[7] 0.20689655 0.24137931 0.27586207 0.31034483 0.34482759 0.37931034
[13] 0.41379310 0.44827586
