I am analysing some binary data with a mixed effects model using
glmmPQL.
I am aware that I cannot use the AIC values to help me find the minimum
adequate model so how do I perform likelihood ratio tests? I need to
fix on the minimum adequate model but I'm not sure of the proper way to
do
* I have both R and Biobase and also download kidpack_1.1.1.tar.gz.
After I unzip the gz file, I got the folders and files. Then i got
lost: how to install the package of kidpack(because there is no zipped file
after I uninstall kidpack_1.1.1.tar.gz)? If I choose install from local
zipped file,
Just a small remark on R coding style :
Sean == Sean Davis [EMAIL PROTECTED]
on Tue, 29 Nov 2005 08:34:39 -0500 writes:
Sean
Sean x - matrix(c(1,1,1,2,2,2,1,1,1,1,1,2),nr=2,byrow=TRUE)
Sean .
(a very helpful answer to Georg's question;
On Wed, 30 Nov 2005, Martin Maechler wrote:
Just a small remark on R coding style :
Sean == Sean Davis [EMAIL PROTECTED]
on Tue, 29 Nov 2005 08:34:39 -0500 writes:
Sean
Sean x - matrix(c(1,1,1,2,2,2,1,1,1,1,1,2),nr=2,byrow=TRUE)
Sean .
(a
Hello to All.
I'd want to use a one-way ANOVA. This means that I have only one factor, with,
lets say, 5 levels.
I made a dataframe, called DATA, with two Columns:
A, that is my response, and it is class numerical.
B, that defines the different levels of my factor, and it is class factor.
If I
Dear R users,
I successfully installed SciViews the other day. However, when I try to
run it now, the command/script window does not appear. Strange. Well,
actually I see a tendency to a script window (in the lower part of the
sciview window where it is suppose to be) during start up, but
I've tried loading the batch script via the command
source(C:\\Program Files\\R\\rw2011\\HO_Rscript.txt)
in interactive mode but I get an error.
Question 2: can someone point out the syntax flaw in trying
to upload this batch script text file?
try
source(C:/Program
Hi I was wondering if there is a permutation test available in R for linear
models with continuous dependent covariates. I want to do a test like the
one shown here.
bmi-rnorm(100,25)
x-c(rep(0,75),rep(1,25))
y-rnorm(100)+bmi^(1/2)+rnorm(100,2)*x+bmi*x
H0-lm(y~1+x+bmi)
H1-lm(y~1+x+bmi+x*bmi)
1. Did you try anova(f1)? The documentation for glmmPQL says it
produces an object of class lme, and anova.glm might not work properly
for it. Also, did you try summary(f1), as suggested in the example in
?glmmPQL?
2. Have you considered using lmer in the lme4 package?
I'm sorry if I wasn't clear
There are repeated measures for each level of my factor.
For instance, the dataframe could look like that:
A B
12.0 1
12.3 1
15 1
12.9 2
16.7 2
15.4 2
23.5 3
9.6 3
7.8 3
In order to fit a random effects, is right to apply:
lme(A~1,data=DATA,random=~1|B)?
On Wed, 30 Nov 2005 [EMAIL PROTECTED] wrote:
Hello to All.
I'd want to use a one-way ANOVA. This means that I have only one factor, with,
lets say, 5 levels.
I made a dataframe, called DATA, with two Columns:
A, that is my response, and it is class numerical.
