You will not learn anything unless you do your own homework.
Watanabe Yumiko [EMAIL PROTECTED] wrote:
I have a question about R.
I would like to simulate a following model.
Xt+1=Xt(1+b)
b is a random variable.
to get 10 plots.
I haven't used R program, how can I code
Sorry, but might as well not have answered..., no?
Yumiko, you didnt say what your distribution assumptions were. take a look
at ?runif and ?rnorm and use that to search for help on your specific topic
to get you started.
-Tariq
On 12/22/06, Mike Prager [EMAIL PROTECTED] wrote:
You will not
Dear R users,
I'am using marray and Limma packages to analyze genepix output.
1) how can I filter bad spots from my data (data contains 3 types of bad
spots).
my experiment contains 12 samples and the bad spot are not associated to the
same probes
2) how can I remove control probes from my data
Dear R users,
I'am using marray and Limma packages to analyze genepix output.
1) how can I filter bad spots from my data (data contains 3 types of bad
spots).
my experiment contains 12 samples and the bad spot are not associated to the
same probes
2) how can I remove control probes from my data
Dear R-experts,
I have a dataset of 4 patients and each patient has many records at four
different time points. I have done 4 different qqnorm plots on the same graph
where each plot represents the records of one patient at each time point. I
would like to do the same graph for the
:[R] question about for loop
Dear R-experts,
I have a dataset of 4 patients and each patient has many records at
four different time points. I have done 4 different qqnorm plots on
the same graph where each plot represents the records of one patient
at each time
Dear R-Users,
For example i have a data matrix with five samples and three variables.
DATA - matrix(c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5),nrow=5,ncol=3,byrow=TRUE)
colnames (DATA) - c(V1,V2,V3)
rownames (DATA) - c(S1,S2,S3,S4,S5)
I want to normalize all samples to same sum of variables:
NormFun -
: Andris Jankevics [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Sent: Friday, December 08, 2006 9:36 AM
Subject: [R] question about apply function
Dear R-Users,
For example i have a data matrix with five samples and three
variables.
DATA -
matrix(c(1,1,1,2,2,2,3,3,3,4,4,4,5,5,5),nrow=5
I have a data set like this
I want to assign outward to Y if sc 90 and assign inward to Y if sc=90.
then cbind(p1982,Y) to get like these
p aa as ms cur sc Y
1 154l_aa ARG 152.04 108.83 -0.1020140 92.10410 inward
2 154l_aa THR 15.86 28.32 0.2563560 103.67100inward
3 154l_aa ASP 65.13
If p1982 is a data.frame:
p1982$Y - ifelse(p1982$sc90, 'inward', 'outward')
If it is a matrix
p1982 - cbind(p1982, Y=ifelse(p1982[,'sc']90, 'inward', 'outward'))
On 12/8/06, Aimin Yan [EMAIL PROTECTED] wrote:
I have a data set like this
I want to assign outward to Y if sc 90 and assign
Hopefully it is a dataframe or else you matrix will be converted to
character; forgot that when I sent it.
On 12/8/06, jim holtman [EMAIL PROTECTED] wrote:
If p1982 is a data.frame:
p1982$Y - ifelse(p1982$sc90, 'inward', 'outward')
If it is a matrix
p1982 - cbind(p1982,
Economiste
BP 294 Yaoundé.
Tél (00237)9597295.
- Message d'origine
De : Leeds, Mark (IED) [EMAIL PROTECTED]
À : r-help@stat.math.ethz.ch
Cc : C. Park [EMAIL PROTECTED]
Envoyé le : Mardi, 5 Décembre 2006, 21h42mn 21s
Objet : [R] stat question - not R question so ignore if not interested
If do
. Park; Leeds,Mark (IED)
Subject: Re: [R] stat question - not R question so ignore if not interested
A classic example used by my colleague Paul Rozin (when he
teaches Psych 1) is to compute the correlation between height
and number of shoes owned, in the class. Shorter students own
more shoes
To whom it may be concernedDear all:
i am a
statistics of Humboldt university in berlin. I need R-2.4 for my data analysis,
but unfortunately, it does not work. The installation
works smoothly, but when I double click on the shortcut or from the start menu,
the error warning jumps out. My
If do a scattrplot of data ( x and y ) and there are two clouds of
points. One cloud is in the left
bottom corner of the plot and the other cloud is in the upper right.
