On Thu, Nov 16, 2006 at 02:55:07PM +0100, Massimo Fenati wrote:
Dear colleagues,
Im a new R-help user. Ive read the advertisements about
the good manners and I hope to propose a good question.
Im using R to build an epidemiological SEIR model based
on ODEs. The odesolve package is very
Hi,
I have encountered this problem quite a few times and thought I would
ask.
Let's say that I have two endpoints, a and b, which are integers. If
a = b, I would like to get a:b, but if a b, then numeric(0), for
example:
myseq(3,5) = 3:5
myseq(3,3) = 3
myseq(3,2) = numeric(0)
The operator :
Hi,
I would like to get the piecewise polynomial form of a B-spline basis
(for repeated calculations of the same spline). polySpline gives the
polynomial representation of a particular spline. I wonder if anybody
has code to do that for the basis itself...
Thanks,
Tamas
Hi,
I am sure this has come up before, but my searches of the archive
didn't give any results (maybe I didn't use the right keywords, but if
I use too many, the search times out).
I have a vector of dimensions n, length is not fixed, eg
n - c(4,5,7)
or
n - c(19,4,5,7)
and a function f that
On Wed, Nov 15, 2006 at 01:22:19PM -0500, YONGWAN CHUN wrote:
I work on large matrices and found something interesting. For multiplication
of matrices, the order has a huge influence on computing time when one of
them is a sparse matrix. In the below example, M is a full matrix and A is a
, Nov 14, 2006 at 10:41:39PM -0500, Tamas K Papp wrote:
Hi,
I would like to fit an (interpolating) spline to data where the
derivatives at the endpoints of the interval are nonzero, thus the
natural spline endpoint-specification does not make sense. Books (de
Boor, etc) suggest
Hi,
I would like to fit an (interpolating) spline to data where the
derivatives at the endpoints of the interval are nonzero, thus the
natural spline endpoint-specification does not make sense. Books (de
Boor, etc) suggest that in this case I use not-a-knot splines.
I know what not-a-knot
On Sat, Nov 11, 2006 at 11:19:46AM -0500, [EMAIL PROTECTED] wrote:
kernel1 - function(theta, param) { exp(loglik(theta, param)) + log(1)}
kernel2 - function(theta, param) {( exp(loglik(theta, param)) +
log(1)) * gm(theta, param) }
kernel2(theta0, param0)
adapt(4, lower
On Wed, Nov 08, 2006 at 09:24:38PM -0500, Charilaos Skiadas wrote:
Hi Charilaos,
I would particularly like to hear from people who were not hard-core
programmers before taking up R, so perhaps had originally some
difficulties with it. How hard was it, and how quickly did it start
Hi,
I found some bottlenecks in my R code with Rprof. First I wanted to
rewrite them in C, but a colleague keeps suggesting that I learn
Fortran, so maybe this is the time to do it...
I like to learn new languages and do it fairly quickly. I would
appreciate the advice of others about these
On Wed, Nov 08, 2006 at 09:49:50AM -0800, Spencer Graves wrote:
You say, I have looked at a few spline packages in R, but didn't
find what I was looking for. Could somebody please point me in the
right direction? It's difficult to comment without more information on
what you've tried
Hi,
I am looking for an R package that would calculate multivarite (mostly
2d and 3d, tensor) cubic interpolating splines, so that I could
evaluate these splines (and their derivatives) at many points (unkown
at the time of calculating the spline polynomials) repeatedly.
To make things concrete,
On Sun, Nov 05, 2006 at 11:13:28AM +, Tolga Uzuner wrote:
Dear R Users,
Does anyone know of a package which can generate random realisations of
a double-exponential jump diffusion process with a drift ? Something
where I can specify the likelihoods of an up or a down jump, the drift
Hi Jon,
I missed the original post. If you only care about people being
interviewed/not interviewed, then I would construct a 2x2 markov chain
(the transition matrix has 2 free variables) and simply calculate the
posterior (if you like Bayesian methods). If the interview times are
irregular in
On Sat, Nov 04, 2006 at 05:29:00PM +0100, Martin Maechler wrote:
Your version of SparseM is probably too old and or may not have
been for R 2.3.1.
Do the following
1) Get R 2.4.0 (or even R-2.4.0-patched)
2) upgrade.packages()
^^^
perhaps you meant update.packages()?
Tamas
Hi,
I have searched the archive for the solution of this question, but
couldn't find anything, so I thought I would ask here.
I am using R on a Debian (testing) system. Many of the R packages I
use are installed as .deb packages, those which are not available in
this format I install using
On Fri, Nov 03, 2006 at 07:20:34AM +, Prof Brian Ripley wrote:
but
a - array(list(f),c(2,2))
a[[2,1]]
Thank you very much. Can you please tell me how to make apply
generate arrays like this? Eg if
a - array(1:16,rep(2,4))
then a
apply(a,c(1,2,4), polynomial)
will just give me a
On Fri, Nov 03, 2006 at 02:47:37PM -0800, Waverley wrote:
Hi,
You probably created that matrix from a list. Eg
a - matrix(list(1,2,3,4),2,2)
a
[,1] [,2]
[1,] 13
[2,] 24
a[,2]
[[1]]
[1] 3
[[2]]
[1] 4
b - matrix(1:4,2,2)
b[,2]
[1] 3 4
Both a and b are matrices, but
On Fri, Nov 03, 2006 at 07:59:37PM +0100, rasti matus wrote:
Dears,
how could I convert an existing package to be able to modify it?
Let s say, if I want to change the way how the results of the package are
display (to see the oroginal code of the code).
