Thank you. I didn't know scale().
Qqline passes through 1st and 3rd quantiles, It doesn't seem very
useful to me. I thought a diagnol line will demonstrate the deviation
from a standard normal. Correct me if I was wrong. Thanks.
On Apr 3, 2005 2:40 AM, [EMAIL PROTECTED] [EMAIL PROTECTED]
Hi,
I am studying the behaviour of exchange rate for which i am using R-plus.
But the problem is that it says INPUT BUFFER OVERFLOW when i plug in
2500 data set point. Can anyone help me in this regards
Waiting for your replies
Warm Regards
RAhul Gupta
Gupta Rahul wrote:
Hi,
I am studying the behaviour of exchange rate for which i am using R-plus.
But the problem is that it says INPUT BUFFER OVERFLOW when i plug in
2500 data set point. Can anyone help me in this regards
PLEASE do read the posting guide!
Dear Bill,
You might want to check whether the parameterization of MNP differs from
the book you mention, which I don't have. In particular, I would check how
the choice specific covariate is calculated. More importantly, I would
also make sure that your chain has converged. Based on my
Thanks so much, Martin, Martyn, Marc and others for your insightful input on
French Curve.
From how the chemist is using the French Curve now, it seems he is using for
spline. Basically, he has two curves from spectrometry data. To find the
area underneath one curve without the noise area, he
Terry Mu wrote on 4/2/2005 9:38 PM:
like:
a %in% abcd
TRUE
Thanks.
See ?regexpr.
regexpr(a, abcd) 0
However, the first argument is not vectorized so you may also need
something like:
sapply(c(a, b, e), regexpr, c(abcd, bcde)) 0
ab e
[1,] TRUE TRUE FALSE
[2,] FALSE TRUE
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide! http://www.R-project.org/posting-guide.html
Hi All:
I would like to generate a binomial random variable that correlates with a
normal random variables with a specified correlation. Off course, the
correlation coefficient would not be same at each run because of randomness.
I greatly appreciate your input.
Ashraf
Hi All;
The following question is directed more to statisticians on the list.
Suppose I have a normal random variable. Is there a transformation that I
can apply so that the new variable is slightly positively skewed.
I greatly appreciate your help.
Ashraf
Remember this is just a diagnostic procedure and all you are really
looking for is whether the normal scores plot is pretty straight. The
reason for anchoring the guiding line at the quartiles is really the
same reason that boxplots use quartiles for the central chunk. You
don't want the guiding
Has anyone managed to get this working?
Here's what I did:
I got the binary build for R2.0.1 from the Omegahat
download page, and made a small change to
the registerClassID function ( to make it use
the right path to RDCOMServer.dll).
Then I tried to replicate the simple TTest example
from the
Ashraf Chaudhary wrote:
Hi All;
The following question is directed more to statisticians on the list.
Suppose I have a normal random variable. Is there a transformation that I
can apply so that the new variable is slightly positively skewed.
I greatly appreciate your help.
Ashraf
Hello sir:
Here's the result of repeated measures ANOVA.
$Error: Within
Df Sum Sq Mean Sq F valuePr(F)
t 2 524177 262089 258.24 1.514e-06 ***
Residuals 6 60891015
---
Signif. codes: 0 `***' 0.001 `**' 0.01 `*' 0.05 `.' 0.1 ` ' 1
My
Hello Tom,
Thanks for the reply.
Unfortunately I do have many NAs in my data as not all vertical
temperature profiles penetrated to the same depth level. In fact if I
simply use na.omit my data matrix is reduced from 4977 to 480
observations, so such a simple solution is not very helpful I'm
I think the box.cox function in package car can do this.
x - rnorm(1000)
hist(x)
library(car)
hist(box.cox(x, p=0.5))
Play around with different powers.
Best,
Matthias
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