There is no class 'numerical':
Giuseppe
GIven the information below it is difficult to provide help. But, you might use
the lmer() function in the Matrix package in a fashion such as
lmer(A ~ B +(1|ID), data)
where ID is a grouping variable. There are plently of papers on lme and lmer in
the R news as well as a book by
I'm trying to add 'gplots' from install.packages(gplots, lib =
/usr/lib/R/library, dependencies = TRUE) on a linux host, but R does
not seem to figure out there's a new package installed (yes, I've
restarted the R-session). I've tried the default, and different library
folders, without success.
df - data.frame( matrix( rnorm(1000), nc=10 ) )
colnames(df) - c(y, paste(x, 1:9, sep=))
ifit - glm( y ~ ., data=df ) # initial fit
a - stepAIC( ifit, keep=extractAIC )
a$keep
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[1,] 10.000 9. 8.
hi all
HOPE SOMEONE CAN HELP!
i 've been searching r and some of the archives in order to find out how
one can consistently estimate the degrees of freedom of the following
random variable:
Y = a*T(v)+b
a and b = constants
T(v) is a Students t distribution with v
On Wed, 30 Nov 2005, Kåre Edvardsen wrote:
I'm trying to add 'gplots' from install.packages(gplots, lib =
/usr/lib/R/library, dependencies = TRUE) on a linux host, but R does
not seem to figure out there's a new package installed (yes, I've
restarted the R-session). I've tried the default,
I posted this a week ago on r-devel but to no avail and hope this not
considered cross-posting:
===cut===
hi everybody,
which each release I hope that the section
weights: an optional numeric vector of (fixed) weights. When present,
library(kidpack)
Error in library(kidpack) : 'kidpack' is not a valid package -- installed
2.0.0?
On 11/30/05, August Berg [EMAIL PROTECTED] wrote:
* I have both R and Biobase and also download kidpack_1.1.1.tar.gz.
After I unzip the gz file, I got the folders and files. Then i got
lost:
Hello R-sters
Is there a way to force e.g. the y-axis of
a persp()-plot to show not equaly spaced labels but the ones
you can give in the y=-command?
I tried
persp(,y=c(0.1,0.5,0.7,1),...)
but the labels were 0.0:1 by 0.2
I'm looking forward to your help
Andy
--
Thanx!
KÃ¥re
On Wed, 2005-11-30 at 13:27 +0100, Roger Bivand wrote:
On Wed, 30 Nov 2005, KÃ¥re Edvardsen wrote:
I'm trying to add 'gplots' from install.packages(gplots, lib =
/usr/lib/R/library, dependencies = TRUE) on a linux host, but R does
not seem to figure out there's a new
August Berg wrote:
library(kidpack)
Error in library(kidpack) : 'kidpack' is not a valid package -- installed
2.0.0?
On 11/30/05, August Berg [EMAIL PROTECTED] wrote:
* I have both R and Biobase and also download kidpack_1.1.1.tar.gz.
After I unzip the gz file, I got the folders and
Prof Brian Ripley [EMAIL PROTECTED] writes:
My questions is:
which formula should I use if I want to use a random effects model?
I think I should use lme, but I don't know how.
aov() is the function for anova modelling. so you want
aov(A ~ B, data = DATA) # fixed effects
On Wed, 30 Nov 2005, Peter Dalgaard wrote:
Prof Brian Ripley [EMAIL PROTECTED] writes:
My questions is:
which formula should I use if I want to use a random effects model?
I think I should use lme, but I don't know how.
aov() is the function for anova modelling. so you want
aov(A ~ B,
On Tue, 29 Nov 2005, Claus Atzenbeck wrote:
How do you calculate post hoc multiple comparisons tests with R for
normal distributed samples with different variances?
In order to make it more visible, I have created an overview that shows
my decision about what test I use. It is available at
Thanks, Henrik.
Vasu.
On 11/29/05, Henrik Bengtsson [EMAIL PROTECTED] wrote:
Vasundhara Akkineni wrote:
I want to retrieve data row wise from a data frame. My data frame is as
below:
data-read.table(table.txt, header=TRUE)
how can i get row-wise data?
Examples:
data[1,]
On Wed, 30 Nov 2005, [EMAIL PROTECTED] wrote:
I'm sorry if I wasn't clear
There are repeated measures for each level of my factor.