If I fit a regression line to this data ( or equivalently , calculate a
correlation ), then obviously, it is going to seem like
The missing piece is why there are two clusters. There is
most likely a two-level factor distinguishing the groups
that was not included in the model. It might not even have
been measured and now you need to find it.
Rich
__
R-help@stat.math.ethz.ch
A classic example used by my colleague Paul Rozin (when he
teaches Psych 1) is to compute the correlation between height
and number of shoes owned, in the class. Shorter students own
more shoes. But ...
On 12/05/06 16:34, Richard M. Heiberger wrote:
The missing piece is why there are two
On Dec 5, 2006, at 3:42 PM, Leeds, Mark ((IED)) wrote:
If do a scattrplot of data ( x and y ) and there are two clouds of
points. One cloud is in the left
bottom corner of the plot and the other cloud is in the upper right.
If I fit a regression line to this data ( or equivalently ,
94404
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Jonathan Baron
Sent: Tuesday, December 05, 2006 1:45 PM
To: Richard M. Heiberger
Cc: r-help@stat.math.ethz.ch; C. Park; Leeds,Mark (IED)
Subject: Re: [R] stat question - not R question so ignore
Hi,
Searching the archives has brought no clue:
For a tex chunk in an Sweave text
Oracle query results: differences \Sexpr{varname},...
I need to change the string varname from X_1 to X\_1,
sub(_,??,X_+) - X\_1
so that subsequent Latex will generate X_1 (i.e. show the underscore)
instead
You are confusing the printed representation with the string (a clue which
is all over the archives, and in ?regex).
X1 - sub(_,\\_,X_1,fixed=TRUE)
print(X1)
cat(X1, \n)
X2 - sub(_,_,X_1)
cat(X1, \n)
both do as you ask.
On Fri, 1 Dec 2006, Christian Hoffmann wrote:
Hi,
Searching the
Hi,
I am new to this, can anyone help.
I am working with matrices, with stocknames as colNames and dates as
rowNames.
The data coontains percentile ranking for the stocks.
Date IBM MSFT 20061122 12 4 20061115 12 4
20061108
12 4 20061101 12 4 20061025 12 4
Try creating a zoo object from your data frame
# data from your post
DF - structure(list(Date = as.integer(c(20061122, 20061115, 20061108,
20061101, 20061025, 20061018, 20061011, 20061004, 20060927)),
IBM = as.integer(c(12, 12, 12, 12, 12, 12, 11, 12, 10)),
MSFT = as.integer(c(4, 4, 4, 4,
Hi Gavin,
I have been analyzing real data (sorry but I am not allowed to post
these data here) and what I got was this,
mydistmat_f.cap - capscale(distmat_f ~ F + L + F:L, mfactors_frame)
Warning messages:
1: some of the first 30 eigenvalues are 0 in: cmdscale(X, k = k, eig =
TRUE, add = add)
On Mon, 2006-11-27 at 15:37 +0100, Alicia Amadoz wrote:
Hi Gavin,
I have been analyzing real data (sorry but I am not allowed to post
these data here) and what I got was this,
mydistmat_f.cap - capscale(distmat_f ~ F + L + F:L, mfactors_frame)
I believe you can write that formula as:
Hi:
I have some problems when I use the function solve function in a loop. In
the following code, I have a diagonal martix ttt whose elements change in
every iteration in a loop. I defined a dpoMatrixclass before the loop so I
do not need to define this class every time in the loop. The
Hello,
Thank you for your help. I have tried to perform the analysis I wanted
with data of example, I mean not real data because I can't provide it
here. So, what I have tried is this,
matrix
[,1] [,2] [,3]
[1,] 0.00 0.13 0.59
[2,] 0.13 0.00 0.55
[3,] 0.59 0.55 0.00
dist_mat
12
On Fri, 2006-11-17 at 12:18 +0100, Alicia Amadoz wrote:
Hello,
Thank you for your help. I have tried to perform the analysis I wanted
with data of example, I mean not real data because I can't provide it
here. So, what I have tried is this,
Hi Alicia,
It would have been more helpful if
Hello Gavin,
Thank you very much for your help. I'm sorry I forgot to include all
commands that I used but next time I will try to write all of them. I
will try with my real data and see how it goes. I think I finally have
understood how capscale works with this kind of data. Thank you.
