Hi,
I have been tried to apply hopach HOPACH in R to cluster some genes. My
data is a binary matrix. It works well for the whole set of genes (say,
1000 genes). Then I selected a subset of the genes (say 300 genes). These
genes are selected based on the regression analysis results for
Dear all,
I've recently switched from EViews to R with RMetrics/fSeries (newest
version of july 10) for my analysis because of the much bigger
flexibility it offers. So far my experiences had been great -prior I
had already worked extensively with S-Plus so was already kind of
familiar with the
@stat.math.ethz.ch
Subject: [R] Questions regarding R and fitting GARCH models
Dear all,
I've recently switched from EViews to R with RMetrics/fSeries (newest
version of july 10) for my analysis because of the much bigger
flexibility it offers. So far my experiences had been great -prior I
had already worked
Ana
You are estimating a random coefficient model on 5 individuals (mean
and variance). Are you sure this is wise?
Ross Darnell
- Original Message -
From: Ana Conesa [EMAIL PROTECTED]
Date: Thursday, July 5, 2007 1:21 am
Subject: [R] questions on lme function
Dear list,
I am
Dear all,
I'm creating a histogram with the function hist(). But
right now what I get is column representation (as normal).
I'm wondering if I could switch X-axis and Y-axis and
get row-representation of frequencies?
One more question, can I define the step of each axises
for the histogram?
Dear R-experts,
I have some questions about boxplots with lattice.
My data is similar as in the example below, I have two factors
(Goodness of Fit and Algorithms) and data values but in each panels the scales
are quite different, therefore the normal boxplots produced by
set.seed(1)
GOF -
## I simplified this panel function by taking the calculations outside
## the panel function to allow use of the original variable names.
my.boxpanel3 - function(x, y, subscripts, ..., medians, best) {
cols - grey(1-best[,panel.number()]/3)
panel.bwplot(x, y, fill=cols, ...)
On May 21, 2007, at 8:39 AM, Klaus Nordhausen wrote:
Dear R-experts,
I have some questions about boxplots with lattice.
My data is similar as in the example below, I have two factors
(Goodness of Fit and Algorithms) and data values but in each panels
the scales are quite different,
Dear list members:
Once I know a KEGG pathway identifier, how can I check all its direct
children identifiers? you know, I could use GOMFCHILDREN or GOCCCHILDREN to
check the children terms for a specific GO term, but I don't know how to do it
in the same way for KEGG in R?
Many Thanks!!
Li, Hua [EMAIL PROTECTED] writes:
Dear list members: Once I know a KEGG pathway identifier, how can I
check all its direct children identifiers? you know, I could use
GOMFCHILDREN or GOCCCHILDREN to check the children terms for a
specific GO term, but I don't know how to do it in the same
Hello,
I am trying to fit a seasonal ARIMA model. I am using the ARIMA package in
R. when I look at the model coefficients I find that that the first order
seasonal moving average term is very close to -1(this is after first order
seasonal differencing), I have tried to look at the literature on
Hi,
I am using biplot (in package stats) to visualize the results of some
PCA analyses. When I use scale=0 in the biplot function, it draws X (PC1)
and Y (PC2) axes, with the scales multiplied by sqrt(N), where N is the
sample size. Is there a way to change these scales so that the actual
Hi,
PCAproj is mainly designed for robust PCA and not for classical PCA.
Therefore, when applying classical estimators to the results of a
robust PCA, like the mean to the robust PCA scores, this will usually
not give zeros. The robust PCs have been centred robustly, and
not classically by the
Professor Filzmoser.
Thank you so much for the detailed response. It is very helpful.
-- TMK --
212-460-5430home
917-656-5351cell
From: Peter Filzmoser [EMAIL PROTECTED]
To: Talbot Katz [EMAIL PROTECTED]
CC: r-help@stat.math.ethz.ch
Subject: Re: Questions about results from PCAproj
Hi.