For instance, the dataframe could look like that:
A B
12.0 1
12.3 1
15 1
12.9 2
16.7 2
15.4 2
23.5 3
9.6 3
7.8 3
In order to fit a random effects,
anders superanders [EMAIL PROTECTED] writes:
Hi I was wondering if there is a permutation test available in R for linear
models with continuous dependent covariates. I want to do a test like the
one shown here.
bmi-rnorm(100,25)
x-c(rep(0,75),rep(1,25))
___
Ah! I didn't notice this until now.
Yes, following Nocedal Wright (excellent book, that) I've defined a
quadratic penalty function to enforce an equality constraint, and added
it to the objective.
On Wed, 30 Nov 2005, Uwe Ligges wrote:
August Berg wrote:
library(kidpack)
Error in library(kidpack) : 'kidpack' is not a valid package -- installed
2.0.0?
On 11/30/05, August Berg [EMAIL PROTECTED] wrote:
* I have both R and Biobase and also download kidpack_1.1.1.tar.gz.
After I
What would be nice would be an R routine that automatically
implements this flowchart.
On 11/30/05, Claus Atzenbeck [EMAIL PROTECTED] wrote:
On Tue, 29 Nov 2005, Claus Atzenbeck wrote:
How do you calculate post hoc multiple comparisons tests with R for
normal distributed samples with
I am trying to write a function that will solve a simple system of
nonlinear equations for the parameters that describe the beta
distribution (a,b) given the mean and variance.
mean = a/(a+b)
variance = (a*b)/(((a+b)^2) * (a+b+1))
Any help as to where to start would be welcome.
--
Scott
On 11/30/05, Prof Brian Ripley [EMAIL PROTECTED] wrote:
On Wed, 30 Nov 2005, Martin Maechler wrote:
Just a small remark on R coding style :
Sean == Sean Davis [EMAIL PROTECTED]
on Tue, 29 Nov 2005 08:34:39 -0500 writes:
Sean
Sean x -
I am trying to mimic the SAS code below in R. The trick is that each
row in the dataset has variable t which controls how many times the
do-loop below will be iterated (that is, the model is fit to the
response, ifate, 0 to t-1 times for each row of data). Is it possible to
incorporate
Hi,
I am calculating coefficient of variance (CV) for my ELISA's data. For
normal values, I use the standard formula CV = SD/Mean * 100. Now, I
would like to calculate CV for log values. Can any one please
suggest me, how I can do this in R?
Thanks in Advance.
Regards,
Sharon
Apropos the question about permutation tests in multiple regression:
We do have perm.test in package ExactRankTests, but it does one- and
two-sample tests, as in t.test, wilcox.test, etc. There doesn't seem
to be an exact version of the permutation test for correlations, i.e.,
the one that could
On Wed, 30 Nov 2005, Gabor Grothendieck wrote:
What would be nice would be an R routine that automatically
implements this flowchart.
This overview is just for my personal usage. I am not a statistician,
but some others told me that there is a lot of experience behind
choosing the right test.
One could have a method= argument with
the default chosen by using the flowchart and the output including
information on which method was used. A good help page
and/or vignette (that included the flowchart) could help ameliorate
difficulties. That would still allow the user to specify a
Gabor Grothendieck [EMAIL PROTECTED] writes:
What would be nice would be an R routine that automatically
implements this flowchart.
I'd recommend learning about p.adjust and the multcomp package
*instead* of following the flowchart. (Ignoring heteroscedasticity
seems a bit silly too, given
I apologise for asking this question here but I am hoping that someone
can either give me direct guidance and/or point me to a better group for
this type of disucssion.
I have what I feel should be a fairly simple problem but which my
limited stats knowledge can't answer. I have two overlapping
Another possibility might be to have a CRAN Task View devoted
to tests. The whole area is quite confusing and it would be nice
to have a central point for guidance.
