I have two factors l1, l2, and I'd like to merge them.
(Remark: The factors can not be converted to charaters)
Function c() does not give me the result I want:
l1 = factor(c('', ''))
l2 = factor(c('ccc', 'dd'))
lMerge = factor(c(l1, l2))
lMerge
[1] 1 2 1 2
Levels: 1 2
I'd
What about the following:
F1 - factor(c(b, a))
F2 - factor(c(c, b))
k1 - length(F1)
k2 - length(F2)
F12.lvls - unique(c(levels(F1), levels(F2)))
F. - factor(rep(F12.lvls[1], k1+k1), levels=F12.lvls)
F.[1:k1] - F1
F.[-(1:k1)] - F2
F.
[1] b a c b
Levels: a b c
This saves
How about simply
F1 - factor(c(b, a))
F2 - factor(c(c, b))
F3 - factor(c(levels(F1)[F1], levels(F2)[F2]))
-sundar
Spencer Graves wrote:
What about the following:
F1 - factor(c(b, a))
F2 - factor(c(c, b))
k1 - length(F1)
k2 - length(F2)
F12.lvls - unique(c(levels(F1), levels(F2)))
Spencer Graves [EMAIL PROTECTED] writes:
Sundar: Your solution is not only more elegant than mine, it's
also faster, at least with this tiny example: start.time -
proc.time()
k1 - length(F1)
k2 - length(F2)
F12.lvls - unique(c(levels(F1), levels(F2)))
F. -
Thanks, Peter.
So Sundar's more elegant solution is equivalent to my initial
response to this question -- which shows how much one can lose trying to
be too clever.
Best Wishes,
spencer graves
Peter Dalgaard wrote:
Spencer Graves [EMAIL PROTECTED] writes:
