On Sat, 3 Jun 2006, ivo welch wrote:
I wonder if this is an intentional feature or an oversight.
These are documented properties of the functions you are using.
in some column summaries or in ifelse operations, apparently I am losing
the date property of my vector.
a - c(198012, 198101,
There is a documented limit of 1000 bytes on R input lines. You are
probably hitting it. Try teaching your Python code generator to wrap
lines.
NB: input means input from the console or stdin, not to the parser. The
front-end is asked for a line of up to 1000 bytes. Some front-ends may
ivo welch [EMAIL PROTECTED] writes:
Dear R wizards: sorry to bug everyone twice in one day.
I would like to annotate my graph by putting text strings into
rectangle boxes with a little cartoon-like bubble with a lid pointing
to a specific location. I can draw some sort of bubble-with-lid
Dear list members,
First of all thank you for your helpful advices.
After your answeres to my firt mail I studied a lot (R-News n°5) and I
tried to perform my analysis:
First, to fit a GLM with a nested design I decided to use the function
lmer in package lme4
as suggested by Spencer Graves and
I am hoping for some advie regarding the following scenario.
I have data from 26 studies that I wanted to analyse using logistic
regression. Given the data was from studies and not individuals I was
unsure how I would perform this in R. When analysed in SPSS, weighting was
used so that each
Dear Bob,
If I follow this properly, this is just a binomial logistic regression,
where, for each of your 26 observations, you have a certain number of
successes (positive instances) and failures (negative ones).
Fitting a binomial logit model is easily accommodated by the glm()
function.
At 14:12 03.06.2006 +0200, Martin Maechler wrote:
Heinz == Heinz Tuechler [EMAIL PROTECTED]
on Tue, 23 May 2006 01:17:21 +0100 writes:
Heinz Dear All, after searching on CRAN I got the
Heinz impression that there is no standard way in R to
Heinz label values of a numerical
Comments below:
mod1-lmer(sp~cla+(1|cla:plotti), data=bacaro,
family=poisson(link=log))
summary(mod1) #sunto del modello
Generalized linear mixed model fit using PQL
Formula: sp ~ cla + (1 | cla:plotti)
Data: bacaro
Family: poisson(log link)
AIC BIC
maybe you could consider something like the following:
varlabs - function(x){
if (is.null(names(x))) NULL else x[!duplicated(x)]
}
varlabs- - function(x, value){
names(x) - names(value[x])
x
}
###
x - c(1, 2, 3, 3, 2, 3, 1)
x
varlabs(x)
varlabs(x) - c(apple=1, banana=2,
Hello,
if I plot a horizontal line, e.g.,
plot(c(1,2),c(1,1),xlim=c(0,3),lwd=2,type=l)
or
plot(c(1,2),c(1,1),xlim=c(0,3),lwd=4,type=l)
then the left end (1st example) or both ends (2nd example) of the lines
are not rectangular but slanted on the graphical display (screen).
That behavour
hi
I'm using the GDD package (in a 64bits fedora machine using R 2.3.0)
to save in a png file some plots and i noticed that changing the lwd
parameter does not change my line width
I tried the same script in a Windows based R ( 2.2.1 r36812), using no
GDD, and it worked.
Does anybody has a
Hello:
I am reading a paper at the moment where the author reports on a
significance test of Cronbach's Alpha. I did not know that it is
possible. Is it? If so, how?
Tom
++
| Tom Backer Johnsen, Psychometrics Unit, Faculty of
I think you want to change par()$lend
Type
par() enter
to see the defaults.
In your situation you might want to begin with something like
dev.off()
par(mar=c(4,6,4,5)+0.1, lend=2)
... then your plotting logic ...
Where the mar argument adjusts the margins. (You can omit this if you're
probably you want to look at the `lend' argument of ?par, e.g.,
op - par(lend = 2)
plot(c(1,2), c(1,1), xlim = c(0,3), lwd = 20, type = l)
par(op)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
How is what you are doing any different from factors?
x - factor(c(1, 2, 3, 3, 2, 3, 1), labels=c(apple, banana, other))
x
[1] apple banana other other banana other apple
Levels: apple banana other
as.numeric(x)
[1] 1 2 3 3 2 3 1
levels(x)[3] - birne
x
[1] apple banana birne birne
Hi all.
In 'write' documentation, one can read:
write(x, file = data,
ncolumns = if(is.character(x)) 1 else 5,
append = FALSE, sep = )
Now my question is: why the default value of 1column for character vectors
and the special value '5' for non character vectors?