On 30 Nov 2005 16:55:13 +0100, Peter Dalgaard [EMAIL PROTECTED] wrote:
Gabor Grothendieck [EMAIL PROTECTED] writes:
What would
Scott Story [EMAIL PROTECTED] writes:
I am trying to write a function that will solve a simple system of
nonlinear equations for the parameters that describe the beta
distribution (a,b) given the mean and variance.
mean = a/(a+b)
variance = (a*b)/(((a+b)^2) * (a+b+1))
Any help as to
On 11/30/2005 10:14 AM, Scott Story wrote:
I am trying to write a function that will solve a simple system of
nonlinear equations for the parameters that describe the beta
distribution (a,b) given the mean and variance.
mean = a/(a+b)
variance = (a*b)/(((a+b)^2) * (a+b+1))
Any help
Hi everybody,
I have to solve a score function by using Newton-Raphson algorithm. Is there
such a fucntion in R? I have built this algoritm
newton-function(tgt,drva,th0,err) {
iter=0
repeat {iter = iter+1
th1=th0-tgt(th0)/drva(th0)
if (abs(th0-th1)err||abs(tgt(th1)).1e-10)
break
th0=th1}
th1
}
Hello everybody,
after consulting V.Ricci's paper (Rappresentazione analitica delle
distribuzioni statistiche con R / Analytical representation of statistical
distributions in R) i would like to ask you further advice and a
confirmation about ks.test.
My willing is to perform ks.test to
Go to http://mathomatic.orgserve.de/math/ and install mathomatic
(its free) or just connect to the online server and do this.
The C output, i.e the result of the two code c commands,
can be used verbatim in R.
Note that mathomatic does not support logs but for simply
problems like this its very
Sharon Anbu [EMAIL PROTECTED] writes:
Hi,
I am calculating coefficient of variance (CV) for my ELISA's data. For
normal values, I use the standard formula CV = SD/Mean * 100. Now, I
would like to calculate CV for log values. Can any one please
suggest me, how I can do this in R?
It
On Wed, 30 Nov 2005, Peter Dalgaard wrote:
Apropos the question about permutation tests in multiple regression:
We do have perm.test in package ExactRankTests, but it does one- and
just for the record: exactRankTests.
two-sample tests, as in t.test, wilcox.test, etc. There doesn't seem
to
Sorry I seemed to have messed up the copying and pasting.
Here it is again.
---
Go to http://mathomatic.orgserve.de/math/ and install mathomatic
(its free) or just connect to the online server and do this.
The C output, i.e the result of the two code c commands,
can be used verbatim in R.
Note
Berton,
Firstly, thanks for your comments.
To address the what you first said, plotting the 3690-element vector is what
is causing R to hang. Rather than lose everything I've entered by hand each
interactive run I've switched to using a batch script, which I can now load
and run at prompt.
Dear R helpers,
I'm using R2.2 under windows XP professional on a Dell double processor
workstation.
I have a large (29Mb) workspace that I'm trying to load both, by double
clicking and by direct load. The message I get is Bad restore file
magic number (file may be corrupted) I believe that
Many packages in Fedora Extras, including R, have been recompiled for
CentOS (a RHEL clone). You can find them here:
http://centos.karan.org/
They should be compatible with RHEL, but of course your mileage may
vary.
Martyn
On Tue, 2005-11-29 at 20:43 +, Prof Brian Ripley wrote:
You don't
Thanks to Gabor, Duncan, and Peter. I knew the answer had something to
do with solving for a and b in terms of mean and variance. I will build
a function using the equations you provided Duncan and will look into
using Mathomatic in the future Gabor. Appreciate the help. Peter, this
Hello,
With the new version 2.2.0, I get strange plots when using the
histogram-like option in plot(). For example, a plot of binomial
probabilities:
plot(0:10,dbinom(0:10,10,.1), type = h, lwd = 30)
gives me weird fat cirular bars, with mass out at values with low
probability. What is the
Dylan == Dylan Beaudette [EMAIL PROTECTED]
on Mon, 28 Nov 2005 13:56:27 -0800 writes:
Dylan Greetings,
Dylan I am trying to add an extra labled axis in position 3 (top x-axis),
with
Dylan numbers that do not match up with the existing axes.
