Try drop=FALSE:
> x
out pred1 predd2
1 1 2.03.0
2 2 3.55.5
3 3 5.5 11.0
> x[,1]
[1] 1 2 3
> data.frame(x[,1])
x...1.
1 1
2 2
3 3
> data.frame(x[,1, drop=FALSE])
out
1 1
2 2
3 3
>
On 9/4/07, Stan Hopkins <[EMAIL PROTECTED]> wrote:
> Not sure why th
Not sure why the data.frame function does not capture the name of the column
field when its being built with only one column.
Can anyone help?
> data
out pred1 predd2
1 1 2.03.0
2 2 3.55.5
3 3 5.5 11.0
> data1=data.frame(data[,1])
> data1
data...1.
1 1
2
Is this close to what you want? 'var' was not defined for row.names.
> M <- matrix(scan(textConnection(x)), ncol=3, byrow=TRUE)
Read 63 items
> dm <- ncol(M)
> v <- vector()
> t <- 1
> while (dm > 0) {
+ v <- c(v,paste("Rép",t,sep=""))
+ t <- t + 1
+ dm <- dm - 1
+ }
> df <- as.data.frame(M)
>
If M is the original matrix,
k <- as.data.frame(M)
names(k) <- paste("Rép",1:ncol(k),sep="")
rownames(k) <- paste("Col",1:nrow(k),sep="") # replace by what you want
k
On 6/18/07, elyakhlifi mustapha <[EMAIL PROTECTED]> wrote:
>
> hello,
> I'm trying to write a function which take a matrix and g
On 6/18/07, Robin Hankin <[EMAIL PROTECTED]> wrote:
>
>
> I think the questioner was looking for row() and col(), which (IMO) are
> difficult to find if you don't know of their existence.
Searching for "R matrix number of rows columns" in google returns, in fourth
position, the manual page for '
hello,
I'm trying to write a function which take a matrix and give a dataframe with
column names and row names but the problem I meet it's that the column number
is changing and the vector containing the column names is also changing how can
I do to write a good progam for the moment I tryied li
On 18 Jun 2007, at 14:16, Adaikalavan Ramasamy wrote:
> See help(dim) and please read the manuals before asking basic
> questions
> like this. Thank you.
>
I think the questioner was looking for row() and col(), which (IMO) are
difficult to find if you don't know of their existence.
[as ind
On 6/18/07, elyakhlifi mustapha <[EMAIL PROTECTED]> wrote:
>
> hello,
> are there functions giving the columns number and the rows number of a
> matrix?
Yes, there are.
Are you trying to use R without reading *any* documentation???
The mailing list is not a substitute for the manuals.
See the Po
See help(dim) and please read the manuals before asking basic questions
like this. Thank you.
elyakhlifi mustapha wrote:
> hello,
> are there functions giving the columns number and the rows number of a matrix?
> thanks.
>
>
>
> __
hello,
are there functions giving the columns number and the rows number of a matrix?
thanks.
_
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.c
Yes, the problem I have is finding away to get rid of the extra levels I do
not need in the subset.
What Don posted works for my needs. I will also read up on factors/levels.
Thanks for all suggestions and sorry my example had and error (x2 was
supposed to y).
Michelle
On 6/16/07, Don MacQueen
I too have no idea what the object named "x2" is, or where it came
from. Particularly since after your use of subset(), the new
dataframe, y, *does* include a row where V2 = 'color'.
But I have a guess at what your problem may be.
In your original dataframe ("x") the first and second columns ar
Not sure what 'x2' is that you are plotting; it is not defined.
read.delimand subset return dataframes, so you don't need
data.frame.
Here is something that does work:
> x <- "shirt,size,40
+ shirt,color,10
+ shirt,length,10
+ shirt,brand, 1
+ shoes,style,5
+ shoes,brand,4
+ shoes,color,1"
> x <-
I have read the R online help and wiki and I cannot seem to get something to
work the way I need it to.
I want to create a new data frame from an subset of an existing data frame
which has no reference to the original superset. If you following this
example, what I am trying to do may make more s
'table()' can compute your desired result in this particular case
(though I don't know if it's what you want in general):
> y <- factor(c("a","b","c")[c(1,1,1,2,2,3,3,3)])
> x <- factor(c("x","y","z")[c(1,2,3,1,2,1,2,3)])
> table(x, y)
y
x a b c
x 1 1 1
y 1 1 1
z 1 0 1
>
If x
Dear R-users,
I have a little problem that I can't solve by myself.
I have a data frame with 2 factors and 8 observations (see the following
code):
y <- c(1,1,1,2,2,3,3,3)
y <- factor(y)
levels(y) <- c("a","b","c")
x <- c(1,2,3,1,2,1,2,3)
x <- factor(x)
levels(x) <- c("x","y","z")
X <- dat
> "Lauri" == Lauri Nikkinen <[EMAIL PROTECTED]>
> on Fri, 9 Feb 2007 14:21:26 +0200 writes:
Lauri> This still does not solve the issue that when I print in R console I
get
Lauri> columns that don't fit in the window underneath each other. Thanks
anyway!
But Brian did give y
Hi,
This still does not solve the issue that when I print in R console I get
columns that don't fit in the window underneath each other. Thanks anyway!
-Lauri
2007/2/9, Martin Maechler <[EMAIL PROTECTED]>:
>
> > "Petr" == Petr Pikal <[EMAIL PROTECTED]>
> > on Fri, 09 Feb 2007 09:42:
> "Petr" == Petr Pikal <[EMAIL PROTECTED]>
> on Fri, 09 Feb 2007 09:42:13 +0100 writes:
Petr> Hi
Petr> On 9 Feb 2007 at 10:17, Lauri Nikkinen wrote:
>> Thank you for your answer. When I set options(width=250) I still get
>> the same result when I print the data.frame o
kinen wrote:
>
> Date sent: Fri, 9 Feb 2007 10:17:48 +0200
> From: "Lauri Nikkinen" <[EMAIL PROTECTED]>
> To: "Prof Brian Ripley" <[EMAIL PROTECTED]>
> Copies to: r-help@stat.math.ethz.ch
> Sub
r-help@stat.math.ethz.ch
Subject: Re: [R] Data.frame columns in R console
> Thank you for your answer. When I set options(width=250) I still get
> the same result when I print the data.frame on my Rgui console (R
> 2.4.1, Windows XP). Colums become underneath each other. I also get a
On Fri, 9 Feb 2007, Lauri Nikkinen wrote:
> Thank you for your answer. When I set options(width=250) I still get the
> same result when I print the data.frame on my Rgui console (R 2.4.1, Windows
> XP). Colums become underneath each other. I also get an error (?) message [
> reached getOption("max
Thank you for your answer. When I set options(width=250) I still get the
same result when I print the data.frame on my Rgui console (R 2.4.1, Windows
XP). Colums become underneath each other. I also get an error (?) message [
reached getOption("max.print") -- omitted 3462 rows ]]. For example if I
?options, look for 'width'.
I don't know what OS this in: the Windows Rgui has an option to set the
width to the width of the console, but you can override it.
On Thu, 8 Feb 2007, Lauri Nikkinen wrote:
> Hi R-users,
>
>
>
> A newbie question: assume that I have for example 30 columns in my
> dat
Hi R-users,
A newbie question: assume that I have for example 30 columns in my
data.frame named DF. When I print DF in R console I get columns that don't
fit on the same row underneath each other. So how do I change the R console
preferences so that the console does not wrap my data.frame column
Try this:
DF[unlist(tapply(rownames(DF), DF$id, function(x) c(x, x[1]))),]
On 8/9/06, Leonardo Lami <[EMAIL PROTECTED]> wrote:
> Hi all,
> I have a simple question:
> I have a data.frame like this:
>
> id x y
> 1 50 1647685 4815259
> 2 50 1647546 4815196
> 3 50 1647454 4815294
>
---Messaggio originale-
>Da: [EMAIL PROTECTED]
>[mailto:[EMAIL PROTECTED] conto di Leonardo Lami
>Inviato: 09 August, 2006 15:33
>A: r-help@stat.math.ethz.ch
>Oggetto: [R] data.frame to shape
>
>
>Hi all,
>I have a simple question:
>I h
Hi all,
I have a simple question:
I have a data.frame like this:
id x y
1 50 1647685 4815259
2 50 1647546 4815196
3 50 1647454 4815294
4 50 1647405 4815347
5 50 1647292 4815552
6 50 1647737 4815410
7 74 1647555 4815201
8 74 1647464 4815023
9 74 1646970 4815129
10 74 1646895 481
Hi there,
I just saw your question on the help list and tough you could help me with
some start-up info
I just downloaded the R project software to try running SEM analysis and I
also downloaded the SEM package. But it just sits there on the desktop and R
does not know where it is...I can¹t
Sara,
You didn't read your data into R correctly.
If your data are really in the form you posted (one long column
of mixed data types and lots of blank lines), then I would:
1. remove the blank lines with my text editor and save (say, mydata.txt)
2. scan() the variable names into a vector
nm
3)
I wonder how did you created your arguments?
HTH
Petr
On 24 May 2006 at 13:05, Sara Mouro wrote:
From: "Sara Mouro" <[EMAIL PROTECTED]>
To:
Date sent: Wed, 24 May 2006 13:05:45 +0100
Subject:[R] data.frame
>
Dear all,
Does any one knows why should I get the following error message, when trying
to do a simple data.frame??
DataF<-data.frame(Subject,BiomR,Spp,Capas,Litter,Herbs,LitterD,MaxCanH,DDifS
p,DSSp,Slope, CanDens,NearestSp)
Erro em data.frame(Subject, BiomR, Spp, Capas, Litter, Herbs,
On Tuesday April 4 2006 21:56, Gabor Grothendieck wrote:
> Try this:
> dd <- read.table(myfile, as.is = TRUE)
> lst <- as.list(dd[,2])
> names(lst) <- dd[,1]
> lst$title
This (almost) works. I did this instead:
p = read.delim("params.txt", as.is=T)
lst = as.list(p[ ,1])
names(lst) = rownames(p)
Larry Howe <[EMAIL PROTECTED]> wants to:
> 1. read in a 2-column data file, e.g.
> status new
> db green
> title "Most Significant Excursions"
> 2. end up with an R list such that I can write e.g.
> lst$title
> and have R return "Most Significant Excursions".
I call this "reading a hash table"
You might want to consider the use of 'attr' to assign attributes to an
object. That way you can keep your object as a data.frame:
> attr(x,"title") <- "Most Significant"
> attr(x,"title")
[1] "Most Significant"
On 4/4/06, Larry Howe <[EMAIL PROTECTED]> wrote:
>
> Hi,
>
> I'm new to R, and I'm
Try this:
dd <- read.table(myfile, as.is = TRUE)
lst <- as.list(dd[,2])
names(lst) <- dd[,1]
lst$title
For a data frame (but not for a matrix) the names are the same
as the colnames and dimnames is a two-element list
consisting of the rownames and colnames. Try this:
DF <- data.frame(A = 1:5, B
Hi,
I'm new to R, and I'm not a statistician (stunned silence). I am trying to do
the following:
1. read in a 2-column data file, e.g.
status new
db green
title "Most Significant Excursions"
2. end up with an R list such that I can write e.g.
lst$title
and have R return "Most Signifi
---
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Peter
Dalgaard
Sent: 08 December 2005 18:57
To: Matthew Dowle
Cc: 'r-help@stat.math.ethz.ch'
Subject: Re: [R] data.frame() size
Matthew Dowle <[EMAIL PROTECTED]> writes:
> Hi,
>
> In the example below wh
Matthew Dowle <[EMAIL PROTECTED]> writes:
> Hi,
>
> In the example below why is d 10 times bigger than m, according to
> object.size ? It also takes around 10 times as long to create, which fits
> with object.size() being truthful. gcinfo(TRUE) also indicates a great deal
> more garbage collecto
Hi,
In the example below why is d 10 times bigger than m, according to
object.size ? It also takes around 10 times as long to create, which fits
with object.size() being truthful. gcinfo(TRUE) also indicates a great deal
more garbage collector activity caused by data.frame() than matrix().
