Hi all,
I just compiled package dna v. 0.2 from source and am having some
difficulty with the window argument of the dotmatrix function.
Some test code; say I'm simulating some nucleotide sequences:
sequence1-trunc(runif(200,0,4))
sequence2-trunc(runif(200,0,4))
I embed a nice 100
I'm not sure I understand the question, but you might look into the
following functions:
unique
heatmap
image
Again, if I understand the question, you would create a length(unique
(x)) by length(unique(y)) sized matrix, and fill it with appropriate
values of z. Then pass that to heatmap or
Hi all,
Does anyone know what happened to the dna library or the dotmatrix
function? For the life of me, I can't find it anywhere with the
exception of this reference:
http://rss.acs.unt.edu/Rdoc/library/dna/html/dotmatrix.html
Thanks!
Jeff.
http://www.nd.edu/~jspies/
How about using the cat function to concatenate the constant string
with the dynamic string and then bold the result of that?
--
Jeff Spies
http://www.nd.edu/~jspies/
On Nov 14, 2006, at 4:39 PM, Rene Braeckman wrote:
Thanks for your quick response. This works but the problem is that
I
A couple days ago, Mark Leeds asked about a solution that would
basically stagger two lists, a and b, to return a list in the form of
a[1], b[1], a[2], b[2], a[3] In particular, the summary of his
question was in reference to lists defined by
x - 5
tempin - seq(1,1411, by=30)
a -
Thanks for the responses; and Gunter, I apologize if you feel you
WTFM again in responding.
The two issues that I originally had in understanding why the
operations behaved as they did were in (1) c() reducing an rbind the
way it did, and (2) vector recycling, as Peter mentioned. Issue (1)
Second part: you want to look at the residuals after specifying a
model? Just use the dependent variables in your subsample as the
dependent variables in your regression equation and subtract that
from your outcome variable in your subsample. Might not be the
answer to the question
For OS X, http://dos2unix.darwinports.com/
--
Jeffrey R. Spies
http://www.nd.edu/~jspies/
On Nov 13, 2006, at 11:06 PM, [EMAIL PROTECTED]
[EMAIL PROTECTED] wrote:
Dennis,
You can get rid of the '^M' by reformating the
file from DOS to UNIX. Withing a UNIX system
send the command
What failed for you did not fail for me.
version
_
platform powerpc-apple-darwin7.9.0
arch powerpc
os darwin7.9.0
system powerpc, darwin7.9.0
status
major2
minor2.1
year 2005
month12
day 20
svn rev 36812
language R
Just to help bound the problem,
tempin - seq(1, 1411, by=30)
tempout - array(data=NA, dim=length(tempin)*2)
tempout[seq(1,length(tempin)*2, by=2)]-tempin
tempout[seq(2,length(tempin)*2, by=2)]-tempin+5
Is this what you're looking for?
Jeff.
On Nov 12, 2006, at 5:20 PM, Leeds, Mark (IED) wrote:
I have index ( of a vector )
Funciton form:
everyOther - function(tempin, x){
tempout[seq(1,length(tempin)*2, by=2)]-tempin
tempout[seq(2,length(tempin)*2, by=2)]-tempin+x
tempout
}
Jeff.
On Nov 12, 2006, at 5:31 PM, Jeffrey Robert Spies wrote:
tempin - seq(1, 1411, by=30)
tempout - array(data=NA
[seq(2,length(tempin)*2, by=2)]-tempin+x
tempout
}
Usage: everyOther(seq(1,1411, by=30), 5)
Sorry,
Jeff.
On Nov 12, 2006, at 5:35 PM, Jeffrey Robert Spies wrote:
Funciton form:
everyOther - function(tempin, x){
tempout[seq(1,length(tempin)*2, by=2)]-tempin
tempout[seq(2
Note, the wrapped sort is a really tight solution but won't
necessarily always give you an intertwined array. For example, if
x=31 (or basically, tempin[2] or greater), then you would get 1, 31,
32, etc. instead of 1, 32, 31 Depends on what you were looking for.
Jeff.
On Nov 12,
Much more elegant!
Is there a way, from the documentation, we would know that c() and
lists in general behave as they do in these two lines?
Jeff.
On Nov 12, 2006, at 6:32 PM, Peter Dalgaard wrote:
One way is
c(rbind(tempin,tempin+5))
another is
rep(tempin, each=2) + c(0,5)
If you were trying to use the sep=\t argument, you might have
encountered an error, as there are three tabs one of the two blank
lines at the end of your data file. The default for read.table and
read.delim (as has been suggested by David and Benilton) is
whitespace, which consumes the
As a student, I'll throw my two cents into this discussion. To
preface my opinion, I am in a Joint Ph.D. program in Quantitative
Psychology and Computer Science; I have a significant programming
background and use R (or custom-built software that relies on R in
some way) for the majority
Yep:
?image
Creates a grid of colored or gray-scale rectangles with colors
corresponding to the values in z. This can be used to display three-
dimensional or spatial data aka “images”. This is a generic function.
Hope that helps,
Jeff.
On Oct 30, 2006, at 7:01 PM, Weiwei Shi wrote:
hi,
I would personally use the following method (example using the iris
data included with R):
data(iris)
tSelect - (iris$Sepal.Length 6.0 iris$Sepal.Length 6.2 iris
$Sepal.Width == 3.0)
tSelectedData - iris[tSelect,]
Then you can simply work with tSelectedData for whatever equation
you
Try:
censummary(AsExample$AsLow, AsExample$AsHigh, AsExample$AsCen)
From the Introduction to R (http://cran.r-project.org/doc/manuals/R-
intro.html#Lists-and-data-frames):
Components of lists may also be named, and in this case the
component may be referred to either by giving the component
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