Dylan Surely this must be
tom wright [EMAIL PROTECTED] writes:
I apologise for asking this question here but I am hoping that someone
can either give me direct guidance and/or point me to a better group for
this type of disucssion.
I have what I feel should be a fairly simple problem but which my
limited stats
Hi everybody,
I am using R 2.2.0 under OS X 10.3.9.
And I am working on the hclust function from the package STATS.
Inside I found a call to a Fortran program hclust.f that I was able to
find into the source distribution of R, but there is a also a call to a
Fortran program hcass2. This very
hi all,
I load a table with headers that enable me to acces it by the column names:
tab-read.table(blob/data.dat,h=T)
attach(tab)
everythings are OK, but i try to sort this table against one of his column like
this:
tab-tab[order(tab$IndexUI),];
It is still ok, the table is sorted, if i type
dlavecchia == dlavecchia [EMAIL PROTECTED]
on Wed, 30 Nov 2005 17:08:47 +0100 writes:
dlavecchia I have to solve a score function by using
dlavecchia Newton-Raphson algorithm. Is there such a
dlavecchia fucntion in R? I have built this algoritm
dlavecchia
RSiteSearch(solving nonlinear equations) just returned 42 hits for
me, many of them potentially relevant to your question. And there are
more capabilities than what I found listed in the first few responses,
including nlme in addition to optim, nls, etc. A more focused question
as
?par lend
Before plotting:
par(lend='square')
-- Bert Gunter
Genentech Non-Clinical Statistics
South San Francisco, CA
The business of the statistician is to catalyze the scientific learning
process. - George E. P. Box
-Original Message-
From: [EMAIL PROTECTED]
Look at ?par specifically at the 'lend' argument.
You probably want to do:
par(lend=1)
Before doing your plot.
--
Gregory L. Snow Ph.D.
Statistical Data Center, IHC
[EMAIL PROTECTED]
(801) 408-8111
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf
Can someone please explain why this wont plot. The cats example given
for the colAUC function will plot.
Many thanks again
tom
#
library(caTools)
a-rnorm(100)
b-rbinom(100,1,0.7)
colAUC(a,b,plotROC=TRUE)
colAUC(a,b,plotROC=TRUE)
Error in strwidth(legend, units = user,
If you examine the code for the function violating.runs in the qcc
package (try violating.runs) you can deconstruct it to find that the code
flags runs where there are .qcc.options$run.length or more points in a row on
one side of the center (process mean).
However, the classic
Thanks a lot! I wonder why that isn't the default
-Original Message-
From: Berton Gunter [mailto:[EMAIL PROTECTED]
Sent: Wednesday, November 30, 2005 1:14 PM
To: Owen, Jason; r-help@stat.math.ethz.ch
Subject: RE: [R] strange plots with type = h option
?par lend
Before
On 11/30/2005 12:00 PM, giovanna jona lasinio wrote:
Dear R helpers,
I'm using R2.2 under windows XP professional on a Dell double processor
workstation.
I have a large (29Mb) workspace that I'm trying to load both, by double
clicking and by direct load. The message I get is Bad restore file
On 11/30/2005 12:27 PM, David Ruau wrote:
Hi everybody,
I am using R 2.2.0 under OS X 10.3.9.
And I am working on the hclust function from the package STATS.
Inside I found a call to a Fortran program hclust.f that I was able to
find into the source distribution of R, but there is a also
Hi. Sorry to pester, but I didn't get a reply to this (perhaps owing
to Thanksgiving break). This seems to be a case where the R language
simply doesn't do what it says it does (i.e., allow addition or
subtraction of a difftime object and a date-time object).
