G'day Stéphane,
SD == Stéphane Dray [EMAIL PROTECTED] writes:
SD I have found a problem (bug?) with Sweave. [...] The value
SD of 'a' has change between the two Schunks. It seems that the
SD problem only appear when there are plot (fig=T) in the first
SD one. Without plot,
What am I doing wrong? (please cc me when replying)
yy - 1:10
xx - yy*2
xYplot(yy~xx,ylab=) #this plots as it should
text(.4,5,expression(paste(log, frac(p(b),p(a)) )))
Error in text.default(0.4, 13, expression(paste(log, frac(p(b), p
(a) :
plot.new has not been called yet
This is
Spencer Graves wrote:
Thank you all for your replies and for all your hard work to make R
what it is. The wise course for me is probably to use R 2.1.1 when I
need the Matrix package until this issue gets fixed.
No, you can use R-2.2.0, but simply use the last working version of
It would be more interesting to ask why does this does not work.
mylist - list( value=5, plusplus = mylist$value + 1 )
I think this is because plusplus cannot be evaluated because mylist does
not exist and mylist cannot be created until plusplus is evaluated.
There are people on this list
You can do this:
L - list(value = 2)
L$plusplus - L$value + 1
or use the proto package which does support this sort of
manipulation:
library(proto)
as.list(proto(,{value = 2; plusplus = value+1}))
That creates a proto object with the indicated two components
and then converts it to
On 11/12/05, Michael Kubovy [EMAIL PROTECTED] wrote:
What am I doing wrong? (please cc me when replying)
yy - 1:10
xx - yy*2
xYplot(yy~xx,ylab=) #this plots as it should
text(.4,5,expression(paste(log, frac(p(b),p(a)) )))
Error in text.default(0.4, 13, expression(paste(log, frac(p(b), p
Dear R-helpers,
I apologize for this certainly simple question.
I have the following R lines :
m = matrix(1:12 , 3 , 4);
m
[,1] [,2] [,3] [,4]
[1,]147 10
[2,]258 11
[3,]369 12
m1 = subset(m , m[,2]=5);
m1
[1] 2 3 5 6 8 9 11 12
but
Do you mean simply m[m[,2]=5,] ?
Kristel
[EMAIL PROTECTED] wrote:
Dear R-helpers,
I apologize for this certainly simple question.
I have the following R lines :
m = matrix(1:12 , 3 , 4);
m
[,1] [,2] [,3] [,4]
[1,]147 10
[2,]258 11
[3,]3
On Sat, 2005-11-12 at 20:24 +0100, [EMAIL PROTECTED] wrote:
Dear R-helpers,
I apologize for this certainly simple question.
I have the following R lines :
m = matrix(1:12 , 3 , 4);
m
[,1] [,2] [,3] [,4]
[1,]147 10
[2,]258 11
[3,]369
Marc Schwartz a écrit :
What version of R are you using? You did not indicate this in your post
as you are asked to do in the posting guide.
I apologize for that, I use Version 2.0.1
In R version 2.1.0, a matrix method was added to the subset() function,
so I am guessing that you are
Kristel Joossens a écrit :
Do you mean simply m[m[,2]=5,] ?
yes. Arghh !!!
Thanks to all of you for your helpful answers.
Vincent
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide!
Dear R-helpers,
Suppose I have dataset like this below:
data(HairEyeColor)
dfHEC - as.data.frame(as.table(HairEyeColor))
my.dfHEC - data.frame(Hair=rep(dfHEC$Hair,dfHEC$Freq),
Eye=rep(dfHEC$Eye,dfHEC$Freq),
Sex=rep(dfHEC$Sex,dfHEC$Freq))
my.dfHEC
Looking at the results that you are expecing I think that you just want to
have only the record from black colored people. If that't the case, for
this dataset the easiest way is to subset the data i.e
data(HairEyeColor)
x=as.data.frame(HairEyeColor)
x2=x[x$Hair==Black,1:3]
x2
Hair Eye
Dear members of the list,
I'm fitting ordinal regressions using polr, and in some models I
get the error copied below. Dependent variable is an ordered factor
of bird abundance categories, and predictors are continuous habitat
variables.
ro6 - polr(formula = abun ~ InOmbrot + Oliva.OC +
Hello,
I have a table (1) of the form
q1 q3 q4 q8 q9
A 5 2 0 1 3
B 2 0 2 4 4
I have another table (2):
q1 q2 q3 q4 q5 q6 q7 q8 q9
C 10 7 4 2 6 9 3 1 2
I would like to divide the numbers in table (1) by the number of the
appropriate column in table
This will work if you are using matrices (if you have data frames, convert
them to matrix):
table1
q1 q3 q4 q8 q9
A 5 2 0 1 3
B 2 0 2 4 4
table2
q1 q2 q3 q4 q5 q6 q7 q8 q9
C 10 7 4 2 6 9 3 1 2
index - match(colnames(table2), colnames(table1), nomatch=0)
t(t(table1[,index]) / table2[index !=
jim holtman [EMAIL PROTECTED] writes:
This will work if you are using matrices (if you have data frames, convert
them to matrix):
table1
q1 q3 q4 q8 q9
A 5 2 0 1 3
B 2 0 2 4 4
table2
q1 q2 q3 q4 q5 q6 q7 q8 q9
C 10 7 4 2 6 9 3 1 2
index - match(colnames(table2), colnames(table1),
Is there any pure r code to do delaunay or voronoi diagrams?
Thanks!
-
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Any difference between - and =
to assign the values?
-
[[alternative HTML version deleted]]
__
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
- can be used in places where = but otherwise they are the same.
See ?-
On 11/13/05, Robert [EMAIL PROTECTED] wrote:
Any difference between - and =
to assign the values?
-
[[alternative HTML version deleted]]
Sorry, I meant to say - can be used in places where = can't. Seem
to have left out the word can't.
On 11/13/05, Gabor Grothendieck [EMAIL PROTECTED] wrote:
- can be used in places where = but otherwise they are the same.
See ?-
On 11/13/05, Robert [EMAIL PROTECTED] wrote:
Any difference
21 matches
Mail list logo