I have been looking at the PCAproj function in package pcaPP (R 2.4.1) for
robust principal components, and I'm trying to interpret the results. I
started with a data matrix of dimensions RxC (R is the number of rows /
observations, C the number of columns / variables). PCAproj returns a
Hi all,
for the data below I would like to
1. generate a dummy variable for each group gr of the same composition by
people, then save each portion in a separate file,
2. compute the frequency of 1's in x for each person by group
gr. So, mike will have freq=2/3, as he has two 1 and one 0 in
On 2/6/07, Serguei Kaniovski [EMAIL PROTECTED] wrote:
Hi all,
for the data below I would like to
1. generate a dummy variable for each group gr of the same composition by
people, then save each portion in a separate file,
This gives back a list that you can go through and write out each
I have been using the wonderful xtable package lately, in combination
with Sweave, and I have a couple of general questions along with a
more particular one.
I'll start with the particular question. I basically have a 1x3 array
with column names but no row names. I want to create a latex
Hi,
I would like to assign a value to a member b of the list a in position
3, by calling:
assign( target, 2.34, 3)
My question is what the target should be. I tried target - paste(a, $,
b) and something else,
but haven't got the right
Try this:
a - list(a = 1, b = 2, c = 3)
assign(a, replace(get(a), 3, 2.34))
a
$a
[1] 1
$b
[1] 2
$c
[1] 2.34
On 1/13/07, Tong Wang [EMAIL PROTECTED] wrote:
Hi,
I would like to assign a value to a member b of the list a in position
3, by calling:
Hi all:
After calculating in R I want to show the answer and some explanations not
graphic plots in another new device and then save it as txt.file. However, I
couldn't find any package or command to do it yet. I know some commands about
generating graphics on different types of display or
u9470002 wrote:
Hi all:
After calculating in R I want to show the answer and some explanations not
graphic plots in another new device and then save it as txt.file. However, I
couldn't find any package or command to do it yet. I know some commands about
generating graphics on different
Hi,
I am using 2 times series and I want to carry out a regression of Seri1
by Serie2 using structured (autocorrelated) errors.
(Equivalent to the autoreg function in SAS)
I found the function gls (package nlme) and I made:
gls_mens-gls(mening_s_des~dataATB, correlation = corAR1())
My problem
I think the function 'arima' can handle this, except for
the automatic evaluation of the ARMA orders.
Giovanni
Date: Wed, 06 Dec 2006 12:06:46 +0100
From: Lulla OPATOWSKI [EMAIL PROTECTED]
Sender: [EMAIL PROTECTED]
Precedence: list
--===0156932283==
Content-Disposition:
hi, my name is giuseppe and i am an engineer, i am using R for regressions
analysis using mixed random effects model, funztion nlme.
quastions are:
1) when i ask for the summary after a regression using nlme function the
program gives me the values of the coefficients and also the standard
Hi Guiseppe,
On Wed, Nov 29, 2006 at 01:26:37AM +, giuseppe scasserra wrote:
hi, my name is giuseppe and i am an engineer, i am using R for regressions
analysis using mixed random effects model, funztion nlme.
quastions are:
1) when i ask for the summary after a regression using nlme
Christian Schulz [EMAIL PROTECTED] writes:
split - sample(2,nrow(dataframe),replace=T,prob=c(0.04,0.96))
dataframe[split==1,] # 200
dataframe[split==2,] # 4800
regards, christian
?sample should tell you what you need to know.
It does, but the above is not how. To get exactly 200
Further to Alexander's question ... could anyone provide assistance
with random stratified sampling? Let's say we have Alex's dataframe
and we want to stratify the random selection by group membership
(which is contained in one of the eight columns).
We might want to randomly select:
1) a
On Mon, 27 Nov 2006, Mark Na wrote:
Further to Alexander's question ... could anyone provide assistance
with random stratified sampling? Let's say we have Alex's dataframe
and we want to stratify the random selection by group membership
(which is contained in one of the eight columns).
We
Hello!
I have a data set with 8 columns and in about 5000 rows. What I want to
do is to generate samples of this data set.
Samples of a special size, as example 200.
What is the easiest way to do this? No special things are needed, only
the random selection of 200 rows of the data set.
?sample should tell you what you need to know.
On 26/11/06, Alexander Geisler [EMAIL PROTECTED] wrote:
Hello!
I have a data set with 8 columns and in about 5000 rows. What I want to
do is to generate samples of this data set.
Samples of a special size, as example 200.
What is the easiest
split - sample(2,nrow(dataframe),replace=T,prob=c(0.04,0.96))
dataframe[split==1,] # 200
dataframe[split==2,] # 4800
regards, christian
?sample should tell you what you need to know.
On 26/11/06, Alexander Geisler [EMAIL PROTECTED] wrote:
Hello!
