Hi. I'm trying to plot the ratio of used versus unused bird houses
(coded 1 or 0) versus a continuous environmental gradient (proportion of
urban cover [purban2]) that I would like to convert into bins (0 -
0.25, 0.26 - 0.5, 0.51 - 0.75, 0.76 - 1.0) and I'm not having much luck
figuring this
Hi. I'm attempting to fit a logistic/binomial model so I can determine
the influence of landscape on the probability that a box gets used by a
bird. I've looked at a few sources (MASS text, Dalgaard, Fox and
google) and the examples are almost always based on tabular predictor
variables. My
University
Auburn, AL 36849
334-329-9198
FAX 334-844-9234
http://www.auburn.edu/~stratja
Gavin Simpson [EMAIL PROTECTED] 10/13/06 11:23 AM
On Fri, 2006-10-13 at 09:28 -0500, Jeffrey Stratford wrote:
Hi. I'm attempting to fit a logistic/binomial model so I can
I just had a manuscript returned with the biggest problem being the
analysis. Instead of using principal components in a regression I've
been asked to analyze a few variables separately. So that's what I'm
doing.
I pulled a feather from young birds and we quantified certain aspects of
the color
(julian). But | does indicate grouping not nested, correct?
Could someone suggest some coding that might work?
Thanks again,
Jeff
Peter Dalgaard [EMAIL PROTECTED] 10/05/06 7:14 AM
Jeffrey Stratford [EMAIL PROTECTED] writes:
I just had a manuscript returned with the biggest problem being
Harold and list,
I've changed a few things since the last time so I'm really starting
from scratch.
I start with
bbmale - read.csv(c:\\eabl\\2004\\feathers\\male_feathers2.csv,
header=TRUE)
box -factor(box)
chick - factor(chick)
Here's a sample of the data
Hi,
Last week my class conducted an experiment by putting out clay
caterpillars to look at the effects of urbanization, color, and location
on caterpillar predation. There were two sites (urban, rural), three
colors (green, yellow, red) and two locations at each site (edge,
interior). The
for box such as:
rtot.lme - lme(fixed=rtot~sexv, random=~purban2|box,
na.action=na.omit,bb)
or in lmer
lmer(rtot ~ sexv + (purban|box), bb, na.action=na.omit)
Harold
-Original Message-
From: Jeffrey Stratford [mailto:[EMAIL PROTECTED]
Sent: Tue 1/24/2006 8:57 PM
To: Doran
Dear R-users,
I did some more research and I'm still not sure how to set up an ANCOVA
with nestedness. Specifically I'm not sure how to express chicks nested
within boxes. I will be getting Pinheiro Bates (Mixed Effects Models
in S and S-Plus) but it will not arrive for another two weeks from
models in the Matrix package, you would do
lmer(rtot~sex + (purban|box:chick) + (purban|box), na.action=na.omit,
data=bb)
Hope this helps.
Harold
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Jeffrey Stratford
Sent: Tuesday, January 24, 2006 11:34 AM
Dear R-users,
I set up an experiment where I put up bluebird boxes across an
urbanization gradient. I monitored these boxes and at some point I
pulled a feather from a chick and a friend used spectral properties
(rtot, a continuous var) to index chick health. There is an effect of
sex that I
I sent out a question a few days ago asking help with cv.glm and I
didn't get any responses. Is it my question? I'd appreciate any
response just to see my post makes it out there.
What I'm looking to do is to get a column of predicted responses from
cv.glm (leave-one-out). This produces a
Hi folks,
Is there a way to get the predicted values from leave-one-out cross
validation using cv.glm? More generally, is there a way to see what
output is available with any function that may not show up using the
help() function?
Below is the code that I've been using:
SRCOUNT -
Hi. Is there a way to get the values predicted from (leave-one-out)
cv.glm?
It seems like a useful diagnostic to plot observed vs. predicted values.
Thanks,
Jeff
Jeffrey A. Stratford, Ph.D.
Postdoctoral Associate
331 Funchess Hall
Department of
I would appreciate some help writing R code to plot predicted species
richness vs. observed species richness (nat_est) with 95% CI lines.
I'm using glm to get model coefficients and remove-one cross validation
to get predicted (cv.glm).
Here is what I have for the code so far:
SRCOUNT -
R-users,
I'm having some trouble getting .glm and glm.nb to run a polynomial.
I've used x*x and x^2 and neither works. I've checked out the archives
and they refer to an archive that's no longer working.
I've seen that they use poly() but I'm following up my analysis with
cv.glm so I'd
Folks,
Thanks for the help with the hier.part analysis. All the problems
stemmed from an import problem which was solved with file.chose().
Now that I have the variables that I'd like to use I need to run some
GLM models. I think I have that part under control but I'd like to use
a jackknife
Thanks for those on the list that answered my previous question. I'm
just about where I need to be (looking at output).
In the hier.part documentation there is a line env - urbanwq[,2:8].
This means use rows 2 through 8 in the data frame urbanwq, right?
What does the comma represent? If
R-users,
Attached is the file (SR_use2.txt) I'd like to include and includes
column headers. nat_est is the response variable and is the number of
species at a particular point. The other variables are the explanatory
vars (vark, var2, var1, UK, U2, U1, GK, G2, G1, PK, P2, P1).
Here is
Hi, I have no experience with R and I'm finding the manuals a bit obtuse
and written as if I already understood R.
I'm trying to import a csv file from a floppy and it's not working. The
code I'm using is
read.table(F:\GEORGIA\species_richness\SR_use.csv, sep=,, header =
TRUE, row.names = 1)
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