$ R
"'r-help@stat.math.ethz.ch'"
Date sent: Thu, 27 Oct 2005 08:47:45 +0200
Subject:Re: [R] data.frame-question]
> First a general comment on posting style, could you please be more
> specific about where the error occurs as without this it is ver
minor2.0
year 2005
month10
day 06
svn rev 35749
language R
-Original Message-
From: Michael Graber [mailto:[EMAIL PROTECTED]
Sent: 27 October 2005 12:43 AM
To: [EMAIL PROTECTED]
Subject: Re: Re:
9:45 PM
To: R-Mailingliste
Subject: [R] data.frame-question
Dear R-List,
I am very new to R and programming itself, so my question may be easy to
answer for you.
I tried a lot and read through the manuals, but I still have the following
problem:
I have 2 data-frames:
Number<-as.numeric (Number)
N
Mailingliste
> Subject: [R] data.frame-question
>
>
> Dear R-List,
> I am very new to R and programming itself, so my question may
> be easy to
> answer for you.
> I tried a lot and read through the manuals, but I still have the
> following problem:
> I have 2 data-fr
Dear R-List,
I am very new to R and programming itself, so my question may be easy to
answer for you.
I tried a lot and read through the manuals, but I still have the
following problem:
I have 2 data-frames:
Number<-as.numeric (Number)
Name<-as.character (Name)
TAB1<-data.frame (Name,Number)
- it
mcmaster.ca/jfox/sem-package.pdf>.
I hope this helps,
John
John Fox
Department of Sociology
McMaster University
Hamilton, Ontario
Canada L8S 4M4
905-525-9140x23604
http://socserv.mcmaster.ca/jfox
> -----Original Message
I am trying to use sem to measure effective connectivity among four
brain regions. I have pasted the code that I am trying to run since
that seems easier than trying to come up with another example.
The input data is time series data taken from SPM; they are each
1x121 columns of numbers.
Suzanne Witt wrote:
> I keep getting this error when I try to use the sem package. I and
> another person who has successfully used the sem package for similar
> analysis (fMRI effective connectivity) cannot figure out what is
> wrong with my code. I would appreciate any suggestions.
It i
I keep getting this error when I try to use the sem package. I and
another person who has successfully used the sem package for similar
analysis (fMRI effective connectivity) cannot figure out what is
wrong with my code. I would appreciate any suggestions.
The error message:
Error in data
Here is one minor improvement -- it does not overwrite the input:
replace(d,,as.matrix(d))
On 6/10/05, Muhammad Subianto <[EMAIL PROTECTED]> wrote:
> Dear all,
> Thank you very much for your help.
> I would like to thank Andy Liaw and Gabor Grothendieck for their fast help.
>
> Regards,
> Muha
Dear all,
Thank you very much for your help.
I would like to thank Andy Liaw and Gabor Grothendieck for their fast help.
Regards,
Muhammad Subianto
On this day 6/10/2005 2:30 PM, Liaw, Andy wrote:
> Is this what you want?
>
>
>>d[] <- lapply(d, as.character)
>>str(d)
>
> `data.frame': 10
On 6/10/05, Muhammad Subianto <[EMAIL PROTECTED]> wrote:
> Hi,
> Excuse me for this simple question.
> How to convert as.data.frame to as.character?
>
> ?data.frame
>
> > L3 <- LETTERS[1:3]
> > L10 <- LETTERS[1:10]
> > d <- data.frame(cbind(x=c("XYZ"), y=L10), fac=sample(L3, 10, repl=TRUE))
Is this what you want?
> d[] <- lapply(d, as.character)
> str(d)
`data.frame': 10 obs. of 3 variables:
$ x : chr "XYZ" "XYZ" "XYZ" "XYZ" ...
$ y : chr "A" "B" "C" "D" ...
$ fac: chr "B" "A" "C" "B" ...
Andy
> From: Muhammad Subianto
>
> Hi,
> Excuse me for this simple question.
> How
Hi,
Excuse me for this simple question.
How to convert as.data.frame to as.character?