Regards,
On Fri, 2006-11-17 at 12:26 +, Gavin Simpson wrote:
On Fri, 2006-11-17 at 12:18 +0100, Alicia Amadoz wrote:
Hello,
Thank you for your help. I have tried to perform the analysis I wanted
with data of example, I mean not real data because I can't provide it
here. So, what I have
Hi there. Thanks for your time in advance.
My final goal is to calculate 1/2*integral of
(f1(x)^1/2-f2(x)^(1/2))^2dx (Latex codes:
$\frac{1}{2}\int^{{\infty}}_{\infty} (\sqrt{f_1(x)}-\sqrt{f_2(x)})^2dx
$.) where f1(x) and f2(x) are two estimated marginal densities.
My problem:
I have the
Hello,
I am interested in using the capscale function of vegan package of R. I
already have a dissimilarity matrix and I am intended to use it as
'distance' argument. But then, I don't know what kind of data must be in
'comm' argument. I don't understand what type of data must be referred
as
Hi Alicia,
On 11/16/06, Alicia Amadoz [EMAIL PROTECTED] wrote:
'comm' argument. I don't understand what type of data must be referred
as 'species scores' and 'community data frame' since my data refer to
nucleic distances between different sequences.
comm would be the original data from
Sorry, one additional note:
You don't need to specify comm to use capscale. Ignore what I said about
modifying the function.
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@stat.math.ethz.ch mailing list
On Thu, 2006-11-16 at 17:25 +0100, Alicia Amadoz wrote:
Hello,
I am interested in using the capscale function of vegan package of R. I
already have a dissimilarity matrix and I am intended to use it as
'distance' argument. But then, I don't know what kind of data must be in
'comm' argument.
Nice catch, Gavin - I missed that part of the original post. The
nucleic distances need to be included as the left-hand-side of
the formula, not as the distance argument.
comm is still optional, though, but it's not a good idea to omit
it if there's any way you can provide the original data. From
Hello,
I am interested in using the amova function of ade4 package of R. I
would like to know if there is any possibility to perform an amova with
a specific anova model, as a factorial anova with some factors nested,
or, if this could not be done, how could I perform an anova with my
specific
Hello
After (simple random cluster) resampling with replacement I ran MSM
function and I'm getting the following warning message ,which I'm not
sure why. I don't have any absorbing stage set up in my MSM model. I
have a 4 stage uni-directional MSM model. The only thing I see might be
a problem is
# Newbie alert
# I am wanting to multiply the rows in a dataframe by a vector.
# However, the default behavior appears to be for the vector to be applied
# column wise. For example:
vct - 1:4
df - data.frame(c1 = 5:10, c2= 6:11, c3=7:12, c4=8:13)
multTheTwo - vct * df
multTheTwo
# This results
Here are a couple of possibilities:
as.data.frame(t(t(df) * vct))
df * rep(vct, each = nrow(df))
On 11/13/06, RDM [EMAIL PROTECTED] wrote:
# Newbie alert
# I am wanting to multiply the rows in a dataframe by a vector.
# However, the default behavior appears to be for the vector to be
Hi to all ... the same code, but another question.
I changed only the type='n' to type='l' and debugged the function xy.coords.
with type = 'l' :
there are the correct values of x and y inside the function xy.coords
but the y value is filled with NA seems that the length is matching now
because
Carmen Meier said the following on 11/10/2006 9:46 AM:
Hi to all ... the same code, but another question.
I changed only the type='n' to type='l' and debugged the function xy.coords.
with type = 'l' :
there are the correct values of x and y inside the function xy.coords
but the y value is
Hi R-users,
I have 48 blocks like below
1 2 3 4
5 6 7 8
9 10 11 12
13 14 15 16
17 18 19 20
21 22 23 24
25 26 27 28
29 30 31 32
33 34 35 36
37 38 39 40
41 42 43 44
45 46 47 48
in each block there are 18 cloumns and 18 rows which give 18*18*48
observations. The
Christine A. Calmes [EMAIL PROTECTED] wrote:
[...] Basically, I am trying to test a
psychological model in which a person's level of passive, negative
communication with others in their environment (CORUMTO) on one week
predicts their level of depression on the following week (BDIAFTER)
Christoph Buser wrote:
Dear Christine
I think the problem in your second model is that you are
including CORUMTO both as a fixed effect and as a random
effect.
