On Wed, 23 Jun 2004 [EMAIL PROTECTED] wrote:
Dear, R experts.
Does anybody have experience with 'optim' function?
Yes.
I have an error message as the following.
Error in optim(transcoefs, fn = hfdeviance, gr = hfdeviance.grad, method
= BFGS, :
initial value in vmmin is not finite
I
Hello all,
I upgraded from R 1.8.1 to 1.9.0 (Windows XP), and spotted an odd thing.
The last three letters in the Swedish alphabet are å, ä and ö. (In case they don't
show correctly: they are a with a ring, a with two dots, and o with two dots (HTML:
aring; auml; ouml;).
When I use these as
Thank you for the tips, it is also good to know that the packages are getting even
better.
I however solved it this way:
lset(col.whitebg())
x.data - rnorm(16,20,7);y.data - rnorm(16,.55,.25); z.data -
sample(1:4,16,replace=T)
xyplot(y.data~x.data|z.data,
This is a function of the OS set by your locale, and there is nothing we
can do about it. It is done by the C call isalpha in do_makenames in
src/main/character.c.
My Windows XP machine in Swedish does accept all three, using the
CRAN-compiled version of rw1091.exe, so something is up with
Sixten Borg [EMAIL PROTECTED] writes:
Hello all,
I upgraded from R 1.8.1 to 1.9.0 (Windows XP), and spotted an odd thing.
The last three letters in the Swedish alphabet are å, ä and ö. (In case they don't
show correctly: they are a with a ring, a with two dots, and o with two dots (HTML:
Sixten Borg [EMAIL PROTECTED] writes:
When I use these as variable names in a data.frame, odd things happen:
data.frame(a=1, å=2, ä=3, ö=4)
a å ä X.
1 1 2 3 4
I your variables only include numbers (or only characters), this works
XX - cbind(a=1, å=2, ä=3, ö=4, æ=5, ø=6)
XX
a å
Ingolfsson, Olafur wrote:
Sixten Borg [EMAIL PROTECTED] writes:
When I use these as variable names in a data.frame, odd things happen:
data.frame(a=1, å=2, ä=3, ö=4)
a å ä X.
1 1 2 3 4
I your variables only include numbers (or only characters), this works
XX - cbind(a=1, å=2, ä=3, ö=4,
On Thu, 24 Jun 2004, Ingolfsson, Olafur wrote:
Sixten Borg [EMAIL PROTECTED] writes:
When I use these as variable names in a data.frame, odd things happen:
data.frame(a=1, å=2, ä=3, ö=4)
a å ä X.
1 1 2 3 4
I your variables only include numbers (or only characters), this works
Summary:
The locale setting in the operating system seems to be involved in what confused me a
little bit.
Thank you all for your help, especially the suggested work-around data.frame(...,
check.names=F) which works very well.
A mystery still to be solved is why two versions of R, running on
Unung == Unung Istopo Hartanto [EMAIL PROTECTED]
on Thu, 24 Jun 2004 10:49:29 +0700 writes:
Unung Hi R Users, Sorry if its out of topic. I would like
Unung to ask you about twin peaks - normal
Unung distribution. How R can handle it, any example to
Unung explain it in R.
Dear List members,
I am trying to produce some trellis graphics and to save them in a
postscript file but I only get blank files. R behaviour is certainly
strange because I use a loop to generate the graphics (see code below).
When I change the loop variable myself the postscript graphics are
On Thu, 24 Jun 2004, Virgilio Gómez Rubio wrote:
I am trying to produce some trellis graphics and to save them in a
postscript file but I only get blank files. R behaviour is certainly
strange because I use a loop to generate the graphics (see code below).
When I change the loop variable
This is not what I would call a summary. A summary should:
1. State the original question.
2. Give a pre'cis of the responses.
Murray Jorgensen
Sixten Borg wrote:
Summary:
The locale setting in the operating system seems to be involved in what confused me a little bit.
Thank you all for
I've tried to download rw1090.exe 3 times and rw1081.exe once onto a Windows XP from
the UK mirrors (I've tried both of them). When the download is complete and I
double-click on the icon I get an error message telling me the set-up files are
corrupted and to obtain a new copy of the program. I
Fiona Sanderson wrote:
I've tried to download rw1090.exe 3 times and rw1081.exe once onto a Windows XP from the UK mirrors (I've tried both of them). When the download is complete and I double-click on the icon I get an error message telling me the set-up files are corrupted and to obtain a new
Hi,
i'm using Perl to control R under Windows via the Win32::OLE module and
R's (D)COM server. This works fine, if i send commands and/or simple
data structures to R. I am also able to get matrix-shaped return values
into my Perl program, like this
# snip
I was exploring the polynom library with students:
library(polynom)
x - polynomial()
z - (1+x)^100
f - as.function(z) # = Segmentation fault (with R-1.8.1 and R-1.9.0) !!!
Debugging at hand:
as.function.polynomial - function (x, ...)