I have a data set with 8 columns and
A follow-up. Thanks to Matthias, the codes worked very well.
Le
On 11/18/06, Matthias Kohl [EMAIL PROTECTED] wrote:
Hello,
your integrand needs to be a function which accepts a numeric vector as
first argument and returns a vector of the same length (see ?integrate).
Your function
Hi all,
I was trying garchFIt() of fSeries to fit volatility of monthly log returns
of SP500. I tried residuals of normal, student t, skew normal, skew t. But
all innovations except normal got exaxtly same coefficients, even if I
changed their parameters of skew and shape.
Is this correct for
Your example is incomplete (what is x?), but axis(1, at=0.5) may be what
you are looking for.
On Sun, 19 Nov 2006, zhijie zhang wrote:
Dear Ruser,
I use abline() function to add the reference line successfully, but i
can't display the values corresponding to the reference line on the x/y
Hi there. Thanks for your time in advance.
I am using R 2.2.0 and OS: Windows XP.
My final goal is to calculate 1/2*integral of
(f1(x)^1/2-f2(x)^(1/2))^2dx (Latex codes:
$\frac{1}{2}\int^{{\infty}}_{\infty}
(\sqrt{f_1(x)}-\sqrt{f_2(x)})^2dx $.) where f1(x) and f2(x) are two
marginal densities.
Hello,
your integrand needs to be a function which accepts a numeric vector as
first argument and returns a vector of the same length (see ?integrate).
Your function does not fulfill this requirement. Hence, you have to
rewrite your function or use sapply, apply or friends; something like
Dear Ruser,
I use abline() function to add the reference line successfully, but i
can't display the values corresponding to the reference line on the x/y
axis, anybody knows how to display it?
*My simulated programs:*
y-rnorm(50)
plot(x,y)
abline(v=0.5) *#my question is how to display x=0.5
Try:
axis(1, 0.5, tick = TRUE)
On 11/18/06, zhijie zhang [EMAIL PROTECTED] wrote:
Dear Ruser,
I use abline() function to add the reference line successfully, but i
can't display the values corresponding to the reference line on the x/y
axis, anybody knows how to display it?
*My simulated
Hi there. Thanks for your time in advance.
My final goal is to calculate 1/2*integral of
(f1(x)^1/2-f2(x)^(1/2))^2dx (Latex codes:
$\frac{1}{2}\int^{{\infty}}_{\infty}
(\sqrt{f_1(x)}-\sqrt{f_2(x)})^2dx $.) where f1(x) and f2(x) are two
marginal densities.
My problem:
I have the following R
I'm getting a weird behavior using R 2.5.0 for MacOS X -- I have a csv file
with a properly formatted date/time field, e.g. After reading in the csv
to hourly_met_data, with a date field
hourly_met_data$date - as.POSIXct(hourly_met_data$date)
works exactly as it is supposed to (e.g. Min/max of
Thanks! Worked like a charm!
hourly_met_data$date -
as.POSIXct(trunc(as.POSIXct(hourly_met_data$date),day))
--j
On 10/20/06 3:31 PM, jim holtman [EMAIL PROTECTED] wrote:
trunc returns a type of POSIXlt. You have to apply 'as.POSIXct' to the
result.
On 10/20/06, Jonathan Greenberg
:[R] R questions
I have a few questions for R:
1. Other than using a built-in function such as mean(), how do I know
if it is installed in my current version of R?
see the difference between installed packages (e.g. those you have in
your library directory and packages attached by library
You might want to read
Ligges (2003): R Help Desk: Getting Help - R's Help Facilities and
Manuals, R News 3(1), 26--28,
http://cran.r-project.org/doc/Rnews/Rnews_2003-1.pdf
Uwe Ligges
Lynda wrote:
I have a few questions for R:
1. Other than using a built-in function such as mean(), how
I have a few questions for R:
1. Other than using a built-in function such as mean(), how do I know if
it is installed in my current version of R?
2. To get help in R, I can use several ways:
?sort
help.search(sort)
help(sort)
apropos(sort)
the help menu
are there any other ways to get help?