?data.frame
> L3 <- LETTERS[1:3]
> L10 <- LETTERS[1:10]
> d <- data.frame(cbind(x=c("XYZ"), y=L10), fac=sample(L3, 10, repl=TRUE))
> d
x y fac
1 XYZ A A
2 XYZ B A
3 XYZ C A
4 XYZ D A
5
Dear all,
I have encountered a bizarre ocurrence: tapply() does not treat the columns of
data.frame[,cols] in the same way as those of
data.frame[1:length(data.frame),cols]. Whilst for the latter it identifies the
"length" of the column to be length(data.frame) in the former it does not seem
Vincent Detours wrote:
Dear all,
Here is an issue I often stumble on.
1- colunm types in data.frames.
---
d <- data.frame(x=as.character(c("a", "b", "c")), y=as.numeric(c(1, 2, 3)))
d
x y
1 a 1
2 b 2
3 c 3
is.numeric(d[1,2])
[1] TRUE
is.numeric(d[1,1])
[1] FALSE
apply(
Dear all,
Here is an issue I often stumble on.
1- colunm types in data.frames.
---
> d <- data.frame(x=as.character(c("a", "b", "c")), y=as.numeric(c(1, 2, 3)))
> d
x y
1 a 1
2 b 2
3 c 3
> is.numeric(d[1,2])
[1] TRUE
> is.numeric(d[1,1])
[1] FALSE
> apply(d, c(1,2),
Hi Nic
Be careful with variables with same names in your environment as
variables in data.frame. If you have a variable with the same name
e.g. ppmtrans in data frame and in environment, your commands use
variable from environment. So probably trt is from data frame and
ppmtrans from environme
> From: Nic Ellis
>
> At 09:47 PM 2/22/2005 -0500, Liaw, Andy wrote:
> >Following the suggestions in the Posting Guide would help us
> to help you
> >much better.
> >
> >What command(s) did you use to get the data into
> >R? read.table("C:/.../persist.dat",col.names=c("a","b",etc."))
>
>
> >
At 09:47 PM 2/22/2005 -0500, Liaw, Andy wrote:
>Following the suggestions in the Posting Guide would help us to help you
>much better.
>
>What command(s) did you use to get the data into
>R? read.table("C:/.../persist.dat",col.names=c("a","b",etc."))
>What does the `.dat' file look like? Itn
Following the suggestions in the Posting Guide would help us to help you
much better.
What command(s) did you use to get the data into R? What does the `.dat'
file look like? What are `x' and `y'?
Data frames in R, by definition, has to have (unique) rownames. If they are
not present in the da
Dear R users,
I am using v2.0.1 on Windows 2000. I have read a ".dat" file with several
vectors, including 2 factors (2 levels x 3 levels), and a vector of
responses, into R. There are no unique row names. When I try plot(x,y) or
lm(y~x) the following error is returned:
Error in model.frame(f
thanks to Andy Liaw and james holtman that replied to my posting
this is very basic stuff, but for people strugling with these
concepts - as I am... - here goes a more detailed explanation
#
what I wanted was to create a list where every element would be a
column of a given data.frame
the o
Tiago R Magalhaes socrates.Berkeley.EDU> writes:
:
: Hi
:
: a)
: I want to make a list out of a data.frame, where each element of the
: list is a column of the data.frame.
: I looked in the archives and saw a lot of postings but surprsingly
: none elucidated me. I also tried the split, aggreg
> From: Tiago R Magalhaes
>
> Hi
>
> a)
> I want to make a list out of a data.frame, where each element of the
> list is a column of the data.frame.
> I looked in the archives and saw a lot of postings but surprsingly
> none elucidated me. I also tried the split, aggregate help files and
> cou
Hi
a)
I want to make a list out of a data.frame, where each element of the
list is a column of the data.frame.
I looked in the archives and saw a lot of postings but surprsingly
none elucidated me. I also tried the split, aggregate help files and
counldn't see any easy way to do this. I wouldn't
Hi,
as other already pointed out as.matrix is what you need.