Am I wrong? I am about to
What do you need a bunch of functions for? I'm not familiar with the
details of difftime objects, however an easy way out of here is to get
the time difference in seconds, which you can then add or subtract as
you please from date-times.
x-Sys.time(); y-Sys.time()+3600
diff -
I don't know what is wrong but you could use the numeric class
instead of the difftime class as a workaround:
x - Sys.time()
y - x + 3600
diffyx - as.numeric(y) - as.numeric(x)
identical(y - diffyx, x) # TRUE
On 11/23/05, Parlamis Franklin [EMAIL PROTECTED] wrote:
On the help page
I am trying to replace a spreadsheet model of a project justification
with an R script.
I can't seem to track down R functions to calculate Internal Rate of
Return and NPV? Am I missing something? NPV doesn't seem so difficult
to calculate (at least for a regular series) but I am struggling
I agree there are workarounds (although reduction to secs is not
necessarily graceful when you want to add, say, 1 month to a date,
or any other increment for which the total number of seconds is not
fixed--and is also complicated by the existence of leap seconds).
But upon inspection,
On 11/30/05, Parlamis Franklin [EMAIL PROTECTED] wrote:
I agree there are workarounds (although reduction to secs is not
necessarily graceful when you want to add, say, 1 month to a date,
You can do that without difftime via:
seq(x, len = 2, by = month)[2]
or any other increment for which
What if the distributions are not normal etc? You might want to try a
simulation to get an answer. Draw random samples from each
distribution (without assuming normality etc - one way to do this is
to get the quantiles, then draw a sample of quantiles, then draw a
value from each quantile), throw
Hello,
If we define IRR implicitly such that NPV(C, IRR) = 0, then we can just
write an IRR function that finds the zeros of the NPV function. Here are
two such functions:
NPV - function(C, r) {
sum(C / (1 + r) ^ (seq(along = C) - 1))
}
IRR - function(C) {
uniroot(NPV, c(0, 1), C =
If you use lmer from the lme4 package (actually it is in the Matrix
package but logically it is in the lme4 package) to fit a
Generalized Linear Mixed Model you have the option of using PQL, or
the Laplace approximation or Adaptive Gauss-Hermite Quadrature (AGQ).
The log-likelihood for any of
You can use uniroot:
npv - function(i, cf, tt = seq(along = cf)) sum(cf / (1-i)^tt)
npv0 - npv(0.1, 1:10)
npv0
f - function(i, cf, npv0) npv0 - npv(i, cf)
uniroot(f, c(0.01, .99), cf = 1:10, npv0 = npv0)
On 11/30/05, paul sorenson [EMAIL PROTECTED] wrote:
I am trying to replace a spreadsheet
On 11/30/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
You can use uniroot:
npv - function(i, cf, tt = seq(along = cf)) sum(cf / (1-i)^tt)
Sorry that should 1+i
npv0 - npv(0.1, 1:10)
npv0
f - function(i, cf, npv0) npv0 - npv(i, cf)
uniroot(f, c(0.01, .99), cf = 1:10, npv0 = npv0)
On
(re-formulate, re-send, without html)
for vector y = c(1,2,3,4,5), H = 0.66 manual
calculations
using the equations below give a =
c(1,1.66,2.55,3.51,4.50).
KalmanRun with these parameters gives res$states =
(1,1,1,1,1)!
for Kalman Filter Durbin/Koopman give at p67 eqs
4.13:
v =
Dear R People:
I wanted to use the package its this afternoon.
I'm using R Version 2.2.0 for Windows.
I was able to install the package, but ran into trouble at
the library command. Here is the output:
library(its)
Loading required package: Hmisc
Hmisc library by Frank E Harrell Jr
Type
I have another issue.i have a function which calculates the log2(col i
/col2) value, where i stands for columns 3,4,...etc.
data-read.table(table.txt, header=TRUE)
iratio-function(x){
for(n in 3:ncol(data)){
z-log2(data[x,n]/data[x,2])
}
}
Where x- the row number of the data frame(data).
