Hi,
I am trying to use sub, regexpr on expressions like
log(D) ~ log(N)+I(log(N)^2)+log(t)
being a model specification.
The aim is to produce:
ln D ~ ln N + ln^2 N + ln t
The variable names N, t may change, the number of terms too.
I succeded only partially, help on regular
Note that [:alpha:] is a pre-defined character class and should only be
used inside []. And metacharacters need to be quoted. See ?regexp.
f - log(D) ~ log(N)+I(log(N)^2)+log(t)
f1 - deparse(f)
f1
[1] log(D) ~ log(N) + I(log(N)^2) + log(t)
Now we have a string.
(f2 - gsub(I\\((.*)\\) ,
Hello,
Here is what I got after playing a little bit with your problem:
# First of all, if you prefer 'ln' instead of 'log', why not to define:
ln - function(x) log(x)
ln2 - function(x) log(x)^2
ln3 - function(x) log(x)^3
ln4 - function(x) log(x)^4
# ... as many function as powers you need
#
There are some interactive regex tools around. I use a python one
sometimes. You just then have to be careful re escaping and the style
of regular expressions used in the tool you worked with and the target
environment.
Christian Hoffmann wrote:
Hi,
I am trying to use sub, regexpr on
In this post:
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/30590.html
Thomas Lumley provided a function to traverse a formula recursively.
We can modify it as shown to transform ln(m)^n to ln^n(m) producing
proc2. We then bundle everything up into proc3 which uses substitute
to
Dear all,
I am struggling with the use of regular expression. I got
as.character(test$sample.id)
[1] 1.11 10.11 11.11 113.31 114.2 114.3 114.8
and need
[1] 11 11 11 31 2 3 8
I.e. remove everything before the . .
TIA,
Bernd
__
x - scan(clipboard, what=)
Read 7 items
x
[1] 1.11 10.11 11.11 113.31 114.2 114.3 114.8
gsub([0-9]*\\., , x)
[1] 11 11 11 31 2 3 8
Bernd Weiss wrote:
Dear all,
I am struggling with the use of regular expression. I got
as.character(test$sample.id)
[1] 1.11 10.11
One solution is
test - c(1.11,10.11,11.11,113.31,114.2,114.3)
id - unlist(lapply(strsplit(test,[.]),function(x) {x[2]}))
-Original Message-
From: Bernd Weiss [mailto:[EMAIL PROTECTED]
Sent: Thursday, August 18, 2005 12:10 PM
To: r-help@stat.math.ethz.ch
Subject: [R] Regular
Bernd Weiss bernd.weiss at uni-koeln.de writes:
I am struggling with the use of regular expression. I got
as.character(test$sample.id)
[1] 1.11 10.11 11.11 113.31 114.2 114.3 114.8
and need
[1] 11 11 11 31 2 3 8
I.e. remove everything before the . .
Define the dot as
Dirk Eddelbuettel [EMAIL PROTECTED] writes:
Bernd Weiss bernd.weiss at uni-koeln.de writes:
I am struggling with the use of regular expression. I got
as.character(test$sample.id)
[1] 1.11 10.11 11.11 113.31 114.2 114.3 114.8
and need
[1] 11 11 11 31 2 3 8
On 18 Aug 2005 at 21:17, Peter Dalgaard wrote:
Dirk Eddelbuettel [EMAIL PROTECTED] writes:
Bernd Weiss bernd.weiss at uni-koeln.de writes:
I am struggling with the use of regular expression. I got
as.character(test$sample.id)
[1] 1.11 10.11 11.11 113.31 114.2 114.3 114.8
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