{
p - x
horner - function(p) {
a -
Here is a minor update with support for empty arguments. They
are just thrown away eliminating the need to use a dummy name
for them.
list - structure(NA,class=result)
[-.result - function(x,...,value) {
args - as.list(match.call())
args - args[-c(1:2,length(args))]
length(value) -
I would like to create a tree model with at most one split point per variable
using tree, rpart or other routine. Its OK if a variable enters at more
than one node but if it does then all splits for that variable should be
at the same point. The idea is that I want to be able to summarize the
Have you made normal probability plots? Mixtures of a small
number of normal distributions will appear as a collection of straight
line segments with breakpoints related to the mixing percentages, slopes
of the lines proportional to the standard deviations, etc. I don't
understand the
Are your categorical variables factors or ordered factors? If
yes, lm and many other functions including, I believe, nlme, will
automatically create the required dummy variables using contrasts
specified by options()$contrasts. Consider the following:
options(contrasts)
$contrasts
On Thu, 24 Jun 2004 13:01:59 +0100 (BST), Fiona Sanderson
[EMAIL PROTECTED] wrote :
I've tried to download rw1090.exe 3 times and rw1081.exe once onto a Windows XP from
the UK mirrors (I've tried both of them). When the download is complete and I
double-click on the icon I get an error message
I have generated a 3D graph from data in R using the Xgobi package.
Does anybody know how to generate a postscript file of the Xgobi
graph?? I have searched everywhere and I can not find it.
Thanks in advance
Hector
Héctor L. Ayala-del-Río, Ph.D.
Center for Microbial Ecology
Center for
Posting summaries is customary (or used to be) on S-news, where it was
customary to reply to the poster, and not always the whole list. (Whereas
on R it is requested that replies be posted to the entire list, which makes
summaries less necessary.)
However, a good summary can be a very useful
XGobi menu - file - print
Christian
On Thu, 24 Jun 2004, Hector L. Ayala-del-Rio wrote:
I have generated a 3D graph from data in R using the Xgobi package.
Does anybody know how to generate a postscript file of the Xgobi
graph?? I have searched everywhere and I can not find it.
Thanks
Is there any way to rotate a plot generated by the wireframe function (lattice)?
Thank you,
Fabian Garavito
__
[EMAIL PROTECTED] mailing list
https://www.stat.math.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
Have you considered the screen argument to wireframe, as
described in the documentation, including one of the examples?
hope this helps. spencer graves
Garavito,F (pgr) wrote:
Is there any way to rotate a plot generated by the wireframe function (lattice)?
Thank you,
Fabian
For this sort of thing the package rgl is the way to go...
url:www.econ.uiuc.edu/~rogerRoger Koenker
email [EMAIL PROTECTED] Department of Economics
vox:217-333-4558University of Illinois
fax:217-244-6678
Try
print(bwplot(...YOUR PARAMETERS...))
Best wishes,
Karl
Dear List members,
I am trying to produce some trellis graphics and to
save them in a
postscript file but I only get blank files. R
behaviour is certainly
strange because I use a loop to generate the
graphics (see code
Does anybody knows about a R implementation of the neighbor joining algorithm
? I made a Google search without success. Perhaps somebody already cooked
something ?
Thanks in advance
Michel Baylac
Muséum National d'Histoire Naturelle
Systematic and Evolution Dpt
CNRS UMR 2695
Rather than using system() to execute a shell command,
is there a way to emulate the system shell itself in R?
For instance, if the function is shell,
getwd()
[1] /home/a/b
shell() # From R to system shell
$cd .. # cd command in system shell
$CTRL+D# Return to R
I have fitted an arima(0,0,2) model to my data, and am trying to plot a
forecast for the next 15 time steps, but each time i try I am given the
following error message:
Error in .cbind.ts(list(...), makeNames(...), dframe = dframe, union =
TRUE) :
non-time series not of the correct length
On Thu, 24 Jun 2004, Shin, Daehyok wrote:
Rather than using system() to execute a shell command,
is there a way to emulate the system shell itself in R?
For instance, if the function is shell,
getwd()
[1] /home/a/b
shell() # From R to system shell
$cd .. # cd
Paul Roebuck wrote:
I have the following contrived code in package format.
On Solaris and Mac OS X, code runs just fine. On Windows,
it crashes the R environment with the Send Bug Report
dialog. I tried R 1.8.1 (Win2K) and R 1.9 (WinXP) binaries
with the same result. PCs otherwise appear properly
Is it difficult in R to create a function calling system() with user's
inputs iteratively?
Daehyok Shin (Peter)
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Prof Brian Ripley
Sent: Thursday, June 24, 2004 PM 2:28
To: Shin, Daehyok
Cc: R, Help
Hi,
1.) The median function does not work well. Please refer to the data
below (same data is attached as txt-delimited). This is what I try to
do in R:
median ( dataf [2:9] )
I get warning: needs numeric data
2.) BUT if apply the median to a single vector:
median ( dataf
Hi:
Is there a command in R (similar to hblm I guess) that would
allow me to fit a clustered version of the hierarchichal
bayes model,
Y_ij = X_ij\beta + \delta_i + \epsilon_ij
the \epsilon_ij have known variances,
\delta_i ~ N(0,\tau^2)
etc..
Thanks!