i
Just one addition to this. I noticed that its not really true that
the output can be used in R verbatim since the C output uses
pow instead of ^; however, if one replaces the code c statement
with the statement list export then it is valid R. That is the input
to mathomatic should be:
mean =
I don't have STATA and your example is not sufficiently complete for
me to replicate anything. However, my approach to that kind of thing is
to try to find the absolute simplest possible example I can think and
work with that. I have on occasion programmed such simple examples in
Hi
I am running a structural equation model with R using the sem command; am
getting the following error:
Error in sem.default : The model has negative degrees of freedom = -4
My model is as follows:
s_model = specify.model()
x1-m1, b1,NA
x2-m1, b2,NA
x3-m2, b3,NA
x4-m2, b4,NA
x5-m2, b5,NA
Vasundhara Akkineni wrote:
I have another issue.i have a function which calculates the log2(col i
/col2) value, where i stands for columns 3,4,...etc.
data-read.table(table.txt, header=TRUE)
iratio-function(x){
for(n in 3:ncol(data)){
z-log2(data[x,n]/data[x,2])
}
}
Where x- the row
I'm trying to fit a generalized mixed effects model to a data set where
each subject has paired categorical responses y (so I'm trying to use a
binomial logit link). There are about 183 observations and one
explanatory factor x. I'm trying to fit something like:
(lmer(y~x+(1|subject)))
I also
Thanks, Peter and Henrik.
Vasu.
On 11/30/05, Henrik Bengtsson [EMAIL PROTECTED] wrote:
Vasundhara Akkineni wrote:
I have another issue.i have a function which calculates the log2(col i
/col2) value, where i stands for columns 3,4,...etc.
data-read.table(table.txt, header=TRUE)
Hey there
I have two vectors:
y- c(0.4, 0.0, 0.2, -0.2, -0.6, 0.2, 0.0, 0.0, 0.4, 0.4, 0.2)
In the vector y, I want to access (in the order given) all of the values in
between each of the specific values of given.
I understand subsetting with y[i], but how do I get to ssomewhere in
between
HI LIST
i am a new R user,i am trying to make a model,which will give me
output in probability,which will take predictors and predictand serie as input
and and give me output in terms of probability(e.g below normal,normal,above
normal etc.).What is the package and what is the
On Wed, 30 Nov 2005, Erin Hodgess wrote:
Dear R People:
I wanted to use the package its this afternoon.
I'm using R Version 2.2.0 for Windows.
I was able to install the package, but ran into trouble at
the library command. Here is the output:
library(its)
Loading required package:
On Wed, 30 Nov 2005, Ed Wang wrote:
Berton,
Firstly, thanks for your comments.
To address the what you first said, plotting the 3690-element vector is what
is causing R to hang.
Well, amongst the things you are not telling us are your OS and version of
R and what commands you are using.
tom wright wrote:
Can someone please explain why this wont plot. The cats example given
for the colAUC function will plot.
Please report bugs in packages to the package maintainer rather than to
R-help.
Uwe Ligges
Many thanks again
tom
#
library(caTools)
[EMAIL PROTECTED] wrote:
hi all,
I load a table with headers that enable me to acces it by the column names:
tab-read.table(blob/data.dat,h=T)
attach(tab)
everythings are OK, but i try to sort this table against one of his column
like this:
tab-tab[order(tab$IndexUI),];
It is
anil kumar rohilla wrote:
HI LIST i am a new R user,i am trying to make a model,which will
give me output in probability,which will take predictors and
predictand serie as input and and give me output in terms of
probability(e.g below normal,normal,above normal etc.).What is the
package
Eric C. Jennings wrote:
Hey there
I have two vectors:
y- c(0.4, 0.0, 0.2, -0.2, -0.6, 0.2, 0.0, 0.0, 0.4, 0.4, 0.2)
In the vector y, I want to access (in the order given) all of the values in
between each of the specific values of given.
I understand subsetting with y[i], but how
GEE models are very different from the subject-specific models fitted by
glmmPQL: see the comparison in MASS. You are testing quite different
hypotheses. You appear to be assuming that some things `appear not to
work' because they do not give the same results as a different test.
Suppose x
95 matches
Mail list logo