Dear R users,
I am doing my project which I want to plot a piecewise function, I knew
that I can use the command segments to plot. But the problem is I want
to use my real data which needs me to sort of my data by using the 'if
else'command, I use it
If(t[i]36) lambda-0.5
Else lambda-0.2
The
Regarding your other questions
On 9/4/06, Xiao Zhao [EMAIL PROTECTED] wrote:
Dear R users,
I am doing my project which I want to plot a piecewise function, I knew
that I can use the command segments to plot. But the problem is I want
to use my real data which needs me to sort of my data by
Brian Lunergan ff809 at ncf.ca writes:
Evening all:
I'm taking a little time to experiment with R, Sweave, and Miktex/LaTex but
I've run up against some problems and -well- I hope that there are some on
the list who might have some suggestions. This will be kind of wordy as I
will
* Dieter Menne wrote, On 2006-08-04 02:57:
Brian Lunergan ff809 at ncf.ca writes:
Evening all:
I'm taking a little time to experiment with R, Sweave, and Miktex/LaTex but
I've run up against some problems and -well- I hope that there are some on
the list who might have some suggestions.
Hi,
i've two questions concerning the plot of a dendrogram. first, i use
hclust for clustering and if i plot the dendrogram, then the maximal
height is the maximal dissimilarity found in my data. but i want to have
a arbitary maximal height. for example if the maximal dissimilarity in
my data
Hi,
i've two questions concerning the plot of a dendrogram. first, i use
hclust for clustering and if i plot the dendrogram, then the maximal
height is the maximal dissimilarity found in my data. but i want to have
a arbitary maximal height. for example if the maximal dissimilarity in
my data
Evening all:
I'm taking a little time to experiment with R, Sweave, and Miktex/LaTex but
I've run up against some problems and -well- I hope that there are some on
the list who might have some suggestions. This will be kind of wordy as I
will include the complete files involved as I'm just not
Dear friends,
my question is how to aggregate dataset and the inverse manipulation.
e.g.My dataset
data structure1:
x
1
1
2
3
3
data structure2:
x freq
1 2
2 1
3 2
Then how to generate dataset2 from dataset1 and generate dataset1 from
dataset2?
e.g. dataset2 from dataset1 :
x-c(1,1,2,3,3)
data.frame(x = with(df1, rep(x, freq)))
---
Jacques VESLOT
CNRS UMR 8090
I.B.L (2ème étage)
1 rue du Professeur Calmette
B.P. 245
59019 Lille Cedex
Tel : 33 (0)3.20.87.10.44
Fax : 33 (0)3.20.87.10.31
http://www-good.ibl.fr
]
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Dylan Beaudette
Sent: Monday, July 31, 2006 6:43 PM
To: RHELP
Subject: [R] questions regarding spline functions
Greetings,
A couple general questions regarding the use of splines to interpolate
Greetings,
A couple general questions regarding the use of splines to interpolate depth
profile data.
Here is an example of a set of depths, with associated attributes for a given
soil profile, along with a function for calculating midpoints from a set of
soil horizon boundaries:
#calculate
Greetings everyone,
The problem has been solved. A faulty evaluation of the decision
Function was the culprit.
Signed,
Johan Van Kerckhoven
Greetings everyone,
I have the following problem (illustrating R-code at bottom of mail):
Given a training sample with binary outcomes (-1/+1), I
Li, Hua HUL at stowers-institute.org writes:
I am using extract.lme.cov to extract the covariance matrix of lme. But
the results are not expected.
b - lme(travel~1,Rail,~1|Rail)
The default correlation for lme is no correlation within groups.
extract.lme.cov(b,Rail)
The part of
Hi, all:
I am using extract.lme.cov to extract the covariance matrix of lme. But
the results are not expected.
For example,
b - lme(travel~1,Rail,~1|Rail)
The default correlation for lme is no correlation within groups.