That by itself should not be a problem. Here is an example in which
age appears in both the fixed and random part of a model:
University of New York
Park Hall 216
Buffalo, NY 14260
[EMAIL PROTECTED]
(716) 645-3650 x578
-Original Message-
From: Chuck Cleland [mailto:[EMAIL PROTECTED]
Sent: Tuesday, November 07, 2006 5:00 AM
To: Christoph Buser
Cc: Christine A. Calmes; R-help@stat.math.ethz.ch
Subject: Re: [R] question
Christine--
You have two and only two individuals per dyad; when you try to fit random
slopes at level-2 (within couples), you are attempting to estimate an
intercept,
slope, and covariance for each individual. Basically, you don't have enough
data to do it. If you restrict yourself to a
library(nlme)
fm1 - gls(follicles ~ sin(2*pi*Time) + cos(2*pi*Time), Ovary,
+correlation = corARMA(form = ~ 1 | Mare, p = 2))
summary(fm1)
Generalized least squares fit by REML
Model: follicles ~ sin(2 * pi * Time) + cos(2 * pi * Time)
Data: Ovary
AIC BIClogLik
Hi,
I am trying to run a multilevel model with time nested in people and
people nested in dyads (3 levels of nesting) by initially running a
series of models to test whether the slope/intercept should be fixed or
random. The problem that I am experiencing appears to arise between the
random
Hi:
The gls function I used in my code is the following
fm-gls(y~x,correlation=corARMA(p=2) )
My question is how to extact the AR(2) parameters from fm.
The object fm is the following. How can I extract the correlation
parameters
Phi1 and Phi2 from fm? These two parametrs is not in
I've accidently found [1]your photo at a flickr and i'm very interested in
it.
Can you tell me what place i can see in the background of it?
---
wbr, Barbara
References
1.
file://localhost/home/cmf3/tasks/keeper_au_new/0lXwcx/http://www.hunting.pl/flickr.html
Hi,
I have one matrix derived from my function. It is as following:
Browse[1] each.uaa.data
[,1] [,2]
[1,] 33 152.3530
[2,] 33 264.7059
[3,] 51 583.
[4,] 33 323.
[5,] 50 292.549
[6,] 33 300
[7,] 56 104.1176
[8,] 52 246.6667
[9,] 53 242.5490
[10,] 33
On Fri, Nov 03, 2006 at 02:47:37PM -0800, Waverley wrote:
Hi,
You probably created that matrix from a list. Eg
a - matrix(list(1,2,3,4),2,2)
a
[,1] [,2]
[1,] 13
[2,] 24
a[,2]
[[1]]
[1] 3
[[2]]
[1] 4
b - matrix(1:4,2,2)
b[,2]
[1] 3 4
Both a and b are matrices, but
Hi R folks,
I am using R version 2.2.1 for Unix. I am exploring the rpart function,
in particular the rpart.control parameter. I have tried using different
values for xval (0, 1, 10, 20) leaving other parameters constant but I
receive the same tree after each run. Is the10 fold
On Thu, 2 Nov 2006, Brian Sanborn wrote:
Hi R folks,
I am using R version 2.2.1 for Unix. I am exploring the rpart function,
in particular the rpart.control parameter. I have tried using different
values for xval (0, 1, 10, 20) leaving other parameters constant but I
receive the same tree
Hi,
I am new to R community and I have a question on panel configurations in
the Trellis package.
Particularly, I have the following code:
require(lattice)
plotTable - NULL
Date - seq(as.Date(2006-11-01), as.Date(2009-12-01), by = 1)
nYear - length(unique(format(Date,%Y)))
plotTable$Date -
On 10/27/06, Zheleznyak, Anatoley [EMAIL PROTECTED] wrote:
Hi,
I am new to R community and I have a question on panel configurations in
the Trellis package.
