Dear R People:
Here is a function that someone asked for today.
This is getting the sample from different rows from a list.
Hope this helps!
Sincerely,
Erin
oe1
function(n) {
a1 - n%%3
n1 - seq(from=2,to=(n-1+a1),by=3)
n2 - c(1:n)[-n1]
if(a1 == 1)n2 -
Hello,
I would like to have an advise about how to extract objects from a list of
matrixs
I have fitted models (stored in an object called model) using a matrix
response and the same formula and data. I get back, from summary.lm, as many
sumarries as I have responses.
Thus I have extract the
I can reccommend ggobi.
http://www.ggobi.org/
Install the binary standalone, and the Rggobi package for R (both are from the above
site). Works fine for me on Windows 2000, R 1.7.1.
Cheers,
Simon.
Simon Blomberg, PhD
Depression Anxiety Consumer Research Unit
Centre for Mental Health
ZABALZA-MEZGHANI Isabelle wrote:
Hello,
I would like to have an advise about how to extract objects from a list of
matrixs
I have fitted models (stored in an object called model) using a matrix
response and the same formula and data. I get back, from summary.lm, as many
sumarries as I have
[EMAIL PROTECTED] wrote:
HI, my question is about the function tkgetSavefile not save any file, for
example the next script run OK but
not save the file who i like to save, how i cant to save and object R with
tkgetSaveFile, how i use the
function save(objet, file=foo.R) with tkgetSaveFile
I wrote a R package, and installed it. But I don't understand how R can find right
help content for object foo when calling help(foo). Who can give me underlying
details or any reference regarding help(foo)?
In fact, after installing my package pkg_foo and calling library(pkg_foo), I can
Dear colleagues,
May you point me out to the PLS module in R system?
I could not find it at all using PLS or partial as the search keywords.
Thank you.
Sokratis.
--
Sokratis ALIKHANIDI, Ph.D.
Department of Knowledge-based Information Engineering
Toyohashi
If I have understood what you mean, you can use the (surely non-optimal)
code:
#build a matrix
A-matrix(1:20,nrow=5)
A[2,4]-NA
A[,3]-rep(NA,nrow(A))
#count the missing value in each column
fi-apply(A,2,function(x)sum(is.na(x)))
#exclude column(s) having a number of NA equal to nrow(A). Of
antonio rodriguez wrote:
Hi All,
How do I can delete from a matrix (or array) only those columns which have
all their values set to NA?
Cheers
Antonio Rodriguez
---
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Ted,
If you are missing a shared library (libtk8.3.so) then you could
just find the appropriate rpm on the RedHat9 CDs, perhaps
tk-8.3.5-88.i386.rpm in /RedHat/RPMS on the second CD, and install
it with sudo rpm -i.
BUT, there are some known bugs in the Tcl/Tk that comes with
Redhat 9 (which
Hi!
tmpdata-subset(myd, TYPE==A)
levels(tmpdata$TYPE)
[1] A B C
I'd like to get only A as output...
rebuild the factor after subsetting:
tmpdata$TYPE - factor(tmp$TYPE)
If you want the levels of all factors in your data frame to be
adjusted you could also use:
tmpdata -
antonio rodriguez wrote:
Hi All,
How do I can delete from a matrix (or array) only those columns which have
all their values set to NA?
use 'apply' to sweep through columns using a little function that sees
if all values in a column are NA:
eg: x:
x
[,1] [,2] [,3] [,4]
Yiming Zhou wrote:
I wrote a R package, and installed it. But I don't understand how R can find right help content for object foo when calling help(foo). Who can give me underlying details or any reference regarding help(foo)?
In fact, after installing my package pkg_foo and calling
Hiya
I'd like to get only A as output...
two solutions:
1.-use unique()
unique(tempdata$TYPE)
to get your answer
2.-or call factor again to reduce the levels:
tmpd - subset(myd,clas==A)
levels(tmpd$clas)
[1] A B C
tmpd$clas - factor(tmpd$clas)
levels(tmpd$clas)
[1] A
regards,
Many, many thanks to everybody. It helped a lot
Cheers
Antonio
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Uwe Ligges wrote:
Yiming Zhou wrote:
I wrote a R package, and installed it. But I don't understand how R
can find right help content for object foo when calling help(foo).
Who can give me underlying details or any reference regarding
help(foo)?
In fact, after installing my package pkg_foo
Hello,
I've just fitted a model with multi-responses, and I get an object of class
lm mlm.
My problem is that as soon as I invoke the predict method for a dataframe
newdata, the methods runs and give me back prediction at the fitting
points but not for newdata.
Does someone has an explanation
From: ZABALZA-MEZGHANI Isabelle
Hello,
I've just fitted a model with multi-responses, and I get an
object of class lm mlm. My problem is that as soon as I
invoke the predict method for a dataframe newdata, the
methods runs and give me back prediction at the fitting
points but not
Hello everybody!