extract.lme.cov(b,Rail)
The part of covariance matrix looks like:
merge(mn[sample(1:nrow(mn), 3, rep=F),], xy, by.x=c(m,n), by.y=c(x,y))
---
Jacques VESLOT
CNRS UMR 8090
I.B.L (2ème étage)
1 rue du Professeur Calmette
B.P. 245
59019 Lille Cedex
Tel : 33 (0)3.20.87.10.44
Fax : 33 (0)3.20.87.10.31
mnu - unique(mn[order(mn$m,mn$n),])
mnu$p - table(paste(mn$m, mn$n))
merge(mnu[sample(1:nrow(mnu), size=3, prob=mnu$p, replace=F), c(m,n)], xy,
by.x=c(m,n),
by.y=c(x,y))
---
Jacques VESLOT
CNRS UMR 8090
I.B.L (2ème étage)
1 rue
Dear friends,
suppose i have two datasets: A and B
A:
id-1:6
x-c(1,2,3,4,5,6)
y-c(2,4,6,8,3,2)
xy-data.frame(id,x,y)
B
m-c(1,1,3,3,5,5)
n-c(2,2,6,6,3,3)
mn-data.frame(m,n)
Now, i want to perfomr two tasks:
1. get a subset of B,no duplicate values,:
C:
m n
1 2
3 6
5 3
2.Extract the values in A
Greetings everyone,
I have the following problem (illustrating R-code at bottom of mail):
Given a training sample with binary outcomes (-1/+1), I train a linear
Support Vector Machine to separate them. Afterwards, I compute the
weight vector w in the usual way, and obtain the fitted values as
w'x
From: Duncan Murdoch
On 6/26/2006 3:14 PM, Dongseok Choi wrote:
Hello all!
I hope this is the right place to post this question.
The Oregon Chapter of ASA is working with local high
school teachers as one of its outreaching program.
We hope to use and test R as
On Tue, 27 Jun 2006, Liaw, Andy wrote:
From: Duncan Murdoch
On 6/26/2006 3:14 PM, Dongseok Choi wrote:
Hello all!
I hope this is the right place to post this question.
The Oregon Chapter of ASA is working with local high
school teachers as one of its outreaching program.
We hope
On 6/27/2006 8:05 AM, Liaw, Andy wrote:
From: Duncan Murdoch
On 6/26/2006 3:14 PM, Dongseok Choi wrote:
Hello all!
I hope this is the right place to post this question.
The Oregon Chapter of ASA is working with local high
school teachers as one of its outreaching
Hello all!
I hope this is the right place to post this question.
The Oregon Chapter of ASA is working with local high school teachers as one
of its outreaching program.
We hope to use and test R as teaching tools.
So, we think that a menu system (like R commander) with a few packages
On 6/26/2006 3:14 PM, Dongseok Choi wrote:
Hello all!
I hope this is the right place to post this question.
The Oregon Chapter of ASA is working with local high school teachers as one
of its outreaching program.
We hope to use and test R as teaching tools.
So, we think that a
Dear list members,
I'm using R in connection with the RDCOMClient and Excel. The more I use the
package, the more I'm fascinated of it. The possibilities of R can be
brought together with the necessities of outputing my socio-economical
research results in MS Office!
But I have some special
On 4/25/06, Dr. Michael Wolf [EMAIL PROTECTED] wrote:
3. RDCOMCLient and Excel Manual
===
Do you know a good overview of using Excel VBA code via RDCOMClient (e. g.
sh$Select())? Are there people interesting in working out such a paper? I
could contribute some
-help@stat.math.ethz.ch
Subject: Re: [R] Questions on formula in princomp
jim holtman [EMAIL PROTECTED] wrote:
does this explain it?
groups - factor(c(rep(Z,5),rep(X,5),rep(Y,5)))
groups
[1] Z Z Z Z Z X X X X X Y Y Y Y Y
Levels: X Y Z
as.integer(groups)
[1] 3 3 3 3 3 1 1 1
Gabor Grothendieck [EMAIL PROTECTED] wrote:
Sasha Pustota [EMAIL PROTECTED] wrote:
ir - rbind(iris3[,,1], iris3[,,2], iris3[,,3])
lir - data.frame(log(ir))
names(lir) - c(a,b,c,d)
I'm trying to understand the meaning of expressions like ~ a+b+c+d,
used with princomp, e.g.
princomp(~
Just use model.frame to examine what is passed:
ir - rbind(iris3[,,1], iris3[,,2], iris3[,,3])
lir - data.frame(log(ir))
names(lir) - c(a,b,c,d)
lir[1,1] - NA
mf - model.frame(~., lir,na.action=na.omit)
head(mf)
ab c d
2 1.589235 1.098612 0.3364722
Ok, that was just my wishful thinking.
Is there a way to plot repeated labels that identify groups, e.g.
factor(c(rep(s,50),rep(c,50),rep(v,50)))
instead of 1--150 row indices, using something like
biplot(princomp(lir)) ?