Particularly, I have the following code:
require(lattice)
plotTable - NULL
Date - seq(as.Date(2006-11-01), as.Date(2009-12-01), by =
On 10/27/06, Zheleznyak, Anatoley [EMAIL PROTECTED] wrote:
Hi,
I am new to R community and I have a question on panel configurations in
the Trellis package.
Particularly, I have the following code:
require(lattice)
plotTable - NULL
Date - seq(as.Date(2006-11-01), as.Date(2009-12-01), by =
Hi
I am using ggplot under R 2.4 / Linux.
When using
ggsmooth(method=lm)
is there a way to show the results of the separate linear regressions?
Thanks
Rainer
--
Rainer M. Krug, Dipl. Phys. (Germany), MSc Conservation
Biology (UCT)
Department of Conservation Ecology and Entomology
When using
ggsmooth(method=lm)
is there a way to show the results of the separate linear regressions?
Do you mean doing a seperate linear regression for each group in your
data? If so, have a look at ?gggroup for some examples of exactly
that.
Hadley
hadley wickham wrote:
When using
ggsmooth(method=lm)
is there a way to show the results of the separate linear regressions?
Do you mean doing a seperate linear regression for each group in your
data? If so, have a look at ?gggroup for some examples of exactly
that.
No.
I do the
Do you mean doing a seperate linear regression for each group in your
data? If so, have a look at ?gggroup for some examples of exactly
that.
No.
I do the following:
p - ggplot(cc, . ~ expert, aesthetic=list(y=x0050, x=generation))
ggjitter(p)
ggsmooth(method=lm)
And I get
hadley wickham wrote:
Do you mean doing a seperate linear regression for each group in your
data? If so, have a look at ?gggroup for some examples of exactly
that.
No.
I do the following:
p - ggplot(cc, . ~ expert, aesthetic=list(y=x0050, x=generation))
ggjitter(p)
rsqs - as.data.frame(stamp(mtcars, cyl ~ ., function(df)
summary(lm(mpg ~ wt, data=df))$r.squared))
rsqs$wt - 4
rsqs$mpg - 32
ggtext(p, data=rsqs, aes=list(label=value))
But that doesn't work for some reason I don't understand yet (but I'm
working on it)
Ooops - I just had the
hadley wickham wrote:
rsqs - as.data.frame(stamp(mtcars, cyl ~ ., function(df)
summary(lm(mpg ~ wt, data=df))$r.squared))
rsqs$wt - 4
rsqs$mpg - 32
ggtext(p, data=rsqs, aes=list(label=value))
But that doesn't work for some reason I don't understand yet (but I'm
working on it)
Oh yes, you are right. It seems that the default distribution used for
sampling is uniform. And whether the resampling generates a random
distribution or not depends on the distribution being sampled.
Thanks everyone for your help! I appreciate your support very much.
Tom
On 10/19/06, Ted
Hi,
I looked up the help file on sample(), but didn't find the info I was
looking for.
When sample() is used to resample from a distribution, e.g., bootstrap, how
does it do it? Does it use an uniform distribution, e.g., runif(), or
something else? And, when the help file says:sample(x)
When sampling with replacement (like ordinary bootstrap), each draw is
done independently, and in each draw every point has equal probability
of being drawn. When sampling without replacement (random permutation),
all possible sequences (permutations) have equal probability of
occurring. E.g.,
On Thu, 2006-10-19 at 12:07 -0500, tom soyer wrote:
Hi,
I looked up the help file on sample(), but didn't find the info I was
looking for.
When sample() is used to resample from a distribution, e.g., bootstrap, how
does it do it? Does it use an uniform distribution, e.g., runif(), or
On 19-Oct-06 tom soyer wrote:
Hi,
I looked up the help file on sample(), but didn't find the
info I was looking for.
When sample() is used to resample from a distribution, e.g.,
bootstrap, how does it do it? Does it use an uniform distribution,
e.g., runif(), or something else?
I don't
Medicine and Biomedical Sciences
Colorado State University
From: Marc Schwartz [EMAIL PROTECTED]
Reply-To: [EMAIL PROTECTED]
To: tom soyer [EMAIL PROTECTED]
CC: r-help r-help@stat.math.ethz.ch
Subject: Re: [R] Question about random sampling in R
Date: Thu, 19 Oct 2006 13:10:20 -0500
On Thu, 2006
Tom Soyer wrote:
I looked up the help file on sample(), but didn't find the info I was
looking for.
