Spencer == Spencer Graves [EMAIL PROTECTED]
on Wed, 17 Sep 2003 17:41:09 -0700 writes:
Spencer A subset of a data.frame is still a data.frame. A
Spencer data.frame is actually a list with additional
Spencer attributes. As far as I know, your solution,
Spencer as.matrix, is
When assigning a dataframe to a subset of a matrix I got a very odd
result. Am I missing something, or is this a bug? Details are below.
Also, if m is defined outside of the current function, is
m[...] - foo
necessary to update it, or does regular replacement
m[] - foo
work (that is, does
A subset of a data.frame is still a data.frame. A data.frame is
actually a list with additional attributes. As far as I know, your
solution, as.matrix, is an appropriate tool to convert a data.frame to
a matrix. Caution may be appropropriate, however, because if the
data.frame includes