Gabor Grothendieck [EMAIL PROTECTED] wrote:
Just use model.frame to
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Sasha Pustota
Sent: Friday, April 14, 2006 3:35 PM
To: r-help@stat.math.ethz.ch
Subject: Re: [R] Questions on formula in princomp
Ok, that was just my wishful thinking.
Is there a way to plot
Berton Gunter [EMAIL PROTECTED] wrote:
plot(myscores[,1:2],pch=c('s','c','v')[groups])
Thanks, this works. How to understand the result of
the expression
c(1,2,'3)[groups]
[1] 3 3 3 3 3 1 1 1 1 1 2 2 2 2 2
where
groups - factor(c(rep(X,5), rep(Y,5), rep(Z,5)))
?
Sorry if it's
Sasha Pustota [EMAIL PROTECTED] wrote:
Berton Gunter [EMAIL PROTECTED] wrote:
plot(myscores[,1:2],pch=c('s','c','v')[groups])
Thanks, this works. How to understand the result of
the expression
c(1,2,'3)[groups]
[1] 3 3 3 3 3 1 1 1 1 1 2 2 2 2 2
where
groups -
does this explain it?
groups - factor(c(rep(Z,5),rep(X,5),rep(Y,5)))
groups
[1] Z Z Z Z Z X X X X X Y Y Y Y Y
Levels: X Y Z
as.integer(groups)
[1] 3 3 3 3 3 1 1 1 1 1 2 2 2 2 2
c(1,2,3)[groups]
[1] 3 3 3 3 3 1 1 1 1 1 2 2 2 2 2
On 4/14/06, Sasha Pustota [EMAIL PROTECTED] wrote:
Sasha
jim holtman [EMAIL PROTECTED] wrote:
does this explain it?
groups - factor(c(rep(Z,5),rep(X,5),rep(Y,5)))
groups
[1] Z Z Z Z Z X X X X X Y Y Y Y Y
Levels: X Y Z
as.integer(groups)
[1] 3 3 3 3 3 1 1 1 1 1 2 2 2 2 2
c(1,2,3)[groups]
[1] 3 3 3 3 3 1 1 1 1 1 2 2 2 2 2
I did
I hope this time I'm using the iris dataset correctly:
ir - rbind(iris3[,,1], iris3[,,2], iris3[,,3])
lir - data.frame(log(ir))
names(lir) - c(a,b,c,d)
I'm trying to understand the meaning of expressions like ~ a+b+c+d,
used with princomp, e.g.
princomp(~ a+b+c+d, data=lir, cor=T)
By
On 4/13/06, Sasha Pustota [EMAIL PROTECTED] wrote:
I hope this time I'm using the iris dataset correctly:
ir - rbind(iris3[,,1], iris3[,,2], iris3[,,3])
lir - data.frame(log(ir))
names(lir) - c(a,b,c,d)
I'm trying to understand the meaning of expressions like ~ a+b+c+d,
used with princomp,
Hello everyone,
I want to sort a dataset in R, using multiple columns as sorting
criteria. I know I can sort a dataset Data with 14 columns using one
column (the fifth), by typing:
DataSort-Data[order(Data[,5]),1:14]
But how can the dataset be sorted by column 5, then by 6, then by 8?
Sent: Thursday, February 23, 2006 10:06 AM
Subject: [R] Questions for manipulating datasets in R e.g. sorting
andmatching
Hello everyone,
I want to sort a dataset in R, using multiple columns as sorting
criteria. I know I can sort a dataset Data with 14 columns using one
column (the fifth
hi steffi,
try
DataSort-Data[order(Data[,5],Data[,6],Data[,8]),1:14]
and for further details ?order. For matching try ?merge.
Best Regards,
Christian
Stefanie von Felten, IPWIfU schrieb:
Hello everyone,
I want to sort a dataset in R, using multiple columns as sorting
criteria. I know I
Dear R- users,
I obtained a coxph object using the coxph function and use the coxph.detail
function to understand what coxph function actually does.