When sample() is used to resample from a distribution, e.g.,
bootstrap, how does it do it? Does it use an uniform distribution,
e.g., runif(), or something else? And, when the help file
Hi all,
I'm having sometrouble with managing the seach path, in a function , I
need to attach some data set at the begining
and detach them at the end, say, myfunction- function() { attach(mylist);
.detach(mylist) } ,
the problem is, since I am still debugging this
Dear Tong
I think on.exit() makes the job..Namely:
attach(Yourdata) on.exit(detach(YourData))
vito
Tong Wang wrote:
Hi all,
I'm having sometrouble with managing the seach path, in a function , I
need to attach some data set at the begining
and detach them at the end, say,
On 10/17/2006 3:49 AM, Tong Wang wrote:
Hi all,
I'm having sometrouble with managing the seach path, in a function , I
need to attach some data set at the begining
and detach them at the end, say, myfunction- function() {
attach(mylist); .detach(mylist) } ,
Dear all,
I want to see if the treatment of an animal with a specific compound has an
effect on the expression of certain genes. Though my question is based in
biology, it really is all about how to deal with the standard deviation in
normalised data.
I have three groups of animals; untreated,
Thanks, Marc,
I tried it and it didn't really work.
x.num-as.numeric(x)
is.numeric(x.num)
[1] TRUE
x.num-readClipboard()
is.numeric(x.num)
[1] FALSE
is.character(x.num)
[1] TRUE
I use readClipboard to take in data, and it seems after the data is taken
in, x.num changed to character.
I just
Yulei,
It would appear that the default mechanism for the function (which
appears to be Windows specific) is to read in the data from the current
system clipboard as a _character vector_. Thus, perhaps something like:
x.num - as.numeric(readClipboard())
would be helpful.
With respect to
Marc, Thanks! x.num - as.numeric(readClipboard()) works perfect.
Meanwhile, I have tried to use odbcConnectExcel from RODBC pack. It seems
to work as well. I am able to read in the data, but I need to construct a
sql table from the data, and use sqlFetch to retrieve and assign them to
Hi,
I have the following data and there is no binary operator contained,
however, I still receive the error message when running unitrootTest
function, could someone give me a guidance on it??
readClipboard()
[1] 245246261.5 275.5 307284.5 289313.5
323.75 334 312.5 325
On Tue, 2006-10-10 at 22:35 -0400, Yulei Gong wrote:
Hi,
I have the following data and there is no binary operator contained,
however, I still receive the error message when running unitrootTest
function, could someone give me a guidance on it??
readClipboard()
[1] 245246261.5
hi all
i would like to use r and winbugs in order to undertake seemingly unrelated
regression. i am using the R2WINBUGS library. i just simulated a simple example
(sample size is 25) in order to get the correct code.
i suspect that the problem is in my definition of the prior. it wants a
allan clark allan at stats.uct.ac.za writes:
hi all
i would like to use r and winbugs in order to undertake seemingly unrelated
regression. i am using the
R2WINBUGS library. i just simulated a simple example (sample size is 25) in
order to get the correct code.
i suspect that the
If I want to do a join based on *two* matching fields in two data frames,
can merge() handle this? It appears to only handle a single matching column
-- do I need to make a metacolumn or is there some way to do this? E.g.:
Dataframe 1 contains columns A,B,C and Dataframe 2 contains A,B,D
I
help of you.
Xiaohui Chen
Dept. of Statistics
UBC, Canada
From: Jonathan Greenberg [EMAIL PROTECTED]
To: R-help r-help@stat.math.ethz.ch
Subject: [R] Question about merge()
Date: Sat, 23 Sep 2006 15:08:22 -0700
If I want to do a join based on *two* matching fields in two data frames,
can
MERGE DATA FRAMES BY 2 OR MORE VARIABLES
###
# MERGE 2 DATA FRAMES BASED ON#
# 2 OR MORE VARIABLES #
###
data1-data.frame(x.id1 = 1:10, x.id2 = (1:10) * 2, x = rnorm(length(1:10)));
to: r-help@stat.math.ethz.ch
Subject:Re: [R] Question on apply() with more information...