Nice sunday to all,
Thanks a lot!
That was exactly what I was looking for.
By the way, I see that since R version 2.3.0 that can be specified
inline, i.e.,
plot(c(1,2), c(1,1), xlim=c(0,3), lwd=10, type=l, lend=2)
So no need for par()...
Dimitrios Rizopoulos wrote:
probably you want to look at the `lend'
Your question does not include a simple, self-contained example (as
requested in the posting guide! www.R-project.org/posting-guide.html).
Without that, I don't even know where to start. However, the model
appears to be overparameterized and NOT invertible. Have you made acf
and
Dear all,
I am trying to avoid the warnings produced by:
x - -2:2
log(x)
[1] NaN NaN -Inf 0.000 0.6931472
Warning message:
production de NaN in: log(x)
I thought that using ifelse would be a solution, but it is not the case:
ifelse(test = x 0, yes = NaN, no = log(x))
Quoting Renaud Lancelot [EMAIL PROTECTED]:
Dear all,
I am trying to avoid the warnings produced by:
x - -2:2
log(x)
[1] NaN NaN -Inf 0.000 0.6931472
Warning message:
production de NaN in: log(x)
I thought that using ifelse would be a solution, but it is not
Try:
log(ifelse(x 0, NaN, x))
or
suppressWarnings(ifelse(x 0, NaN, log(x)))
or
ifelse(x 0, NaN, log(pmax(0, x)))
On 6/4/06, Renaud Lancelot [EMAIL PROTECTED] wrote:
Dear all,
I am trying to avoid the warnings produced by:
x - -2:2
log(x)
[1] NaN NaN -Inf
I don't know, but if it were my question, I think I could find
out by making local copies of the functions involved and stepping
through the algorithm line by line using debug (see, e.g.,
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/68215.html;).
Have you read Pinheiro and
I haven't seen a reply to this, so I will offer a few comments. I'm
not sufficiently familiar with nlme to answer your question directly,
but I hope my comments might help.
First, have you studied Pinheiro and Bates (2000) Mixed-Effects
Models in S and S-Plus (Springer)?
Dear R people,
I am having a problem with modeling the following SAS code in R:
Class ID Gr Hemi Region Gender
Model Y = Gr Region Hemi Gender Gr*Hemi Gr*Region Hemi*Region
Gender*Region Gender*Hemi Gr*Hemi*Region Gender*Hemi*Region
Gr*Gender*Hemi*Region
Random Intercept Region Hemi /Subject =
Have you reviewed White Paper on timeDate / timeSeries
downloadable from www.rmetrics.org? I believe this should answer your
question. It is my understanding that fCalendar was designed to help
people coordinate trading times and dates between different financial
markets all around
I haven't seen a reply to this post, so I will offer a few comments.
I don't know off the top of my head how to do what you want, but I
believe it can be done.
Are you aware that the standard R distribution includes script files
containing nearly all the R commands
The dse2 package contains functions forecast and forecastCov.
Have you tried them?
There may be functions to estimate vector autoregressive models in
more than one package in R. If you'd like more help from this
listserve, I would encourage you to submit another post after
I can ask my question using and example from Chapter 1 of Pinheiro Bates.
# 1.4 An Analysis of Covariance Model
OrthoFem - Orthodont[ Orthodont$Sex == Female, ]
fm1OrthF -
+ lme( distance ~ age, data = OrthoFem, random = ~ 1 | Subject )
summary( fm1OrthF )
Linear mixed-effects model
Hello,
I am new at tcltk and would like to identify the default background
color for widgets. I have found things like systemBackground or
tk_setPalette, but am not able to get them to work in R. Is there a
name for this color such as lightgray, etc?
Thank you for your time.
Murray,
you'll find it in
VarCorr(fm1OrthF)
Cheers
Andrew
On Mon, Jun 05, 2006 at 04:29:48PM +1200, Murray Jorgensen wrote:
I can ask my question using and example from Chapter 1 of Pinheiro Bates.
# 1.4 An Analysis of Covariance Model
OrthoFem - Orthodont[ Orthodont$Sex ==
I'm having problems with functions starting with underscores
'_foo' - function(x) {1}
seems to work
but I can't assign an attribute to this function
attr('_foo', 'bar') - 'pow'
Any way of doing this? This is for a C++ - R wrapping system so I'd like to
keep the C++ names which start with
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