Hello everyone!
A simple question (I'm not sure about the answer):
How can I give a name to my data.frame from a character vector of names?
For example, each data.frame is a table of results for a subject and I have a
vector of subject names like
b - c(math, geography, history)
How do I
look at ?assign, e.g.,
b - c(math, geography, history)
assign(b[1], data.frame(x=rnorm(5), y=rnorm(5)))
math
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven,
Hello R-Help,
is there any way of using the RODBC Package on a Mac OS X
System? If yes, what do I need to get it running. Concerning these
issues, I am pretty unexperienced, so please state any step
necessary. The actual problem is accessing data in Excel- files.
(unfortunately no alternative
Cara Gormally cgormally at plantbio.uga.edu writes:
I'm having no luck figuring out how to find Bonferroni simultaneous
confidence intervals to obtain a
family of estimates in R.
Try package multcomp (no Bonferroni, but more powerful alternatives) or
multtest on Bioconductor
Dear List Members,
I need some help about programming in S language. My
problem is as follows:
I have meteorological data (about rainfall measurement
each day from 1989-2002), say like
http://www.angelfire.com/ab5/get5/data.rainfall.txt
or http://www.angelfire.com/ab5/get5/R.rainfall.txt
in a
On 11-Mar-05 Martin C. Martin wrote:
hist is lumping things together.
Try:
sum(temp == 0)
compare to the height of the left most bar.
Is this a bug in hist?
- Martin
Well, not a bug strictly speaking since it works as documented,
but I do think it's not necessarily a happy choice.
Mohammad,
?rle
is your friend, I guess.
Detlef
On Fri, 11 Mar 2005 03:07:56 -0800 (PST)
Mohammad Ehsanul Karim [EMAIL PROTECTED] wrote:
Dear List Members,
I need some help about programming in S language. My
problem is as follows:
I have meteorological data (about rainfall measurement
On 11-Mar-05 Mohammad Ehsanul Karim wrote:
Dear List Members,
I need some help about programming in S language. My
problem is as follows:
I have meteorological data (about rainfall measurement
each day from 1989-2002), say like
http://www.angelfire.com/ab5/get5/data.rainfall.txt
or
hi
thanx for the help. i dont want to use matrices. i solve my problem, see
the example below.
the set.seed is used because in my actual application i need to generate
INDEPENDENT variables. will this ensure that the variables are
independent?
z3-function(w)
{
for (i in 1:w)
{
ss-0
Dear Cara,
You could use the confint() function, setting the level argument to 1 -
alpha/length(coefficients(model)), where model is the linear model that
you've fit and alpha is the complement of the level of confidence. If you're
interested only in a subset of say p coefficients, then use 1 -
Trevor Wiens wrote:
On Thu, 10 Mar 2005 16:19:41 -0600
Frank E Harrell Jr [EMAIL PROTECTED] wrote:
The goodness of fit test only works on prespecified models. It is not
valid when stepwise variable selection is used (unless perhaps you use
alpha=0.5).
Perhaps I'm blind, but I can't find any
On Fri, 11 Mar 2005, Stephan Freyberger wrote:
Hello R-Help,
is there any way of using the RODBC Package on a Mac OS X
System? If yes, what do I need to get it running. Concerning these
issues, I am pretty unexperienced, so please state any step
necessary. The actual problem is accessing data in
hi all
i would like to generate independent vectors. i have included the code
below. i display the correlation matrix of the n*p (n=the number of
samples, p= the number of variables) matrix.
what i find is that as n increases, the correlation matrix tends to an
identity matrix. i.e.
You might try mvrnorm() in MASS.
library(MASS)
mvrnorm(n=10, mu=rep(0, 3), Sigma=diag(3), empirical=TRUE)
Clark Allan wrote:
hi all
i would like to generate independent vectors. i have included the code
below. i display the correlation matrix of the n*p (n=the number of
samples, p= the number of
thanx. this function works and does exactly what i want
Chuck Cleland wrote:
You might try mvrnorm() in MASS.
library(MASS)
mvrnorm(n=10, mu=rep(0, 3), Sigma=diag(3), empirical=TRUE)
Clark Allan wrote:
hi all
i would like to generate independent vectors. i have included the code
Hi
I have a dataset (.txt file and .dat file) in which the length of one
record is 144. There is no header in the .txt or .dat file itself. When I
read this file using the read.table command, and want to drop some
coloumns by setting the argument colClasses to NULL for the columns that
I want to
mgcv version 1.2 is on CRAN now. mgcv provides generalized additive models
and generalized additive mixed models with automatic estimation of the
smoothness of model components.
Changes in this version are:
* A new gam fitting method is implemented for the generalized case. It
provides more
bogdan romocea br44114 at yahoo.com writes:
:
: Dear useRs,
:
: I have a simple/RTFM question about XML parsing. Given an XML file,
: such as (fragment)
: A100/A
: B23/B
: Ctrue/C
: how do I import it in a data frame or list, so that the values (100,
: 23, true) can be accessed through the
Gabor Grothendieck wrote:
You could check out the ctv package that was recently announced.
It uses XML so its source would provide an example.
If its a one-time operation, Excel reads XML and you could then
use one of the many Excel to R possibilities.
For an xml file like this:
?xml version=1.0?
