Robin Hankin wrote:
Hi
If
string - xyz
f - function(x){1 + sin(cos(x)) + exp(x^2)}
How do I manipulate string and f() to give the string
1 + sin(cos(xyz)) + exp(xyz^2)
?
Hi,
Here what i'll do :
f - function(x){
sprintf(1 + sin(cos(%s)) + exp(%s^2), x, x)
}
Cheers,
Romai
--
one approach could be the following
strng - gsub(x, xyz, deparse(body(f))[2])
sub('^[[:space:]]+', '', strng)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven,
Hi Dmitris
thanks for this but it's not quite right:
f - function(x){sin(x)+exp(x)}
strng - gsub(x, xyz, deparse(body(f))[2])
sub('^[[:space:]]+', '', strng)
[1] sin(xyz) + exyzp(xyz)
and I would want sin(xyz) + exp(xyz)
On 13 Sep 2006, at 08:45, Dimitris Rizopoulos wrote:
strng
Rizopoulos [EMAIL PROTECTED]
Cc: Robin Hankin [EMAIL PROTECTED]; [EMAIL PROTECTED]
Sent: Wednesday, September 13, 2006 9:54 AM
Subject: Re: [R] functions and strings
Hi Dmitris
thanks for this but it's not quite right:
f - function(x){sin(x)+exp(x)}
strng - gsub(x, xyz, deparse(body(f))[2
Hi Dmitris, Thierry,
I'm getting there but it's still not quite right if f() includes
something like x^2:
f - function(x){exp(x^2)}
gsub((x), (xyz), deparse(body(f))[2], fixed = TRUE)
[1] x^2
[I don't care about the spaces]
also,
I can't quite see how to implement Thierry's
Hello everyone
I know it looks like I'm making heavy weather of this, but
I don't think I communicated my problem properly. I really
appreciate you guys' help here.
I am writing a wrapper for a mathematical library to
which I want to send character strings that it can execute,
and then pass the
Hi,
Perhaps try this (based on 'bquote'):
rewrite.expression - function(expr, to, dep) {
f - function(expr) {
if ( length(expr) == 1 )
if ( expr == as.name(dep) )
as.name(to)
else
expr
else
as.call(lapply(expr, f))
}
f(expr)
}
rewrite -
Rich
that is swet
and does exactly what I want.
Thank you very much.
best wishes
rksh
On 13 Sep 2006, at 10:54, Rich FitzJohn wrote:
Hi,
Perhaps try this (based on 'bquote'):
rewrite.expression - function(expr, to, dep) {
f - function(expr) {
if ( length(expr) == 1
Robin Hankin [EMAIL PROTECTED] writes:
Rich
that is swet
and does exactly what I want.
Thank you very much.
I just wonder whatever substitute() did to get ignored like that?
substitute(1 + sin(cos(x)) + exp(x^2), list(x=quote(xyz)))
1 + sin(cos(xyz)) + exp(xyz^2)