I´m working with a dataset from twelve fertilizer trials, where the
technical fertilizer product and application method, but not the
intensity of fertilization, is varied. (I´m using R1.7.1 and W2000.)
The call:
ejna1t4b.lme - lme( Yield ~ TrCode, data = ejna1t4,
+
For plotting 3D points, you might want to check the function 'cloud' in the
'lattice' package (some good examples in the help file), you can feed the 3
most important factors to the function and see a 3d rep of your data. A
perhaps, a better 3D representation comes from the function 'sm.density'
Hi,
a very basic question:
What ist the easiest way in R to concatenate two lists of vectors?
E.g, I have
x-list(c(1,2))
y-list(c(3,4))
and I want to receive
list(c(1,2),c(3,4))
thank you!
Axel
Fraunhofer Institut fuer
Arbeitswirtschaft und Organisation
c(x,y) will do it.
Hope this helps -Matt
-Original Message-
From: Axel Benz [mailto:[EMAIL PROTECTED]
Sent: Friday, September 19, 2003 8:57 AM
To: [EMAIL PROTECTED]
Subject: [R] newby problem - concatenate lists
Hi,
a very basic question:
What ist the easiest way in R to concatenate
Hi,
Thanks to Barry Rawlinson and Sundar Dorai-Raj the problem was solved.
The problem was that I was doing integer division when I should have
been doing float division followed by ceil or floor.
Sorry about that and many thanks to those who took the time to look at this.
Best,
Guy
Lists are just like vectors:
x-list(c(1,2))
y-list(c(3,4))
c(x,y)
[[1]]
[1] 1 2
[[2]]
[1] 3 4
HTH,
Andy
-Original Message-
From: Axel Benz [mailto:[EMAIL PROTECTED]
Sent: Friday, September 19, 2003 8:57 AM
To: [EMAIL PROTECTED]
Subject: [R] newby problem - concatenate lists
Axel Benz wrote:
Hi,
a very basic question:
What ist the easiest way in R to concatenate two lists of vectors?
E.g, I have
x-list(c(1,2))
y-list(c(3,4))
and I want to receive
list(c(1,2),c(3,4))
What about c(x, y) ???
Uwe Ligges
thank you!
Axel
Eryk -
Question 1: Square brackets work, just the same as for
vectors, and return a (smaller or larger) list object.
The new thing with lists, not available (or needed) with
vectors, is double square brackets, which return one list
element as itself, not enclosed in a list.
See
Hi,
does there exists a R-function computing Hall-Wellner-Confidence-Bands?
Thanks,
Ralf Strobl
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Where did you search? From www.r-project.org - search - R site
search, I just got 84 matches for pls and 63 for partial least
squares. A generalization of PLS is structural equations, for which
I got 53 matches. The third match for pls mentioned package
pls.pcr, which presumably is still
On Fri, 19 Sep 2003, Richard A. O'Keefe wrote:
I know about persp(), and a bunch of other things in R that give me
a 3d view of a 2d field (plots of a function of 2 arguments, in other
words). But I want to plot a bunch of 3D points and label them.
I would try {g,x}gobi.
-thomas
On Fri, 19 Sep 2003, Axel Benz wrote:
Hi,
a very basic question:
What ist the easiest way in R to concatenate two lists of vectors?
E.g, I have
x-list(c(1,2))
y-list(c(3,4))
and I want to receive
list(c(1,2),c(3,4))
c(x,y)
-thomas
__
On Fri, 19 Sep 2003, Wolski wrote:
The second problem i have are that i want to store parmeters to the plot.default
function in a list. eg.: pars-list(xlim=c(0,100),xlab=irrelevant ,
ylab=incredible important).
and call the plot.default function with this list as parameters.
I know that
Thank you Spencer,
but it seems not to work with strings :
myquery - c(select . very long string = gives syntax error
myquery - {c(select . very long string= gives syntax error
It seems that the closing is required in any case.
Thank you in any case,
Alessandro
HI, i'm trying to save a data frame with the next script:
x-c(1,2,3)#suposse here the data frame
a-tkgetSaveFile()
a-tkgetSaveFile()
save(x,file=as.character(a))
but i obtain the next warning message:
Warning messages:
1: the condition has length 1 and only the first element will be used in:
Ruben -
Why not simply save(x, file=new.file.name) ?
See help(save), help(files). The file name must be
quoted, and it must be passed as a named argument to save().
- tom blackwell - u michigan medical school - ann arbor -
On Fri, 19 Sep 2003 [EMAIL PROTECTED] wrote:
HI, i'm
The Criminological Research Institute of Lower Saxony (KFN) in Germany
(Hannover) seeks a quantitative methodologist (Psychologist/Sociologist)
to work in a research project on the developmental consequences of
incarceration of juvenile delinquents.