Hi,
I tried both ideas, but it isn't that what I'm looking for.
I want to avoid for loop, because the matrix is of big size(1200*1200
entries)
With a loop I would do
Dear list,
I try to do the following:
I have an list of length n, with elements done by smooth.spline
(SmoothList).
Now I have a matrix with n rows and m columns with x-values(Xarray)
Now I want ot predict the y-values.
Therefor I want to take the first element of SmoothList and the first row
at 8:05, Gunther Höning wrote:
From: Gunther Höning [EMAIL PROTECTED]
To: r-help@stat.math.ethz.ch
Date sent: Mon, 18 Sep 2006 08:05:28 +0200
Subject:[R] Question on apply()
Dear list,
I try to do the following:
I have
:[EMAIL PROTECTED]
Gesendet: Montag, 18. September 2006 08:43
An: Gunther Höning; r-help@stat.math.ethz.ch
Betreff: Re: [R] Question on apply()
Hi
not much information about what can be wrong. As nobody knows your Xarray
and SmoothList it is hard to guess. You even omitted to show what does not
work
So
Höning [EMAIL PROTECTED]
To: 'Petr Pikal' [EMAIL PROTECTED],
r-help@stat.math.ethz.ch
Subject:AW: [R] Question on apply() with more information...
Date sent: Mon, 18 Sep 2006 09:26:01 +0200
Ok.
I tried this too, but it still doesn't work.
Here
than just to predict a value, but it isn't
important for the initial question...
Gunther
-Ursprüngliche Nachricht-
Von: Petr Pikal [mailto:[EMAIL PROTECTED]
Gesendet: Montag, 18. September 2006 11:44
An: Gunther Höning
Cc: r-help@stat.math.ethz.ch
Betreff: Re: AW: [R] Question on apply
From: =?ISO646-US?Q?Gunther_H=3Fning?= [EMAIL PROTECTED]
Date: 2006/09/18 Mon AM 06:26:25 CDT
To: 'Petr Pikal' [EMAIL PROTECTED]
Cc: r-help@stat.math.ethz.ch
Subject: Re: [R] Question on apply() with more information...
I think you want something like below but it
probably needs some fixing up
Hi,
I would like to paired ID_ with Cod for analysis in spdep.
Any ideas?
head(bai$att.data)
ID_ NAME1_ NAME2_ PARTS_ POINTS_ LENGTH_ AREA_
1 410690205001 410690205001 NA 1 158 5.243338 1.2668820
2 410690205009 410690205009 NA 1 159 6.071286
Hi,
I want to do 2-dimentional loess smoothing in gam through the command
gam(Y~lo(X1,X2,span=span,degree=1) )
in library gam.
The span is the percentage of data points to define the neighborhood and used
for the smoothing.
Does this command do one 2-dimentional smoothing with
Hello Colleagues,
I programmed in SAS for 3 years and would like to switch to a not so costly
software product.
Hence I started to evaluate R, and my first test look promising.
However I have some question:
1. Is it possible to query R files by SQL internally on data frames (not on
a
Thorsten Muehge wrote:
Hello Colleagues,
I programmed in SAS for 3 years and would like to switch to a not so costly
software product.
Hence I started to evaluate R, and my first test look promising.
However I have some question:
1. Is it possible to query R files by SQL internally
Thorsten Muehge MUEHGE at de.ibm.com writes:
1. Is it possible to query R files by SQL internally on data frames (not on
a database) and how is the syntax (I have the RODBC package installed).
It is possible to do similar things conceptually in R as in SQL---at least the
basic SQL queries (I
For your 1st question, you can write query against the tables in DB using RODBC.
Being a SAS programmer, I have to say that reporting function of R is
not as good as that of SAS.
On 9/13/06, Thorsten Muehge [EMAIL PROTECTED] wrote:
Hello Colleagues,
I programmed in SAS for 3 years and
Wensui Liu wrote:
For your 1st question, you can write query against the tables in DB using
RODBC.
Being a SAS programmer, I have to say that reporting function of R is
not as good as that of SAS.
I beg to differ. See for example
http://biostat.mc.vanderbilt.edu/StatReport
Frank Harrell
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