Hi,
Could you be more specific
Dear R users,
Are there any generic arrays (arrays which can store arbitrary
objects) in R? Something along the lines of
f - function(x) x^2
a - array(f,c(2,2))
etc.
I have found fasp in the spatstat package, but in my particular case,
I need an array of polynomials, not functions. I know
Hi,
I wonder if it would make sense to make uniroot detect zeros at the
endpoints, eg
if f(lower)==0, return lower as the root, else
if f(upper)==0, return upper as the root, else
stop if f(upper)*f(lower) 0 (currently it stops if =), else
proceed to the algorithm proper.
Currently I am using
Hi,
I have a vector which contains the cdf of a univariate distribution.
The support of the rv is [0,1], so eg if the vector has 101 elements,
the give the CDF at 0,0.01,...,1. The function is quite smooth. [1]
I would like to calculate (approximate) the density. I tried fitting
a splinefun
Hi,
I have a matrix A and a vector b, and would like to apply a function
f(a,b) to the rows of A and the elements of b. Eg
A - matrix(1:4,2,2)
b - c(5,7)
f - function(a,b) {sum(a)*b}
myapply(f,A=A,b=b)
would give
(1+3)*5 = 20
(2+4)*7 = 42
I found mapply, but it does not work for matrices.
Hi,
I am approximation a value function (in dynamic programming) V:
R^n-R. In different versions of the problem, n is between 2 and 5.
I would like to use splines to use this, I checked the mailing list
and CRAN but couldn't find anything that would help me (Tps in fields
is too slow, cobs would
Hi,
I have a large table in Postgresql (result of an MCMC simulation, with 1
million rows) and I would like to retrive colums (correspond to variables)
using RODBC. I have a column called index which is used to order rows.
Unfortunately, sqlQuery can't return all the values from a column at
I am using RODBC with Postgresql. I have disabled the log file in
~/.odbc.ini, but nevertheless I still get a logfile in /tmp, which can
grow to gigabytes, so I would like to disable it.
It appears that the logfile is generated by R:
% lsof | grep /tmp/psqlodbc_tpapp7482.log
R 7482
I have a large dataset (about 1 million data points from a
68-dimensional state space, result of an MCMC simulation) which won't
fit in memory. I think that the only solution for analyzing this is
saving it in relational database (when generated) and then reading
back only portions of this data.
I have a matrix r and a scalar d, and I would like to apply the
following functions to each of its elements:
1. if r 0, no change
2. if 0 = r d, replace element by zero
3. if d = r, replace element by r-d
I wrote a small function for this
m - function(b) {sapply(b, function(bb) {
if (bb
On Mon, Aug 08, 2005 at 04:07:10PM +0100, Prof Brian Ripley wrote:
On Mon, 8 Aug 2005, Tamas K Papp wrote:
m - function(b) {sapply(b, function(bb) {
if (bb 0) {bb} else {if (bbd) {bb-d} else 0}
})}
Why use sapply?
r[] - ifelse(r = d, r-d, ifelse(r = 0, 0, r))
is one more
I have a huge matrix on which I need to do a simple (elementwise)
transformation. Two of these matrices cannot fit in the memory, so I cannot
do this in R.
I thought of writing some C code to do this and calling it using .C with
DUP=FALSE. All I need is a simple for loop that replaces elements
On Mon, Aug 08, 2005 at 03:17:44PM -0400, Chuck Cleland wrote:
You might consider one of these approaches instead:
plot(jitter(x), jitter(y))
or
pdf(file=c:/AlphaExample.pdf, version = 1.4)
plot(x, y, col = rgb(1, 0, 0, .2), pch = 16)
dev.off()
sunflowerplot() is also useful for
Is there a way of running BUGS on OS X (from R)? I only see Windows
versions on their website.
If not, what are the alternatives for Bayesian analysis?
Thanks,
Tamas
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On Wed, Sep 15, 2004 at 02:21:18PM -0400, Liaw, Andy wrote:
That's more of a question for the BUGS developers. BUGS is not open source,
so whatever binary is provided, that's all you can use. If I'm not
mistaken, WinBUGS is the only version under development.
I found something called JAGS,
I am an economist who decided it's high time that I learned some
Bayesian statistics. I am following An Introduction to Modern
Bayesian Econometrics by T. Lancaster.
The book recommends using BUGS, but I wonder if there are any
alternatives which are free software and fully integrated to R
On Mon, Sep 13, 2004 at 08:40:15AM -0400, Frank Samuelson wrote:
If anyone has a few extra CPU cycles to spare,
I'd appreciate it if you could verify a problem that I
have encountered. Run the code
below and tell me if it crashes your R before
completion.
library(lme4)
data(bdf)
The fact that as.integer(TRUE) is 1 (and that for FALSE, it gives
zero) is a really nice feature, eg when constructing piecewise
functions (for example, as in -x*(x0)+x*(x=0)) and for many other
things.
Since I haven't found a reference about this, I just wanted to ask
whether this is officialy
Hi,
I would like to make certain portions of axis lines thicker (as Tufte
suggests). How can I draw on axes? I only need a couple of line
segments on the left and bottom one.
Thanks
Tamas
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Dear List,
I have switched from Linux to OS X, and I find the R interface there
really nice. I am using Emacs+ESS, and the quartz device.
My only problem is that
1. I can't move the quartz window, whenever I go above it I see a
spinning rainbow circle (AFAIK that means I am busy or can't
On Sun, Sep 12, 2004 at 01:50:21PM -0400, Tamas K Papp wrote:
1. I can't move the quartz window, whenever I go above it I see a
spinning rainbow circle (AFAIK that means I am busy or can't
touch me in OS X)
2. Once something gets in front of it, I cannot raise it any more.
3. I
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