For more detailed information see:
On Fri, 19 Sep 2003 [EMAIL PROTECTED] wrote:
Thank you Spencer,
but it seems not to work with strings :
myquery - c(select . very long string = gives syntax error
myquery - {c(select . very long string = gives syntax error
I think you will have to rewrite this
On 19-Sep-03 James Wettenhall wrote:
BUT, there are some known bugs in the Tcl/Tk that comes with
Redhat 9 (which don't exist in previous Redhat distributions) :
https://bugzilla.redhat.com/bugzilla/show_bug.cgi?id=89098
https://bugzilla.redhat.com/bugzilla/show_bug.cgi?id=101678
Jason Skelton wrote:
Could anyone advise me on the easist way of upgrading R from 1.6.2 to
1.7.1 ? is there a script like the bioconductor update.packages ?
or do I have to download the tar file and build it again ?
apologies for the trivial questions from a biologist
The latter.
Uwe Ligges
Dear all
I want to find a distance between two points in three dimensional space and an
angle between two vectors from [0,0,0] to specified points. I searched archives
and found some solution using dist but I am not sure how to use it if I have
several sets of such points.
Here is some
It seems to me that the simplest approach is as follows. Say you have a
function as follows:
dosomething - function(x,y) 0.523*x^2 + 0.34*y
Then you just use apply as follows to get your result (assuming that the
first column of matrix m contains the x values and the second column
contains the y
Hi,
I need to find out if the exponential, weibull, and log-normal
distributions in the survreg package use the same
parameterizations as in the functions rexp, rweibull, and
rlnorm. I have looked at the R-help and Venables Ripley
(2002), and they have different functional forms for the
Oh, the question might have been more precisely formulated I guess...
update surely helps a lot in the practical work at the computer. But
that is not my problem. The problem is where and how to introduce the
variables in the command.
I´ve tried things like: random = ~ P.AL | Trial/Block
as
I've been programming in one directory and recently switched to another
directory. It appears that in doing so I've uncovered a problem. My
environment was saving something so that my code would work and now I don't
know how to fix it. I have the following bit of code:
for(i in 1:index){
Hi, all. I'd like to know if exists a manner to get the first index where
a condition is attained in a vector. For example,
There is a better solution than
first.index - table(subject[corretor==27])[1]
(give me the subject for the first time that corretor is 27)?
Thanks,
Have you considered which, as in the following:
a - rep(1:2, 2)
a
[1] 1 2 1 2
which(a==1)
[1] 1 3
which(a==1)[1]
[1] 1
hope this helps. spencer graves
Cezar Augusto de Freitas Anselmo wrote:
Hi, all. I'd like to know if exists a manner to get the first index where
a condition is attained
Spencer Graves [EMAIL PROTECTED] writes:
For m[1] - ... to work, m must already be defined. To fix this,
execute m - rep(NA, index) before your second for loop, and it
should work. hope this helps. spencer graves
If saveList is actually a list, it would be more effective to use
m =
On Fri, 2003-09-19 at 13:15, Cezar Augusto de Freitas Anselmo wrote:
Hi, all. I'd like to know if exists a manner to get the first index where
a condition is attained in a vector. For example,
There is a better solution than
first.index - table(subject[corretor==27])[1]
(give me the
It may be easier to use the match function which is defined to return
the index of the first match.
corretor - c(15, 23, 27, 34, 25, 27, 26)
match(27, corretor)
[1] 3
Marc Schwartz [EMAIL PROTECTED] writes:
On Fri, 2003-09-19 at 13:15, Cezar Augusto de Freitas Anselmo wrote:
Hi, all. I'd
On Fri, 2003-09-19 at 15:57, Douglas Bates wrote:
It may be easier to use the match function which is defined to return
the index of the first match.
corretor - c(15, 23, 27, 34, 25, 27, 26)
match(27, corretor)
[1] 3
True and presumably much faster as the size of the search vector and
Hola amig@:
Me llamo Verónica. Te escribo desde Madrid, España y formo parte de un equipo del
Movimiento Humanista.
Hoy son ya millones de personas las que experimentan cómo la sociedad en que vivimos
se deshumaniza día a día. El ser humano ha perdido todo valor, el mundo se mueve en
torno al
Hi R users,
I am trying to use the aggregate function with a survey design object and
survey functions, but get the following error. I think I am incorrectly using the
syntax somehow, and it may not be possible to access variables directly by
name in a survey-design object. Am I right? How do
The following paper may be of interest to some. The author is generous about
sharing a recently revised version.
A
HREF=http://papers.ssrn.com/sol3/papers.cfm?abstract_id=259648;http://papers.ssrn.com/sol3/papers.cfm?abstract_id=259648/A
[[alternative HTML version deleted]]
What do you get from the following:
is.element(income, objects())
spencer graves
[EMAIL PROTECTED] wrote:
Hi R users,
I am trying to use the aggregate function with a survey design object and
survey functions, but get the following error. I think I am incorrectly using the
syntax
In a message dated 9/19/03 7:46:07 PM Pacific Daylight Time,
[EMAIL PROTECTED] writes:
What do you get from the following:
is.element(income, objects())
spencer graves
is.element(income, objects())
[1] FALSE
The following may give further info about why I am getting this. Design
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