Hi Sebastian,
Your equations can be easily solved - no programming
is required!
Let's number you equations:
(1) 0.007= 2VZ
(2) 0.03= W(Y+Z)
(3) 0.034= X(y+Z)
(4) 0.013 = (X+W)Y +(X-W)Z
(5) X = W+V
Substitute (5) into (3) and then divide (2) by (3) to
get
(W+V)/W = 0.034/0.03
so that
(6) V = (
Try brute force:
> f <- function(x) {
+ V <- x[1]; W <- x[2]; X <- x[3]; Y <- x[4]; Z <- x[5]
+ if (!(V < W && W < X && Y < Z)) return(Inf)
+ ((0.007 - 2*V*Z)^2 +
+ (0.03 - W*(Y+Z))^2 +
+ (0.034 - X*(Y+Z))^2 +
+ (X - W+V)^2 +
+ (0.013 - (X+W)*Y +(X-W)*Z))^2
+ }
> s <- 1:10/10
> g <- expand.grid(V
Hello,
I have a system of five equations to solve with five 'unknows'(V, W, X,
Y and Z) and constraints. The equations are:
0.007= 2VZ
0.03= W(Y+Z)
0.034= X(y+Z)
0.013 = (X+W)Y +(X-W)Z
X = W+V
Constraints:
0https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.
It is probably very well explained in a basic math book which you either
own or can borrow at many libraries.
The method is called substitution and you most probably dont get much
help or insight from R.
If it is a linear equation system with more unknowns use the function
'solve' which you wo
Hi everyone,
I need your help to use R to solve two equations with two unknown variables=
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