what follow are the R output
fit-coxph(Surv(B3TODEATH,STATUS)~GROUP+AGE+SEX+SEX:AGE)
detail- coxph.detail(fit)
-detail
$time
.(rows of
On 1/4/06 12:28 AM, Vincent Deng [EMAIL PROTECTED] wrote:
Dear R-helpers
I have a stupid question about cbind function. Suppose I have a
dataframe like this
Frame:
A 10
C 20
B 40
and a numeric matrix like this
Matrix:
A 1
B 2
C 3
cbind(Frame[,2],Matrix[,1]) simply binds
Dear R-helpers
I have a stupid question about cbind function. Suppose I have a
dataframe like this
Frame:
A 10
C 20
B 40
and a numeric matrix like this
Matrix:
A 1
B 2
C 3
cbind(Frame[,2],Matrix[,1]) simply binds these two columns without
checking the order, I mean, the result will be
A 10 1
B
On Wed, 2006-01-04 at 13:28 +0800, Vincent Deng wrote:
Dear R-helpers
I have a stupid question about cbind function. Suppose I have a
dataframe like this
Frame:
A 10
C 20
B 40
and a numeric matrix like this
Matrix:
A 1
B 2
C 3
cbind(Frame[,2],Matrix[,1]) simply binds these two
Hi
There is a very good introduction script to R on
http://www.r-project.org/
under manuals, including an index of nice functions. For
example you will find the basic plots, how to sort vectors and
so on.
Furthermore have a look at
?RSiteSearch
It is very useful to search in R archives for
Yuying Shi wrote:
Dear Sir/Madam,
I am a beginner in R. Here is my questions.
1. Can you give me one test for randomness (a name and descriptive
paragraph is sufficient).
2. I have learned a uniform random number generator [e.g. not the
algorithms: i)Wichmann-Hill, ii)
Dear Sir/Madam,
I am a beginner in R. Here is my questions.
1. Can you give me one test for randomness (a name and descriptive
paragraph is sufficient).
2. I have learned a uniform random number generator [e.g. not the
algorithms: i)Wichmann-Hill, ii) Marsaglia-Multicarry, iii) Super-Duper
Hi,
The latest version of R had some changes to functions readbin() and
writeBin() [which] now support raw vectors as well as filenames and
connections.. As a result I am working on retiring raw2bin and bin2raw
functions from caTools package which do exactly the same. Thanks to Prof.
Ripley for
I think you can use 'seek()' here, but it may not be completely reliable on all
platforms.
-roger
Tuszynski, Jaroslaw W. wrote:
Hi,
The latest version of R had some changes to functions readbin() and
writeBin() [which] now support raw vectors as well as filenames and
connections.. As a
Hi,
I am new to R. I have one question about outputing
files in a loop; Suppose I have the following loop:
for (i in 1:10) {
temp = 100*2 matrix;
}
I want to output the value of temp into 10 files with
each file containing the number of looping index (i.e,
file1.csv, file2.csv, ...) without
On Sat, 2005-10-01 at 08:59 -0700, James Anderson wrote:
Hi,
I am new to R. I have one question about outputing
files in a loop; Suppose I have the following loop:
for (i in 1:10) {
temp = 100*2 matrix;
}
I want to output the value of temp into 10 files with
each file containing
concerning question 1: -- labeling of outliers --
you can get the outliers by boxplot(...)$out
try:
set.seed(17)
x-rexp(99)
names(x)-paste(x,1:99)
out-boxplot(x)$out
text(rep(1.1,length(out)), out, names(out))
Peter Wolf
Stephen D. Weigand wrote:
Dear Yulei,
On Sep 26, 2005, at 6:56 PM,
Hi, there.
I have two questions about using R to create boxplots.
1. The function boxplot() plots the outliers. How can I label the exact
values arount these outlier points? Does R have an option allow me to
do that?
2. How can I put two boxplots in one x-y axis?
Thanks.
Yulei
Dear Yulei,
On Sep 26, 2005, at 6:56 PM, Yulei He wrote:
Hi, there.
I have two questions about using R to create boxplots.
1. The function boxplot() plots the outliers. How can I label the exact
values arount these outlier points? Does R have an option allow me to
do that?
You can use
Sep, 22nd,2005
Dear Authors,
Thanks for reading this email. I'm a graduate student from China (PRC) and
learning the R at present. Now I have some questions to ask you as I have met
some strange problems during installing and
Thank you for your detailed description. Please look at what:
capabilities()
jpeg pngtcltk X11 http/ftp sockets libxml fifo
TRUE TRUE TRUE TRUE TRUE TRUE TRUE TRUE
cledit IEEE754iconv
TRUE TRUE TRUE
says on your
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