Hi
I have a data.frame with say 10 continuous variables and one grouping
factor (say 3 levels)
how can I easily (without loops) apply for each continous variable e.g.
an aov, with the grouping factor as my factor (or if the grouping factor
has 2 levels, eg. a t-test)
thanks for a hint
cheers
On Fri, 11 Mar 2005, Upasna Sharma wrote:
Hi
I have a dataset (.txt file and .dat file) in which the length of one
record is 144. There is no header in the .txt or .dat file itself. When I
read this file using the read.table command, and want to drop some
coloumns by setting the argument
On Fri, 11 Mar 2005, Christoph Lehmann wrote:
Hi
I have a data.frame with say 10 continuous variables and one grouping factor
(say 3 levels)
how can I easily (without loops) apply for each continous variable e.g. an
aov, with the grouping factor as my factor (or if the grouping factor has 2
you mean something like this:
dat - data.frame(matrix(rnorm(10*100), 100), f=sample(letters[1:3],
100, TRUE))
models - lapply(dat[sapply(dat, is.numeric)], function(x, f)
aov(x~f), f=dat$f)
#
models
lapply(models, summary)
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
On Fri, 11 Mar 2005 07:32:30 -0500
Frank E Harrell Jr [EMAIL PROTECTED] wrote:
What I mean is the effective significance level for keeping a variable
in the model. Using AIC for one degree of freedom variables is
effectively using an alpha of 0.16 if I recall properly.
But I hope you got
Christoph Lehmann [EMAIL PROTECTED] writes:
Hi
I have a data.frame with say 10 continuous variables and one grouping
factor (say 3 levels)
how can I easily (without loops) apply for each continous variable
e.g. an aov, with the grouping factor as my factor (or if the grouping
factor has 2
Check out www.xlsolutions-corp.com, they are offering
a course in San Francisco March 31st - April 1st.
--- paul king [EMAIL PROTECTED] wrote:
Hi all,
I am taking a new job in San Francisco and looking
for an upcoming
advanced R/S+ programming course in bay area.
Best - Paul
In trying to use simplex() from the boot package, I have run into a
situation that doesn't seem like it should be possible. It is claiming
that it has solved the LP, but returns a vector of all zeros, which
does not satisfy the constraints I passed in. A small example:
ubMatrix -
hi
I'm student in master, for my work I use R software, I make a grphic, I will,
for each point on graphic the corresponding date of consulting. The number of
consultations is variable for the patients ( min=6, max= 44)
thank's
-
mails !
Dear list,
I've had difficulty saving my workspace to an .RData file.
This causes considerable frustration as it means that I have to regenerate
my analysis every time I want to update it. For microarray data in
particular, this can be quite time consuming.
I'm saving my data to a network
many thanks for the sapply hint. How can I use sapply for a compact
result of the aov computation, say I call
sapply(dd[-1], function(y, f) aov(y ~ f), f = dd$V1)
aov gives the result in another form than t.test
thanks a lot
Peter Dalgaard wrote:
Christoph Lehmann [EMAIL PROTECTED] writes:
Hi
I
Dear all;
Searching the R site for answers to my problem, but found none.
Here is the run and error:
bwplot(dev ~ Dbhcl | Period, data = DbhValid2, font = 2,
+ main=list( ), axis.font =2,
+ ylab = list(label = Residual (cm), font = 2),
+ xlab = list(label = Dbh class (cm), font =
Hi can someone help me with the following warning message I got when I used two
way anova: Warning messages: 1: Models with response NULL removed because
response differs from model 1 in: anova.lmlist(object, ...) 2: Models with
response NULL removed because response differs from model 1 in:
On Friday 11 March 2005 11:47, Yang, Richard wrote:
Dear all;
Searching the R site for answers to my problem, but found none.
If this is what I'm guessing it is, you haven't searched carefully enough.
This was a bug (in lattice) that was reported several times, but has been
fixed long ago.
Thank, Deepayan Sarkar and Sundar Dorai-Raj for their quick responses. After
updating lattice, the problem resolved.
Richard
-Original Message-
Subject: [R] Lattice bwplot error
Dear all;
Searching the R site for answers to my problem, but found none.
Here is the run and
Dear list,
I would like to know:
1. After I have used the R code (http://pscl.stanford.edu/zeroinfl.r) to fit a
zero-inflated negative binomial model, what criteria I should follow to compare
and select the best model (models with different predictors)?
2. How can I compare the model I get
John Fox described one version of the standard Bonferroni
correction. I just got 51 hits from www.r-project.org - Search - R
Site Search - Bonferroni; you may wish to review them. More
generally, a Google search for Bonferroni produced about 347,000
hits, the fifth of which was the
I'm not certain what you want, but will the following help you:
plot(1:4, type=n)
text(1:4, letters[1:4])
If this does NOT solve your problem, please tell us why it is
deficient. If you try something else that does not work, please
describe what you tried and why you didn't like
Dear R-users,
using the interactive mode, the command
summary(my.survreg.object)
will output details of the object my.survreg.object in a very neat
fashion.
I would like to have that sent to a file, in ascii format, as it
appears within the interactive mode.
Is that possible ?
This seems like
On Fri, 2005-03-11 at 22:49 -0500, Charles Dugas wrote:
Dear R-users,
using the interactive mode, the command
summary(my.survreg.object)
will output details of the object my.survreg.object in a very neat
fashion.
I would like to have that sent to a file, in ascii format, as it
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