Does this do what you want?
n-10
k-5
expand.grid(rep(list(1:n),k))
However be carful, even this small example prouces matrix with10 rows.
Best,
Ales Ziberna
- Original Message -
From: Globe Trotter [EMAIL PROTECTED]
To: [EMAIL PROTECTED]; r-help@stat.math.ethz.ch
Sent: Friday,
Re: [R] Survreg Weibull lambda and pYes, that is correct!
Best,
Ales Ziberna
- Original Message -
From: Stephen
To: Ales Ziberna ; r-help@stat.math.ethz.ch
Sent: Thursday, November 24, 2005 4:17 PM
Subject: RE: [R] Survreg Weibull lambda and p
Hi Ales,
Sorry Mis-read
Ales Ziberna [EMAIL PROTECTED] writes:
Does this do what you want?
n-10
k-5
expand.grid(rep(list(1:n),k))
However be carful, even this small example prouces matrix with10 rows.
I'm not sure this is what was wanted, since it is generating the same
samples multiple times. Consider
m -
I am a Macintosh computer (MAC OS X Version 10.4.3) user. I would like to
run R for structural equation modeling and meta-analysis but am having
difficulty using the Rcmdr interface.
According to the R commander installation notes for Tiger Macs I need to
1) Install X11.app from Apple Install
Hi,
I have problems compiling R 2.2.0 under AIX 4.3 with GCC and xlf95 (FORTRAN)
Compilers.
here the error message I got:
make[1]: Entering directory `/home/mau/sy/R-2.2.0/src/modules/X11'
make[1]: `Makedeps' is up to date.
make[1]: Leaving directory `/home/mau/sy/R-2.2.0/src/modules/X11'
Dear list members,
how can multiple imputation realized for anova tables in R? Concretely,
how to combine
F-values and R^2, R^2_adjusted from multiple imputations in R?
Of course, the point estimates can be averaged, but how to get
standarderrors for F-values/R^2 etc. in R?
For linear models,
On 25-Nov-05 Marc Schwartz wrote:
On Thu, 2005-11-24 at 21:55 +, Ted Harding wrote:
I'm rather with Peter on this question! I've tried to infer what
you're really trying to do.
My a-priori plausible hypothesis was that you have
k-12
independent observations which have equal
Hellp!
I would like to generate all possible partitions of length n with k
clusters. It should be noted that the labels of the classes are irrelevant.
Thanks for any suggestions!
Best regards,
Ales Ziberna
__
R-help@stat.math.ethz.ch mailing
P Ehlers wrote:
Marc Schwartz wrote:
On Thu, 2005-11-24 at 21:55 +, Ted Harding wrote:
On 24-Nov-05 P Ehlers wrote:
Bianca Vieru- Dimulescu wrote:
Hello,
I'm trying to calculate a chi-squared test to see if my data are
different from the theoretical distribution or not:
Hi,
Is anyone has solved MR Xin Meng problem (see below) ?
We have the same analysis configuration : 10 groups (including control one)
with 2 mesures for each (ref at t0 and response at t1).
We expect to compare each group response with control response (group 1)
using a multiple comparison
I have an ordering and factor problem to which there must be a simple
solution! The version is R 2.0.1 (2004-11-15) on A Linux platform.
A data frame H is read in from a .csv file using read.csv with as.is=TRUE.
Another data frame HN is constructed from data and I want to compare two
columns
John,
at ?factor, you can see :
Be careful only to compare factors with the
same set of levels (in the same order). In particular,
'as.numeric' applied to a factor is meaningless, and may happen by
implicit coercion. To revert a factor 'f' to its original
numeric values,
have also a look at ?is.ordered, it may be more useful than my previous
mail.
florence.
On 11/25/05, John Logsdon [EMAIL PROTECTED] wrote:
I have an ordering and factor problem to which there must be a simple
solution! The version is R 2.0.1 (2004-11-15) on A Linux platform.
A data frame
Dear Ehlers, thanks for your message.
Following the example on stepAIC and Venebles Ripleys book, it seems that
update rearranges the terms. I didnt understand how to indicate the formula in
the function.
I have the initial model U ~ var1+var2+var3+var4 (family Gaussian). I want first
to
Thanks Ales,
Best wishes
Stephen.
From: Ales Ziberna [mailto:[EMAIL PROTECTED]
Sent: Fri 25/11/2005 10:05
To: Stephen; r-help@stat.math.ethz.ch
Subject: Re: [R] Survreg Weibull lambda and p
Yes, that is correct!
Best,
Ales Ziberna
- Original
Hi list,
I've been trying to install the LS2W package in R. It's originally a
S+plus package so things don't work out as planned. Has anyone
succesfully installed this package in R (2.2.0)?