Just one comment:
as.matrix(x[1,])
should be much faster for larger data frames compared to
as.matrix(x)[1,]
Best
jan
On Tue, 23 Nov 2004, Tiago R Magalhaes wrote:
> Hi
>
> I want to extract a row from a data.frame but I want
On Tue, 2004-11-23 at 16:27 +, Tiago R Magalhaes wrote:
> Hi
>
> I want to extract a row from a data.frame but I want that object to
> be a vector . After trying some different ways I end up always with a
> data.frame or with the wrong vector. Any pointers?
>
> x <- data.frame(a = factor(
Is this what you want?
> as.matrix(x[1,])[1,]
a b
"a" "4"
HTH,
Andy
> From: Tiago R Magalhaes
>
> Hi
>
> I want to extract a row from a data.frame but I want that object to
> be a vector . After trying some different ways I end up always with a
> data.frame or with the wrong vector. An
A data frame is a list, and a list is a vector. Once you understand that,
yoy may understand what you are seeing.
as.matrix(x)[1,] seems to be one of the easiest ways to get what you want
On Tue, 23 Nov 2004, Tiago R Magalhaes wrote:
Hi
I want to extract a row from a data.frame but I want that
Hi
I want to extract a row from a data.frame but I want that object to
be a vector . After trying some different ways I end up always with a
data.frame or with the wrong vector. Any pointers?
x <- data.frame(a = factor(c('a',2,'b')), b = c(4,5,6))
I want to get
"a" "4"
I tried:
as.vector(x[1,])
On Tue, 8 Jun 2004, Philip Sobolik wrote:
> Is there a limit to the number of columns that a data.frame can have?
Yes. A data frame is a list, and a list is limited to 2^31-1 items.
> For
> example, can I read.csv() a file that has 1000 columns and 10,000 rows,
> will it break or is it limi
Is there a limit to the number of columns that a data.frame can have? For
example, can I read.csv() a file that has 1000 columns and 10,000 rows,
will it break or is it limited by available memory.
...
Philip Soboli
Dear R-help,
I was surprised to find that data.frame() keeps the names of all columns:
> x1 <- structure(1:5, names=1:5)
> x2 <- structure(5:1, names=5:1)
> x3 <- structure(10:6, names=10:6)
> x <- data.frame(x1, x2, x3)
> str(x)
`data.frame': 5 obs. of 3 variables:
$ x1: Named int 1 2 3 4 5
On Mon, 9 Feb 2004 19:10:00 -0300, you wrote:
>Hi Duncan,
>
>You were right. It was a vector and not a data.frame that I was dealing
>with. But still I am having dificulties. Please, take a look at some output
>(I am using R Commander GUI by the way):
>
>R-cmdr> print(b)
> [1] 0.70 0.85 0.80 0.70
Dear Gustavo,
To fill in other list members, this is occurring with code written to
augment the Rcmdr package.
The problem is that .numeric is a vector of names of numeric variables
in the "active data set" (data frame) maintained by Rcmdr, it is not
itself a data frame. Consequently, your varste
OTECTED]
Enviada em: Monday, February 09, 2004 5:25 PM
Para: Gustavo Pinheiro
Cc: [EMAIL PROTECTED]
Assunto: Re: [R] data.frame to matrix
On Mon, 9 Feb 2004 17:47:36 -0300, "Gustavo Pinheiro"
<[EMAIL PROTECTED]> wrote :
>Hello all,
>
>I've had trouble converting
On Mon, 9 Feb 2004 17:47:36 -0300, "Gustavo Pinheiro"
<[EMAIL PROTECTED]> wrote :
>Hello all,
>
>I've had trouble converting a data.frame to a matrix (numeric) using either
>data.matrix() and as.matrix().
>After executing one of those I end up with another data.frame with only the
>first column of
Hello all,
I've had trouble converting a data.frame to a matrix (numeric) using either
data.matrix() and as.matrix().
After executing one of those I end up with another data.frame with only the
first column of the original data.frame.
I use a window (tcltk) to let the user choose the columns he wa
On Tue, 18 Nov 2003, Jeff D. Hamann wrote:
> Can someone tell me why this is since I can't seem to find an explination in
> the docs or FAQ for this.
>
> Since there are no "BM" in the mtrs data.frame, but only in the "parent"
> data.frame (trees), I'm assuming the subset data.frame is still as
Can someone tell me why this is since I can't seem to find an explination in
the docs or FAQ for this.
