Hi,
We are looking for a skilled statistician/programmer
seeking a career at the intersection of
finance, applied statistics and computer science.
This position requires a person with a strong background in
- data analysis,
- design and implementation of algorithms,
- software development
-
Hi,
# Dimensions(in characters) of the internal pager.
pgrows = 48
pgcolumns = 128
Thanks, that worked.
Regards,
John.
-Original Message-
From: talepanda [mailto:[EMAIL PROTECTED]
Sent: 06 February 2007 06:37
To: Gavin, John
Cc: R-help@stat.math.ethz.ch
Subject: Re: [R]
Hi,
Using the Rconsole file I can specify the size and location of the Rgui
windows on NT.
e.g.
# Dimensions (in characters) of the console.
rows = 51
columns = 100
How can I specify the size of the help windows that popups
when I ask for help? e.g. '?help'
I would like the popup window to
Hi,
(I addressed the JRI issues I had in my previous email below
http://article.gmane.org/gmane.comp.lang.r.general/70322
by working with the precompiled version of JRI
that is part of the rJava package.)
So I can now run the JRI examples as expected but am having difficulty
getting the Rengine
Hi,
I want to call R from within Java, using jri as per
http://www.rosuda.org/software/jri/
So I am following the instructions in the README file for JRI 0.2-4.
I have run 'sh configure.win' and 'make' and they seemed to be
successful.
(See below for the output from make, for example.)
But when
Hi Deepayan,
You will need to do it manually, e.g.:
xyplot(value ~ date, data = x,
panel = function(x, y, subscripts, ...) {
panel.grid(h = -1, v = 0, col = grey, lwd = 1, lty = 1)
panel.abline(v = as.Date(c(2005/01/01, 2006/01/01)),
Hi,
I have a basic question about aligning date labels for the x-axis
in an xyplot so that they align with the grid lines
from the panel.grid argument.
For example, with
x - data.frame(
date = seq(as.Date(2005/01/01), as.Date(2006/06/01),
length.out = 20), value = runif(20))
xyplot(value ~
Hi,
On a new pc, I am trying to 'CHECK' an R package
containing only R code but the process is hanging and I cant see why.
The 00check.log file shows
* using log directory 'c:/temp/opRisk.Rcheck'
* using R version 2.2.1, 2005-12-20
* checking for file 'opRisk/DESCRIPTION' ... OK
* this is
Hi Patrick/Jeff,
Does
t(apply(z, 1, sort, na.last=TRUE))
do what you want?
Not quite.
t(apply(z, 1, sort, na.last=TRUE))
[,1] [,2] [,3]
[1,]11 NA
[2,]11 NA
[3,]11 NA
[4,]1 NA NA
[5,]1 NA NA
[6,] NA NA NA
Row 2 is the problem.
I
Hi Patrick,
Yes, that works. Thanks for your time.
Regards,
John.
-Original Message-
From: Patrick Burns [mailto:[EMAIL PROTECTED]
Sent: 28 February 2006 10:28
To: Gavin, John
Cc: [EMAIL PROTECTED]; r-help@stat.math.ethz.ch
Subject: Re: [R] elements in each row of a matrix to the
Hi,
Given a matrix like
(z - matrix(c(
1, 1, NA, NA, NA, NA,
1, NA, 1, NA, 1, NA,
NA, 1, 1, 1, NA, NA), ncol = 3))
[,1] [,2] [,3]
[1,]11 NA
[2,]1 NA1
[3,] NA11
[4,] NA NA1
[5,] NA1 NA
[6,] NA NA NA
is there a vectorised way to
Gavin john.gavin at ubs.com,
Quantitative Risk Models and Statistics,
UBS Investment Bank, 6th floor,
100 Liverpool St., London EC2M 2RH, UK.
Phone +44 (0) 207 567 4289
Fax +44 (0) 207 568 5352
Visit our website at http://www.ubs.com
This message contains confidential information and is intend
files and Bill Venables' R-news article (June 2002),
I have tried various permutations with substitute without success.
e.g.
do.call(substitute, list(fun, list(a = as.name(x), b = as.name(y
Regards,
John.
John Gavin john.gavin at ubs.com,
Quantitative Risk Models and Statistics,
UBS Investment
(a = as.name(x), b = as.name(y
Regards,
John.
John Gavin john.gavin at ubs.com,
Quantitative Risk Models and Statistics,
UBS Investment Bank, 6th floor,
100 Liverpool St., London EC2M 2RH, UK.
Phone +44 (0) 207 567 4289
Fax +44 (0) 207 568 5352
Visit our website at http://www.ubs.com
like:
long column \\
Column heading \\
Heading with\\
spaces \\
What is the best way to do this or something similar?
I am on XP with R 1.9.1 (using XEmacs and ESS).
Regards,
John.
John Gavin john.gavin at ubs.com,
Quantitative Risk Models and Statistics,
UBS
Hi,
The solution to my problem is to use
lattice:::calculateAxisComponents to calculate appropriate labels
for the time axis in trellis plots.
# For example, given
x - seq.POSIXt(strptime(2003/01/01, format = %Y/%m/%d),
strptime(2003/10/01, format = %Y/%m/%d), by = month)
y -
Hi,
V1.8.0 seems to allow DateTimeClasses as the x argument in xyplots (lattice).
For example:
x - seq.POSIXt(strptime(2003/01/01, format = %Y/%m/%d),
strptime(2003/10/01, format = %Y/%m/%d), by = month)
y - rnorm(length(x))
dat - data.frame(x= x, y = y)
xyplot(y ~ x, data = dat,
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