On Thu, 24 Jun 2004 13:23:22 -0700, Alexi Zubiria
[EMAIL PROTECTED] wrote :
Hi,
1.) The median function does not work well.
It works fine for me. You were trying to take the median of a list.
It only knows how to take the median of a vector.
Use dataf [,2:9] not dataf [2:9] to get a
Oops, missed something below:
On Thu, 24 Jun 2004 13:23:22 -0700, Alexi Zubiria
[EMAIL PROTECTED] wrote :
Hi,
1.) The median function does not work well.
It works fine for me. You were trying to take the median of a list.
It only knows how to take the median of a vector of numbers.
Use
Have you considered lme?
hope this helps. spencer graves
m i wrote:
Hi:
Is there a command in R (similar to hblm I guess) that would
allow me to fit a clustered version of the hierarchichal
bayes model,
Y_ij = X_ij\beta + \delta_i + \epsilon_ij
the \epsilon_ij have known variances,
Alexi Zubiria wrote:
Hi,
1.) The median function does not work well. Please refer to the data
below (same data is attached as txt-delimited). This is what I try to
do in R:
median ( dataf [2:9] )
I get warning: needs numeric data
2.) BUT if apply the median to a single vector:
Hi Laura!
in your last line, you have myforecast$pred instead of my.forecast$pred
Hope this helps!
If that's not it, try
str(my.list)
str(my.forecast$pred)
and check to see that they are both time series
Sincerely,
Erin Hodgess
Associate Professor
Department of Computer and Mathematical
Hi,
How can I get descriptive statitics (mean, se, etc) for a variable expressed in
percentage? (like summary() for a continous var) Can I tell R to do that?
Thank you
PP
__
[EMAIL PROTECTED] mailing list
On Thu, 24 Jun 2004, Shin, Daehyok wrote:
Is it difficult in R to create a function calling system() with user's
inputs iteratively?
See the example below!
Daehyok Shin (Peter)
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] Behalf Of Prof Brian Ripley
You wrote:
How can I get descriptive statitics (mean, se, etc) for a variable
expressed in percentage? (like summary() for a continous var) Can I
tell R to do that?
Percentages (and proportions) ***are*** continuous variates.
cheers,
This works:
model.matrix(~I(pos3),data=data.frame(pos=c(1:5)))
(Intercept) I(pos 3)TRUE
1 1 0
2 1 0
3 1 0
4 1 1
5 1 1
attr(,assign)
[1] 0 1
attr(,contrasts)
hi,
i was wondering if you can give me an example on how to import a data set
in csv format. i tried the manual's example, but have been getting an
error message:Error: syntax error.
sincerely,
jose sanchez
__
[EMAIL PROTECTED] mailing list
Hi,
Try read.csv()
i.e. take a look at ?read.csv
HTH
Kevin
- Original Message -
From: Jose Sanchez [EMAIL PROTECTED]
To: [EMAIL PROTECTED] [EMAIL PROTECTED]
Sent: Friday, June 25, 2004 10:38 AM
Subject: [R] help in importing data
hi,
i was wondering if you can give me an
Trevor Hastie [EMAIL PROTECTED] writes:
This does not:
model.matrix(~I(pos3),data=data.frame(pos=c(1:2)))
Error in contrasts-(`*tmp*`, value = contr.treatment) :
contrasts can be applied only to factors with 2 or more levels
Oh yes it does:
From: Peter Dalgaard
Trevor Hastie [EMAIL PROTECTED] writes:
This does not:
model.matrix(~I(pos3),data=data.frame(pos=c(1:2)))
Error in contrasts-(`*tmp*`, value = contr.treatment) :
contrasts can be applied only to factors with 2 or more levels
Oh yes it does:
Ditto here.
Trevor's problem is reproducible on R 1.8.1 (which is what he was using) on
both Linux RHEL 3.0 and Solaris and R 1.8.0 on Windows.
- Original Message -
From: Trevor Hastie [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, June 24, 2004 3:12 PM
Subject: [R] problem with
BN == Balasubramanian Narasimhan [EMAIL PROTECTED] writes:
BN Trevor's problem is reproducible on R 1.8.1 (which is what he
BN was using) on both Linux RHEL 3.0 and Solaris and R 1.8.0 on
BN Windows.
Yep, on my Linux box (details below) I have the same problem with R
1.8.1 but no
Hi there
I have a data frame with about 65,000 rows and 8 variables. I am trying to
get rid of the double entries of a factor variable ID so I can get a
unique observation for each ID
I tried:
dupl_unique.data.frame(data[ID,]) #I obtain a data frame with 21,547
observations..so far so good,
From: F Z
Hi there
I have a data frame with about 65,000 rows and 8 variables.
I am trying to
get rid of the double entries of a factor variable ID so I
can get a
unique observation for each ID
I tried:
dupl_unique.data.frame(data[ID,]) #I obtain a data frame with 21,547
data[!duplicated(data$ID),]
will do. Your unique(data[ID,]) removes duplicated rows in data[ID,],
assuming the object ID exists.
Alec Stephenson
Department of Statistics
Macquarie University
NSW 2109, Australia
F Z [EMAIL PROTECTED] 06/25/04
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