Cheers,
Koen
__
R-help@stat.math.ethz.ch mailing list
Thanks to Florence but it needs a little modification. However as I have
now discovered the str() command, things are looking up.:))
I have a character matrix so I() just leaves it as characters whereas I
want the various columns to be integers or whatever they contain.
To take Florence's
Dear Maha,
I'm not a Mac user, so can't offer much help, since you appear to have
followed the Mac installation notes. (Rick: I'm copying this reply to you in
case you didn't see Maha's message on r-help.)
I'm writing primarily to make sure that you know that the Rcmdr doesn't
support either
another posibility would be to use something like:
v1 - c(1, 2, 3); v2 - c(a, b, c); v3 - c(1, 2, 3)
dat - data.frame(v1, v2, v3)
3
dat - lapply(dat, as.character)
dat - as.data.frame(lapply(dat, type.convert))
dat
sapply(dat, data.class)
I hope it helps.
Best,
Dimitris
Hello:
I am trying to use optim() to estimate the maximum likelihood of a
function a*x^b = y.
Unfortunately, I always get the error, that there is no default value for b.
Could you give me an example, on how to correctly optimize this function
with input data x-c(1,3,11,14).
Thanks a lot,
On Fri, 25 Nov 2005 [EMAIL PROTECTED] wrote:
Hi,
I have problems compiling R 2.2.0 under AIX 4.3 with GCC and xlf95 (FORTRAN)
Compilers.
Did you check out the R-admin manual? That suggests you need
SHLIB_LDFLAGS=-Wl,-G
which you do not seem to have. Note also the report there that you
Adrienne Gret-Regamey wrote:
Hello:
I am trying to use optim() to estimate the maximum likelihood of a
function a*x^b = y.
Unfortunately, I always get the error, that there is no default value for b.
Could you give me an example, on how to correctly optimize this function
with input
Dear R users,
I am trying to fit a GLMM using lmer to a dataset where the brood identity
(LNRREIR) is nested within mothers identity. The reason for this is that
each mother can have several nests within each year and also between years.
I am running the following script (actually I
Antonio,
Antonio Olinto wrote:
Dear Ehlers, thanks for your message.
Following the example on stepAIC and Venebles Ripley’s book, it seems that
update rearranges the terms. I didn’t understand how to indicate the formula
in
the function.
I have the initial model U ~
Urania,
I'm not very fond of putting additive residuals on the righthand side.
This practice tends to obscure the fact that we're fitting a conditional
mean function:
E(Y|x) = function(x; parameters)
We then need to assess the model fit and uncertainties of parameter
estimates. We may want to
Hi Maha,
Can you provide me with a bit more info? No need to copy the R Help
Mailing List for now.
Can you let me know:
1) When you start X11, does the X11 window popup (which I usually
close immediately)?
2) Can you load library(car) from the R console?
3) Does the Rcmdr window pops up?
4)
I have posed this question earlier, however it has probably not been clear
enough.
My problem is such. I would like to find all possible partitions of a set of
n objects into k groups. The ordering of the groups does not matter, only
which objects are together matters.
For example, there
Dear R people,
I am working on a solaris 9 workstation with very restrictive access
policy. It means I have still to use R 1.7.1 and gcc 2.95.
The problems is following: I have written a small function in c++ using
boost library and I want to dyn.load the resulting .so file into R.
Compilation
On Fri, 25 Nov 2005, Ott Toomet wrote:
Dear R people,
I am working on a solaris 9 workstation with very restrictive access
policy. It means I have still to use R 1.7.1 and gcc 2.95.
Headers that long ago were not AFAIR written for C++, so ensure you used
extern C {} when including them.
I am running R 2.2.0 in a Windows XP environment. During my previous r
session, I saved my workspace as 20051123b.Rdata. (On disk, it is ~1.25 gb.)
I have launched R. (I have the following in my application shortcut
--max-mem-size=4000M, and although it may not be necessary, I have also
Probably not very fast but the number of partitions of a number,
also known as the Bell number, grows pretty dramatically so you
won't be able to use it for large numbers even with an efficient
implementation (though you could use it for larger numbers than
the solution here). The main attribute
Dear all,
I am trying to draw a survival curve with probability of surviving as
the y-axis and days (0- 500 days )as the x-axis. however, i do not
want the days to be equally spaced on the x-axis as i am more
interested in looking at the behaviour of the curve in the first 50
days. I am reluctant
Let me try to summarize my view on this:
- I still it would make sense to have a *simple* peaks() function
in R which provides the same (or more) functionality as the
corresponding S-plus one.From
For a proper data analysis situation, I think one would have to
do something more
Hello all,
I have a data file table.txt which i have attached. I am trying to pass the
columns as arguments to a function totnorm where i am displaying a total
normalization plot. The function is given below:
Just some clarification. The answer I gave before is interpreted like this:
3 0 0 means the partition of 3 into 3+0+0, 2 1 0 means
the partition of 3 into 2+1+0 and 1 1 1 means the partition
of 3 into 1+1+1.