Since there are no "BM" in the mtrs data.frame, but only in the "parent"
data.frame (trees), I'm assuming the subset data.frame is still associated
with the original. Is that correct and how woul
Hi,
I think I have the same problem. The following works
> aa<-data.frame(1:10)
> ab<-data.frame(1:12)
> ba<-data.frame(1:14)
> bb<-data.frame(1:16)
> xa<-data.frame()
> xa$aa<-aa
> xa$ab<-ab
> xb<-data.frame()
> xb$ba<-ba
> xb$bb<-bb
> xx<-data.frame()
> xx$xa<-xa
> xx$xb<-xb
> summary(xx)
xa
I think data.matrix() is what you want.
-roger
Sokratis Alikhanidi wrote:
Dear colleagues,
I am beginner, so the primitive questions:
in pls.pcr package in the function mvr I need to indicate a matrix of observations and
a vector of responses.
But read.table function returns the data.frame o
One place to start is "A Guide for the Unwilling S User".
Patrick Burns
Burns Statistics
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and "A Guide for the Unwilling S User")
Sokratis Alikhanidi wrote:
Dear colleagues,
I am beginner, so the primitive questi
Dear colleagues,
I am beginner, so the primitive questions:
in pls.pcr package in the function mvr I need to indicate a matrix of observations and
a vector of responses.
But read.table function returns the data.frame object.
What is the way for conversion of the data.frame object into matrix
Hi!
> is there a exstisting function (..i found nothing until now.)
> what makes it possible transfrom a dataset:
>
> ID AGE V.MAI V.JUNE
> 11 20 100 120
> 12 30 200 90
>
> into
>
> IDAGEV
> 1120 100
> 1120 120
> 1230200
> 1230
Try ?reshape
A
-Original Message-
From: Christian Schulz [mailto:[EMAIL PROTECTED]
Sent: Wednesday, 24 September 2003 3:42 PM
To: [EMAIL PROTECTED]
Subject: [R] data.frame with duplicated id's
Hi,
is there a exstisting function (..i found nothing until now.)
what makes it pos
Hi,
is there a exstisting function (..i found nothing until now.)
what makes it possible transfrom a dataset:
ID AGE V.MAI V.JUNE
11 20 100 120
12 30 200 90
into
IDAGEV
1120 100
1120 120
1230200
123090
,or have i to programm th
Still works for me in both 1.7.1 and 1.8.0 (in development)
> data(women)
> women[["height"]]
[1] 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72
> women$height
[1] 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72
Can you provide an example of how it is failing for you?
Dirk Repsilber <[EMAIL PROTEC
On Thu, 24 Jul 2003 16:27:28 +0200, Dirk Repsilber
<[EMAIL PROTECTED]> wrote :
>Hi,
>
>is there advice how to subset a data.frame, where until R version 1.7.0
>it was possible to write
>
> > data[["subset"]]
>
>which meant the same as
>
> > data$subset
>
>(data is a data.frame). From 1.7.1 on thi
Dirk Repsilber wrote:
Hi,
is there advice how to subset a data.frame, where until R version 1.7.0
it was possible to write
> data[["subset"]]
which meant the same as
> data$subset
(data is a data.frame). From 1.7.1 on this does not seem to work longer.
Could there be a bug in downwards co
Hi,
is there advice how to subset a data.frame, where until R version 1.7.0
it was possible to write
> data[["subset"]]
which meant the same as
> data$subset
(data is a data.frame). From 1.7.1 on this does not seem to work longer.
Could there be a bug in downwards compatibility?
sincerely y
On Mon, 2 Jun 2003, Jean Eid wrote:
> I have two seperate questions that both deal with the way R handels data
> sets:
>
> First, I am trying to read a data set of 80M into R. I am using
> read.table(). The file is a tab file and I have tested the function for a
> small amount of lines. It seems
Hi all,
I have two seperate questions that both deal with the way R handels data
sets:
First, I am trying to read a data set of 80M into R. I am using
read.table(). The file is a tab file and I have tested the function for a
small amount of lines. It seems to work fine (i.e. correct amount of colu
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