As pointed out to me privately you asked for only those partitions
that correspond to
Isn't Bell number different from the number of partitions, P_n, of a number,
n?
Bell number, B_n, is the number of subsets into which a set with n
elements can be divided. So, B_3 = 5, and B_4 = 15, whereas P_3 = 3, and
P_4 = 5. Bell numbers grow much more rapidly than the number of partitions.
Yes, I just checked on Wikipedia and its as you say.
On 11/25/05, Ravi Varadhan [EMAIL PROTECTED] wrote:
Isn't Bell number different from the number of partitions, P_n, of a number,
n?
Bell number, B_n, is the number of subsets into which a set with n
elements can be divided. So, B_3 = 5,
Vasu,
You have a lot of problems here.
1. How was your file generated? Excel? You have trailing tabs on
all but row 1 which is why your read.table call with sep=\t
gives you columns that don't seem to agree with what you expect.
See the argument row.names in ?read.table.
2. It's never a good
Your question is not quite clear. Do you mean write and read an R list
object to a file?
If so, one method is provided by
dget() and dput()
on 11/24/2005 12:16 PM Leaf Sun said the following:
I need to write and read a list in R. I did r.site.search, found there
is a package rmutil doing
Hi,
My name is José María Gómez, and I am pretty new in R. Thus, I apologize
deeply if my questions are extremmely naïve.I have checked several
available books and URL's, without finding any answer.
I'm trying to fit Generalized Linear Mixed Models via PQL. Below I provide
the structure of my
Dear Rs
I have two vectors A and B
where
A is
V1d
1 0.00010 1.123278
2 0.002186431 1.120448
3 0.004351214 1.106661
4 0.006515998 1.107713
5 0.008680781 1.107667
6 0.013010348 1.106353
7 0.019504698 1.104077
8 0.034658181 1.103202
9 0.051976447 1.103200
10
Using the zoo package you can merge the curves together
and use na.approx to fill in the blanks. Assuming that
the first column in each instance is the x variable:
library(zoo)
Az - zoo(A[,2], A[,1])
Bz - zoo(B[,2], B[,1])
Cz - na.approx(merge(Az, Bz))
plot(Cz[,1] - Cz[,2])
On 11/25/05,
Thanks for your replies, Jim and Gabor:
Jim:
The x-axis is going to be in log scale. Basically I am comparing two
algorithms. One is very quick and another one is slow. X axis denotes time
and y axis is a normalized solution quality.
I hope it is clear now if not then let me know
Gabor:
I am
In that case you will need to modify the last line to be:
plot(time(Cz), coredata(Cz[,1] - Cz[,2]), log = x, type = l)
On 11/25/05, Prasanna [EMAIL PROTECTED] wrote:
Thanks for your replies, Jim and Gabor:
Jim:
The x-axis is going to be in log scale. Basically I am comparing two
Gabor:
The zoo lib. works perfectly for my problem. Thanks
On 11/26/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
In that case you will need to modify the last line to be:
plot(time(Cz), coredata(Cz[,1] - Cz[,2]), log = x, type = l)
On 11/25/05, Prasanna [EMAIL PROTECTED] wrote:
Thanks
Hi, R-help,
let x-rnorm(1000),
now I want to get a sequence y,which is satisfied with as follow:
y[1]-x[2]-x[1]
y[2]-x[3]-x[2]
y[999]-x[1000]-x[999]
Is there a function in R could achieve this requirement directly?
Thank you in advance!
致
礼！
?diff
y - diff(x)
HTH,
--sundar
广星 wrote:
Hi, R-help,
let x-rnorm(1000),
now I want to get a sequence y,which is satisfied with as follow:
y[1]-x[2]-x[1]
y[2]-x[3]-x[2]
y[999]-x[1000]-x[999]
Is there a function in R could achieve this requirement directly?
Thank you in
Thank you very much.
I have tried as follow:
y-x[2:length[x]]-x[1:(length[x]-1)]
apparently, it is not better than the diff.
Thank you again.
=== 2005-11-26 12:19:32 您在来信中写道：===
?diff
y - diff(x)
HTH,
--sundar
广星 wrote:
Hi, R-help,
let x-rnorm(1000),
now I want to get a sequence
http://www.cuddyvalley.org/psychoR/code
now contains version 1.4 of ca.R
There are already many versions of CA and CCA in various R packages,
but this one has some unique features, so maybe it is useful.
The function ca() can do simple CA, but it also
allows for linear restrictions on the row
An informal assessment may be useful: PLOT THE DATA.
x y experiment
0.1 0.5 A
0.2 0.6 A
0.3 0.6 A
0.4 0.7 A
0.5 0.9 A
1 3 B
2 4 B
3 6.5 B
4 7.5 B
5 11 B
10 18 C
20 35 C
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